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JEE • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 98 questions

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31 Medium
31 of 98
Remembering +4 | -1
Test by which starch and cellulose can be distinguished from each other is
View answer and explanation
Correct option: C
Iodine test
Option C (Iodine test) is correct because starch gives a blue-black color with iodine, while cellulose does not.
32 Medium
32 of 98
Understanding +4 | -1
The ion which can be precipitated with H2S\mathrm{H}_2 \mathrm{S} in presence of NH4OH\mathrm{NH}_4 \mathrm{OH}
View answer and explanation
Correct option: B
Ni+2\mathrm{Ni}^{+2}
The correct answer is B. Ni+2Ni^{+2} is a group IV cation that precipitates as a sulfide in the presence of H2SH_2S and NH4OHNH_4OH.
33 Medium
33 of 98
Remembering +4 | -1
Which of the following is used to oxidise Fe+2\mathrm{Fe}^{+2} to Fe+3\mathrm{Fe}^{+3} in III group.
View answer and explanation
Correct option: C
conc. HNO3\mathrm{HNO}_3
Option C (conc. HNO3\mathrm{HNO}_3) is correct because concentrated nitric acid is a strong oxidizing agent that can oxidize Fe+2\mathrm{Fe}^{+2} to Fe+3\mathrm{Fe}^{+3}.
34 Medium
34 of 98
Remembering +4 | -1
The sulphides of which one of the following groups of elements are soluble in yellow ammonium sulphide?
View answer and explanation
Correct option: C
As,Sb and Sn\mathrm{As}, \mathrm{Sb} \text{ and }\mathrm{Sn}
Option C (As,Sb and Sn\mathrm{As}, \mathrm{Sb} \text{ and }\mathrm{Sn}) is correct because the sulfides of Arsenic (As), Antimony (Sb), and Tin (Sn) are soluble in yellow ammonium sulfide.
35 Medium
35 of 98
Understanding +4 | -1
An inorganic salt on reaction with dil. HClHCl (or dil H2SO4)\text{(or dil }\mathrm{H}_2 \mathrm{SO}_4) gives colourless gas, which turns lime water milky. The anion present in the salt is
View answer and explanation
Correct option: A
CO32−\mathrm{CO}_3^{2-}
Option A is correct because carbonate ions react with dilute HCl to produce carbon dioxide, which turns lime water milky.
36 Hard
36 of 98
Analyzing +4 | -1
An equimolar mixture of ferrous oxalate & stannous chloride is treated with decinormal acidic KMnO4\mathrm{KMnO}_4 giving ferric, stannic & chlorate ions along with CO2\mathrm{CO}_2 gas. If the titre value is 225 ml.225 \mathrm{~ml}. Numbers of millimoles of chlorate ions produced are
View answer and explanation
Correct option: D
2.64 m moles
Option D is correct because the calculation of millimoles of chlorate ions produced is based on the stoichiometry of the redox reactions, resulting in 2.64 m moles.
37 Medium
37 of 98
Remembering +4 | -1
Which sulphide is soluble in (NH4)2CO3\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3
View answer and explanation
Correct option: B
AS2S3A S_2 S_3
Option B (AS2S3AS_2 S_3) is correct because Arsenic trisulfide (As2S3\mathrm{As_2S_3}) is soluble in ammonium carbonate due to the formation of soluble complex ions.
38 Medium
38 of 98
Analyzing +4 | -1
A white powder when strongly heated gives off brown fumes. A solution of this powder gives a yellow precipitate with a solution of KI.\text{KI}. When a solution of barium chloride is added to a solution of powder, a white precipitate results. This white powder may be
View answer and explanation
Correct option: D
AgNO3\mathrm{AgNO}_3
The correct answer is D (AgNO3\mathrm{AgNO}_3) because it decomposes to give brown fumes of NO2NO_2, forms a yellow precipitate with KI (AgI), and reacts with barium chloride to form a white precipitate of AgCl.
39 Medium
39 of 98
Understanding +4 | -1
Which is maximum hydrated:
View answer and explanation
Correct option: D
SiCl4{SiCl}_4
Option D (SiCl4{SiCl}_4) is correct because the hydration energy is proportional to the charge density of the cation, and Si4+Si^{4+} has the highest charge density among the given options.
40 Medium
40 of 98
Remembering +4 | -1
Starch iodide paper is used to test for the presence of :
A. iodide ion
B. oxidising agent
C. reducing agent

D. iodine
View answer and explanation
Correct option: D
Oxidising agent
Option D (Oxidising agent) is correct because starch iodide paper is used to detect the presence of oxidizing agents, which oxidize iodide ions to iodine, forming a blue-violet complex with starch.
