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JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-73 of 73 questions

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61 Easy

61 of 73

Application +4 | -1

In Which of the following compounds the oxidation number of carbon is maximum:

View answer and explanation

Correct option: B

\mathrm{CHCl}_3

Option B (

\mathrm{CHCl}_3

) is correct because the oxidation number of carbon in this compound is +2, which is the highest among the given options.

62 Easy

62 of 73

Application +4 | -1

Oxidation number of oxygen in

{O_2}{F_2}

View answer and explanation

Correct option: C

+1

Option C (+1) is correct because fluorine is more electronegative than oxygen, assigning it a -1 oxidation state, leading to +1 for oxygen.

63 Easy

63 of 73

Analyzing +4 | -1

\mathrm{C} + {\mathrm{H}_2}\mathrm{O} \to \mathrm{CO} + {\mathrm{H}_2};{\mathrm{H}_2}\mathrm{O acts as}:

View answer and explanation

Correct option: A

Oxidant

Option A (Oxidant) is correct because in the reaction

\mathrm{C} + {\mathrm{H}_2}\mathrm{O} \to \mathrm{CO} + {\mathrm{H}_2}

, hydrogen in water gains electrons (reduction), so water acts as an oxidizing agent (oxidant).

64 Easy

64 of 73

Understanding +4 | -1

An element with electronic arrangement at 2, 8, 18, 1 will exhibit the following oxidation states

View answer and explanation

Correct option: B

Option A is correct because an element with the electronic configuration 2, 8, 18, 1 (Copper) can exhibit multiple oxidation states due to the involvement of d-electrons.

65 Easy

65 of 73

Application +4 | -1

In the reaction,

\mathrm{C}{\mathrm{H}_3}\mathrm{OH} \to \mathrm{HCOOH}

, the number of electrons that must be added to the right is:

View answer and explanation

Correct option: A

Option A (4) is correct because the oxidation state of carbon changes from -2 to +2, requiring 4 electrons to be added to the right side of the equation.

66 Easy

66 of 73

Remembering +4 | -1

A group of methods of quantitative chemical analysis involving the measurement of volume of reacting substance is known as :

View answer and explanation

Correct option: B

Volumetric analysis

Option B (Volumetric analysis) is correct because volumetric analysis involves measuring the volume of reacting substances to determine the quantity of an analyte.

67 Easy

67 of 73

Application +4 | -1

The oxidation number of sulphur in

\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7

and iron in

\mathrm{K}_4 \mathrm{Fe}(\mathrm{CN})_6

is respectively:

View answer and explanation

Correct option: A

+6

and

+2

Option A (+6 and +2) is correct because the oxidation number of sulfur in H2S2O7 is +6 and the oxidation number of iron in K4Fe(CN)6 is +2.

68 Easy

68 of 73

Analyzing +4 | -1

Which of the following is not a redox reaction?

View answer and explanation

Correct option: D

\mathrm{NaCl}+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{NaHSO}_4+\mathrm{HCl}

Option D is correct because the reaction

\mathrm{NaCl}+\mathrm{H}_2\mathrm{SO}_4 \rightarrow \mathrm{NaHSO}_4+\mathrm{HCl}

does not involve any change in the oxidation state of any element.

69 Easy

69 of 73

Understanding +4 | -1

The halogen that most easily reduced is

View answer and explanation

Correct option: A

{F_2}

Option A (

{F_2}

) is correct because fluorine is the most electronegative element, making it the strongest oxidizing agent and thus the most easily reduced halogen.

70 Easy

70 of 73

Application +4 | -1

The correct decreasing order of oxidation number of oxygen in compounds

Ba{O_2},{O_3},\,K{O_2}

and

O{F_2}

, is

View answer and explanation

Correct option: B

O{F_2} > {O_3} > K{O_2} > Ba{O_2}

Option B (

O{F_2} > {O_3} > K{O_2} > Ba{O_2}

) is correct because it represents the correct decreasing order of oxidation states of oxygen in the given compounds.

71 Easy

71 of 73

Analyzing +4 | -1

Assertion (A): The oxidation state of oxygen in

{F}_2 {O}

is +2.

Reason (R): Electronegativity of

F

is more than that of oxygen.

View answer and explanation

Correct option: A

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

Option A is correct because both the assertion and reason are true, and the reason correctly explains why oxygen has a +2 oxidation state in

{F}_2 {O}

72 Easy

72 of 73

Remembering +4 | -1

Which of the following is the most powerful oxidizing agent?

View answer and explanation

Correct option: A

\mathrm{F}_2

Option A (

\mathrm{F}_2

) is correct because fluorine (

F_2

) has the highest standard reduction potential (

E^{\circ}=+2.5 \mathrm{~V}

), making it the strongest oxidizing agent.

73 Easy

73 of 73

Analyzing +4 | -1

Among the following, the number of elements showing only one non-zero oxidation state is

\mathrm{O},\mathrm{\;Cl},\mathrm{\;F},\mathrm{\;N},\mathrm{\;P},\mathrm{\;Sn},\mathrm{\;Tl},\mathrm{\;Na},\mathrm{\;Ti}

View answer and explanation

Correct option: B

Option B (2) is correct because only F and Na exhibit only one non-zero oxidation state.

Revision notes and key takeaways

Review REDOX REACTIONS in your textbook or class notes, then use this set to check your understanding.

Showing 61-73 of 73 questions

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