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JEE • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 98 questions

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61 Hard
61 of 98
Remembering +4 | -1
The principal reason that solid sodium hydroxide is not used as a primary standard for acid-base titrations is that it
View answer and explanation
Correct option: A
Absorbs water from air
Option A (Absorbs water from air) is correct because solid sodium hydroxide is hygroscopic and readily absorbs moisture from the air, affecting its purity and concentration.
62 Medium
62 of 98
Remembering +4 | -1
When excess of SnCl2{SnCl}_2 is added to a solution of HgCl2,{HgCl}_2, a white ppt turning grey is obtained. The grey colour is due to the formation of
View answer and explanation
Correct option: D
Hg{Hg}
Option D (Hg{Hg}) is correct because the grey color is due to the formation of metallic mercury when HgCl2{HgCl}_2 is reduced by excess SnCl2{SnCl}_2.
63 Medium
63 of 98
Understanding +4 | -1
When adding the indicator to the conical flask,
only two or three drops are added because

(i) too much indicator may make it difficult
to see the colour change at the end-point


(ii) the indicator is corrosive, and adding too
much poses a greater risk

(iii) the indicator may be a weak acid or base
and may interfere with the titration result.

Which of the above statements is/are correct?
View answer and explanation
Correct option: C
(iii) only
Option C ((iii) only) is correct because indicators are weak acids or bases and can interfere with the titration result if too much is added.
64 Medium
64 of 98
Understanding +4 | -1
Which of the following doesn’t give a ppt. with silver nitrate solution.
View answer and explanation
Correct option: A
Ethyl bromide
Option A (Ethyl bromide) is correct because ethyl bromide does not readily provide free bromide ions (Br−Br^−) in solution to react with AgNO3AgNO_3 to form a precipitate.
65 Medium
65 of 98
Remembering +4 | -1
When K2Cr2O7{K}_2 {Cr}_2 {O}_7 crystals are heated with conc. HCl,{HCl}, the gas evolved is
View answer and explanation
Correct option: C
CrO2Cl2{CrO}_2 {Cl}_2
Option C (CrO2Cl2{CrO}_2 {Cl}_2) is correct because when K2Cr2O7{K}_2 {Cr}_2 {O}_7 crystals are heated with conc. HCl,{HCl}, chromyl chloride (CrO2Cl2{CrO}_2 {Cl}_2) gas is evolved.
66 Medium
66 of 98
Remembering +4 | -1
Identify the test which is not a part of qualitative analysis?
View answer and explanation
Correct option: A
Litmus test
Option A (Litmus test) is correct because the litmus test is used to determine the pH of a solution, while the other tests are used for identifying specific substances in qualitative analysis.
67 Medium
67 of 98
Remembering +4 | -1
To a metal nitrate, when KI\text{KI} solution is added, a black precipitate is produced at first, on adding excess of KI,\text{KI}, orange solution is produced. Identify the metal ion.
View answer and explanation
Correct option: A
Hg2+\mathrm{Hg}^{2+}
Option A (Hg2+\mathrm{Hg}^{2+}) is correct because Hg2+\mathrm{Hg}^{2+} forms a black precipitate with KI, which dissolves in excess KI to form an orange solution.
68 Hard
68 of 98
Analyzing +4 | -1
A NaOH\mathrm{NaOH} solution is to be standardized by titrating it against a known mass of potassium hydrogen phthalate. Which procedure will give a molarity of NaOH\mathrm{NaOH} that is too low?
View answer and explanation
Correct option: C
Neglecting to fill the tip of the buret with
NaOH\text{NaOH} solution before titrating
Option C is correct. If the tip of the buret is not filled, the volume of NaOH dispensed will be less than what is read, leading to an underestimation of the NaOH molarity.
69 Medium
69 of 98
Remembering +4 | -1
Blue borax bead is obtained with
View answer and explanation
Correct option: B
Cobalt
Option B (Cobalt) is correct because cobalt ions produce a blue color in the borax bead test due to the formation of cobalt(II) metaborate.
70 Medium
70 of 98
Analyzing +4 | -1
An aqueous solution of colourless metal sulphate M,M, gives a white ppt. with NH4OH.\mathrm{NH}_4 \mathrm{OH}. This was soluble in excess of NH4OH.\mathrm{NH}_4 \mathrm{OH}. On passing H2S\mathrm{H}_2 \mathrm{S} through this solution a white ppt is formed. The metal MM in the salt is
View answer and explanation
Correct option: D
Zn\mathrm{Zn}
Option D (Zn) is correct because Zinc sulfate (ZnSO4) forms a white precipitate with NH4OH that dissolves in excess, and then forms a white precipitate of ZnS with H2S.
71 Medium
71 of 98
Understanding +4 | -1
Which method(s) can be used to determine the concentration of HNO3\mathrm{HNO}_3 in an aqueous solution of nitric acid?