41 Medium
41 of 98
Remembering +4 | -1
Of the following sulphides which one is insoluble in dil. acids but soluble in alkalies.
View answer and explanation
Correct option: D
Sb2S3\mathrm{Sb}_2 \mathrm{S}_3
Option D is correct. Sb2S3\mathrm{Sb}_2 \mathrm{S}_3 is insoluble in dilute acids but soluble in alkalies, forming thioantimonate(III) and antimonite(III) ions.
42 Medium
42 of 98
Remembering +4 | -1
All of the following can be used as primary standards in acid-base titrations EXCEPT:
View answer and explanation
Correct option: D
Sodium hydroxide
Option D (Sodium hydroxide) is correct because NaOH is hygroscopic and absorbs moisture from the air, making it difficult to obtain in a pure, stable form for accurate standardization.
43 Medium
43 of 98
Remembering +4 | -1
Mark the correct statement:
View answer and explanation
Correct option: D
All the above statement are correct
Option D (All the above statement are correct) is correct because each statement accurately describes the precipitation of basic radicals in qualitative analysis.
44 Medium
44 of 98
Remembering +4 | -1
A black sulphide is formed by the action of H2S\mathrm{H}_2 \mathrm{S} on
View answer and explanation
Correct option: A
Cupric chloride
Option A (Cupric chloride) is correct because cupric chloride reacts with hydrogen sulfide to form copper sulfide, which is a black precipitate.
45 Hard
45 of 98
Understanding +4 | -1
A purple coloured solution is added from a burette to FeSO4\mathrm{FeSO}_4 solution kept in the flask. After sometime, the purple colour changes to light pink. The ion formed from that solution is
View answer and explanation
Correct option: D
Mn2+\mathrm{Mn}^{2+}
Option D (Mn2+\mathrm{Mn}^{2+}) is correct because the purple color of KMnO4\mathrm{KMnO}_4 is due to MnO4−\mathrm{MnO}_4^{-} which is reduced to the almost colorless Mn2+\mathrm{Mn}^{2+} ion.
46 Medium
46 of 98
Understanding +4 | -1
In (III) group of basic radical analysis, NH4Cl\mathrm{NH}_4 \mathrm{Cl} is added before group reagent NH4OH.\mathrm{NH}_4 \mathrm{OH}. This is due to
View answer and explanation
Correct option: D
Decrease the degree of ionisation of group reagent
Option D (CH3OH\mathrm{CH}_3 \mathrm{OH}) is correct because alcohols are more acidic than terminal alkynes, benzene, and alkanes due to the electronegativity of oxygen.
47 Medium
47 of 98
Analyzing +4 | -1
The ion that cannot be precipitated by both HCl{HCl} and H2S{H}_2 {S} is
View answer and explanation
Correct option: C
Ag+{Ag}^{+}
Option C (Ag+{Ag}^{+}) is correct because Ag+{Ag}^{+} is precipitated only by HCl{HCl}, not by H2S{H}_2{S}.
48 Medium
48 of 98
Remembering +4 | -1
Which of the following will not produce a precipitate with AgNO3AgNO_3 solution
View answer and explanation
Correct option: A
F−F^-
Option A (F−F^-) is correct because silver fluoride (AgFAgF) is soluble in water and does not form a precipitate with AgNO3AgNO_3 solution.
49 Medium
49 of 98
Remembering +4 | -1
A colourless salt gives violet colour in bunsen flame, it may be
View answer and explanation
Correct option: D
K2CO3\mathrm{K}_2 \mathrm{CO}_3
Option D (K2CO3\mathrm{K}_2 \mathrm{CO}_3) is correct because potassium ions (K+K^+) impart a violet color to the Bunsen flame.
50 Medium
50 of 98
Remembering +4 | -1
Which of the following sulphate is insoluble in water?
View answer and explanation
Correct option: C
PbSO4\mathrm{PbSO}_4
Option C (PbSO4\mathrm{PbSO}_4) is correct because lead sulfate is known to be insoluble in water due to the strong lattice energy.
51 Medium
51 of 98
Analyzing +4 | -1
Addition of excess of ammonium chloride ammonia buffer to a solution containing nitrates of Al,\mathrm{Al}, Bi,\mathrm{Bi}, Mg\mathrm{Mg} and Zn\mathrm{Zn} will precipitate hydroxides of
View answer and explanation
Correct option: A
Al and Bi\mathrm{Al} \text{ and }\mathrm{Bi}
The correct answer is A because Al and Bi hydroxides have lower solubility products and will precipitate out in the presence of the ammonium chloride/ammonia buffer, while Mg and Zn hydroxides require higher pH for precipitation.
