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JEE • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-98 of 98 questions

91 Easy

91 of 98

Remembering +4 | -1

Beilstein test used for

View answer and explanation

Correct option: A

Halogens

Option A (Halogens) is correct because the Beilstein test is used to detect the presence of halogens in a chemical substance.

92 Easy

92 of 98

Remembering +4 | -1

Mercurous ion is represented as:

View answer and explanation

Correct option: A

\mathrm{Hg}_2^{2+}

The correct answer is A (

\mathrm{Hg}_2^{2+}

) because the mercurous ion exists as a diatomic species with a +2 charge overall, meaning each mercury atom has a +1 oxidation state.

93 Medium

93 of 98

Understanding +4 | -1

Sometimes yellow turbidity appears while passing

\mathrm{H}_2 \mathrm{S}

gas even in the absence of II group radicals. This is because of

View answer and explanation

Correct option: C

The oxidation of

\mathrm{H}_2 \mathrm{S}

gas by some acid radicals

Option C (The oxidation of

\mathrm{H}_2 \mathrm{S}

gas by some acid radicals) is correct because the yellow turbidity is due to the formation of elemental sulfur by the oxidation of

H_2S

by oxidizing agents present.

94 Medium

94 of 98

Remembering +4 | -1

An orange precipitate in the second group is given by

View answer and explanation

Correct option: B

\mathrm{Sb}^{3+}

Option B (

\mathrm{Sb}^{3+}

) is correct because antimony(III) sulfide (

\mathrm{Sb}_2 \mathrm{S}_3

) precipitates as an orange solid in the second group analysis.

95 Medium

95 of 98

Remembering +4 | -1

Mark the compound which is soluble in hot water.

View answer and explanation

Correct option: A

Lead chloride

Option A (Lead chloride) is correct because lead chloride (

PbCl_2

) is known to be soluble in hot water due to increased kinetic energy breaking the lattice structure.

96 Medium

96 of 98

Remembering +4 | -1

\text{NiS}

is separated from

\mathrm{ZnS}

by treating with

View answer and explanation

Correct option: B

conc.

\mathrm{HCl}

Option B (conc.

\mathrm{HCl}

) is correct because

\mathrm{NiS}

is insoluble in conc.

\mathrm{HCl}

while

\mathrm{ZnS}

is soluble.

97 Medium

97 of 98

Remembering +4 | -1

When

\mathrm{H}_2 \mathrm{S}

gas is passed in a metal sulphate solution in presence of

\mathrm{NH}_4 \mathrm{OH},

a white precipitate is produced. The metal is identified as

View answer and explanation

Correct option: A

\mathrm{Zn}

Option A is correct because Zinc (Zn) ions react with H2S in the presence of NH4OH to form a white precipitate of Zinc sulfide (ZnS).

98 Medium

98 of 98

Remembering +4 | -1

Which of the following statements is correct about phenolphthalein:

(A) It is a phthalein dye.

(B) It is used as an acid base indicator

(C) It is obtained by condensation of phenol with phthalic anhydride in presence of conc.

\mathrm{H}_2 \mathrm{SO}_4

View answer and explanation

Correct option: D

A, B, C

Option D (A, B, C) is correct because all three statements about phenolphthalein are accurate and well-established facts.

Revision notes and key takeaways

Review PRACTICAL CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

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