I) titration with a standard base

II) titration with a standard oxidizing agent

III) precipitation with Ag+\mathrm{A g}^+
View answer and explanation
Correct option: A
I only
Option A (I only) is correct because the concentration of HNO3, being an acid, can be determined by titration with a standard base.
72 Medium
72 of 98
Remembering +4 | -1
......... is formed when potassium iodide is heated with conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4
View answer and explanation
Correct option: B
I2I_2
Option B (I2I_2) is correct because when potassium iodide is heated with concentrated H2SO4\mathrm{H}_2 \mathrm{SO}_4, iodine (I2I_2) is produced.
73 Medium
73 of 98
Analyzing +4 | -1
An aqueous solution of FeSO4⋅Al2(SO4)3\mathrm{FeSO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 and chrome alum is heated with excess of Na2O2\mathrm{Na}_2 \mathrm{O}_2 and filtered the materials obtained are
View answer and explanation
Correct option: C
A yellow filtrate and a brown residue
The correct answer is C (A yellow filtrate and a brown residue) because the yellow filtrate contains sodium chromate (Na₂CrO₄) formed by oxidation of Cr³⁺, and the brown residue is due to the formation of basic ferric sulfate from the oxidation of FeSO₄.
74 Medium
74 of 98
Remembering +4 | -1
Which of the following does not give NH3{NH}_3 on heating with NaOHNaOH solution?
View answer and explanation
Correct option: B
Aniline
Option B (Aniline) is correct because aniline does not have an amide group that can be hydrolyzed by NaOH to release ammonia.
75 Hard
75 of 98
Application +4 | -1
100 ml100 \mathrm{~ml} of 0.1 M0.1 \mathrm{~M} aqueous ferric alum solution is completely reduced with Iron to give Ferrous Ions. The volume of 0.1 M0.1 \mathrm{~M} acidified KMnO4\mathrm{KMnO}_4 solution required for complete reaction with ferrous Ions in the solution will be
View answer and explanation
Correct option: C
40 ml40 \mathrm{~ml}
Option C (40 ml) is correct because the volume of KMnO4 required is determined by the stoichiometry of the reactions involved in the reduction of ferric alum and subsequent oxidation of ferrous ions.
76 Medium
76 of 98
Analyzing +4 | -1
When a substance AA reacts with water it produces a combustible gas BB and a solution of substance CC in water. When another substance DD reacts with this solution of C,C, it also produces the same gas BB on warming but DD can produce gas BB on reaction with dilute sulphuric acid at room temperature. AA imparts a deep golden yellow colour a smokeless flame to Bunsen burner. A,B,CA, B, C and DD respectively are:
View answer and explanation
Correct option: A
Na,H2,NaOH,Zn\mathrm{Na}, \mathrm{H}_2, \mathrm{NaOH}, \mathrm{Zn}
The correct answer is A (Na,H2,NaOH,Zn\mathrm{Na}, \mathrm{H}_2, \mathrm{NaOH}, \mathrm{Zn}) because it correctly identifies the substances based on their reactions with water and acids, and the flame test.
77 Medium
77 of 98
Remembering +4 | -1
The compound formed in the borax bead test of Cu2+\mathrm{Cu}^{2+} ion in oxidising flame is:
View answer and explanation
Correct option: C
Cu(BO2)2\mathrm{Cu}\left(\mathrm{BO}_2\right)_2
Option C (Cu(BO2)2\mathrm{Cu}(\mathrm{BO}_2)_2) is correct because in the borax bead test, Cu2+\mathrm{Cu}^{2+} ions react with borax to form cupric metaborate, which has a characteristic color.
78 Medium
78 of 98
Remembering +4 | -1
Phenolphltalein indicator is prepared by
dissolving phenolpthalein in
View answer and explanation
Correct option: B
Ethyl alcohol
Option B (Ethyl alcohol) is correct because phenolphthalein is soluble in ethyl alcohol and is typically dissolved in it to prepare the indicator solution.
79 Easy
79 of 98
Analyzing +4 | -1
[x]+H2SO4→[y][x]+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow[y] a colourless gas with irritating smell, [y]+K2Cr2O7+H2SO4→[{y}]+\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow green solution. [x][{x}] and [y][y] are
View answer and explanation
Correct option: A
SO32−,SO2\mathrm{SO}_3^{2-}, \mathrm{SO}_2
Option B is correct because gold chloride can react with copper, iron, nickel, chromium, zinc, or tin due to gold's high reduction potential, but the reason given is irrelevant.
80 Medium
80 of 98
Remembering +4 | -1
Which one of the following salt give green coloured flame when the salt is tested by Pt wire
View answer and explanation