52 Medium
52 of 98
Remembering +4 | -1
Which is not dissolved by dil HCl?\mathrm{HCl}?
View answer and explanation
Correct option: D
BaSO4\mathrm{BaSO}_4
Option D (BaSO4\mathrm{BaSO}_4) is correct because barium sulfate is insoluble in dilute hydrochloric acid.
53 Hard
53 of 98
Application +4 | -1
A 16 ml16 \mathrm{~ml} volume of 0.2 M KMnO40.2 \mathrm{~M} \mathrm{~KMnO}_4 solution is needed to oxidize 25.00 ml25.00 \mathrm{~ml} of a FeSO4\mathrm{FeSO}_4 solution in an acidic medium. What is the number of moles of FeSO4\mathrm{FeSO}_4 being oxidized for the reaction
View answer and explanation
Correct option: B
1.6×10−21.6 \times 10^{-2}
Option B (1.6×10−21.6 \times 10^{-2}) is correct because it represents the number of moles of FeSO4 oxidized, calculated using the stoichiometry of the redox reaction with KMnO4.
54 Medium
54 of 98
Remembering +4 | -1
Which of the following give white precipitate when HCl\mathrm{HCl} is added to its aqueous solution
View answer and explanation
Correct option: A
Hg+\mathrm{Hg}^{+}
Option A (Hg+\mathrm{Hg}^{+}) is correct because mercurous ions react with HCl to form a white precipitate of mercurous chloride.
55 Medium
55 of 98
Understanding +4 | -1
A one litre flask is full of brown bromine vapours. The intensity of brown colour of vapour will not decrease appreciably on adding to the flask some.
View answer and explanation
Correct option: A
Pieces of marble
Option A (Pieces of marble) is correct because marble (calcium carbonate) does not react significantly with bromine vapor, thus not decreasing the color intensity.
56 Medium
56 of 98
Remembering +4 | -1
Sodium sulphite on heating with dilute HClHCl liberates a gas which
View answer and explanation
Correct option: B
Turns acidified potassium dichromate paper green
Option B (Turns acidified potassium dichromate paper green) is correct because sulfur dioxide gas (SO2SO_2) released from the reaction reduces dichromate ions (Cr2O72−Cr_2O_7^{2-}) to chromium ions (Cr3+Cr^{3+}), causing the color change.
57 Medium
57 of 98
Remembering +4 | -1
Disodium hydrogen phoshate is used to test:
View answer and explanation
Correct option: A
Mg2+\mathrm{Mg}^{2+}
Option A (Mg2+\mathrm{Mg}^{2+}) is correct because disodium hydrogen phosphate is used in a test to detect the presence of magnesium ions (Mg2+\mathrm{Mg}^{2+}) in solution, forming a white precipitate of magnesium ammonium phosphate.
58 Medium
58 of 98
Analyzing +4 | -1
Which one among the following pairs of ions cannot be separated by H2S{H}_2 {S} in dilute HCl?{HCl}?
View answer and explanation
Correct option: A
Bi3+,Sn4+\mathrm{Bi}^{3+}, \mathrm{Sn}^{4+}
Option A is correct because both Bi3+ and Sn4+ precipitate as sulfides in dilute HCl with H2S, making their separation impossible under these conditions.
59 Medium
59 of 98
Remembering +4 | -1
The reagent NH4Cl\mathrm{NH}_4 \mathrm{Cl} and aqueous NH3\mathrm{NH}_3 will precipitate
View answer and explanation
Correct option: B
Al3+\mathrm{Al}^{3+}
Option B (Al3+\mathrm{Al^{3+}}) is correct because Al3+\mathrm{Al^{3+}} precipitates as Al(OH)3\mathrm{Al(OH)_3} in the presence of NH4Cl\mathrm{NH_4Cl} and aqueous NH3\mathrm{NH_3}.
60 Medium
60 of 98
Analyzing +4 | -1
A mixture of chlorides of copper, cadmium, chromium, iron and aluminium was dissolved in water acidified with HCl{HCl} and hydrogen sulphide gas was passed for sufficient time. It was filtered, boiled and a few drops of nitric acid were added while boiling. To this solution ammonium chloride and solution hydroxide were added and filtered. The filtrate shall give test for
View answer and explanation
Correct option: B
Sodium and aluminium
Option B (Sodium and aluminium) is correct because after precipitation of CuS and CdS by H2S, and boiling with HNO3, Al3+ forms [Al(OH)4]− in the presence of NH4Cl and NH4OH, which remains in the filtrate along with Na+.
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