Correct option: A
Barium salt
Option A (Barium salt) is correct because barium salts produce a green-colored flame in the flame test due to the excitation of barium ions.
81 Medium
81 of 98
Remembering +4 | -1
On passing a gas, 'XX', through Nessler's regent, a brown precipitate is obtained. The gas 'XX' is
View answer and explanation
Correct option: B
NH3{NH}_3
Option B (NH3{NH}_3) is correct because ammonia reacts with Nessler's reagent to form a brown precipitate.
82 Medium
82 of 98
Remembering +4 | -1
The presence of NH4+\mathrm{NH}_4^{+} radical in solution can be detected by
View answer and explanation
Correct option: D
Nessler's reagent
Option D (Nessler's reagent) is correct because Nessler's reagent (K₂HgI₄) reacts with ammonium ions (NH₄⁺) to form a brown precipitate, indicating the presence of ammonium ions.
83 Medium
83 of 98
Application +4 | -1
In Carius method of estimation of halogens, 0.5 g of an organic compound gave 0.376 g of AgBr. The percentage of bromine in the compound is (Atomic mass of Ag = 108 u and Br = 80 u)
View answer and explanation
Correct option: D
0.32
Option D (0.32) is correct because the percentage of bromine is calculated using the ratio of the mass of bromine to the mass of AgBr, multiplied by the ratio of the mass of AgBr to the mass of the organic compound, and then by 100.
84 Medium
84 of 98
Remembering +4 | -1
The metal ion which is precipitated when H2S\mathrm{H}_2 \mathrm{S} is passed with HCl.\mathrm{HCl}.
View answer and explanation
Correct option: C
Cd2+\mathrm{Cd}^{2+}
Option C (Cd2+\mathrm{Cd}^{2+}) is correct because Cadmium ions are precipitated as sulfides when H2S is passed through an acidic solution (HCl).
85 Hard
85 of 98
Analyzing +4 | -1
The molar mass of an unknown organic liquid (M∼100)(M \sim 100) is determined by placing 5 mL5 \mathrm{~mL} of the liquid in a weighed 125−mL125-\mathrm{mL} conical flask fitted with a piece of Al{Al} foil with a pin hole in it. The flask is heated in a boiling water bath until the liquid evaporates to expel the air and fill the flask with the unknown vapor at atmospheric pressure. After cooling to room temperature the flask and its contents are reweighed. The uncertainty in which piece of apparatus causes the largest percentage error in the molar mass?
View answer and explanation
Correct option: A
Balance (±0.01 g)( \pm 0.01 \mathrm{~g})
Option A is correct because the balance has the smallest absolute uncertainty but contributes the largest percentage error due to its impact on the molar mass calculation.
86 Medium
86 of 98
Analyzing +4 | -1
Which of the following pairs of cations can not be separated by using NH3\mathrm{NH}_3 solution.
View answer and explanation
Correct option: B
Zn+2,Cu+2\mathrm{Zn}^{+2}, \mathrm{Cu}^{+2}
Option D (Al+3,As3+\mathrm{Al}^{+3}, \mathrm{As}^{3+}) is correct because both aluminum and arsenic ions form precipitates with ammonia solution.
87 Medium
87 of 98
Remembering +4 | -1
In borax bead test, which of the following compound is formed
View answer and explanation
Correct option: A
Meta borate
Option A (Meta borate) is correct because in the borax bead test, metal oxides react with borax to form metaborates, which impart characteristic colors.
88 Medium
88 of 98
Understanding +4 | -1
Which of the following pairs of ions would be expected to form precipitate when dilute solution are mixed?
View answer and explanation
Correct option: D
Fe3+,PO43−\mathrm{Fe}^{3+}, \mathrm{PO}_4^{3-}
Option D (Fe3+, PO43-) is correct because Fe3+ and PO43- ions react to form insoluble iron(III) phosphate (FePO4), which precipitates out of the solution.
89 Medium
89 of 98
Remembering +4 | -1
When acetic acid and potassium ferrocyanide are added to copper salt, the colour of the precipitate is
View answer and explanation
Correct option: C
Brown
Option C (Brown) is correct because the reaction between copper salt and potassium ferrocyanide results in a reddish brown precipitate of copper ferrocyanide.
90 Medium
90 of 98
Remembering +4 | -1
MnO2MnO_2 and H2SO4H_2SO_4 added to NaCl, the greenish yellow gas liberated is
View answer and explanation
Correct option: A
Cl2Cl_2
Option A (Cl2Cl_2) is correct because the reaction of MnO2MnO_2 and H2SO4H_2SO_4 with NaCl produces chlorine gas, which is greenish-yellow.
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