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JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Medium

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Showing 61-90 of 195 questions

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61 Medium
61 of 195
Remembering +4 | -1
Formulae of phenyl carbinol and chloral are respectively :
View answer and explanation
Correct option: B
C6H5CH2OH  and  CCl3CHO{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH\;}{\kern 1pt} {\kern 1pt} \mathrm{and}{\kern 1pt} \mathrm{\;CC}{\mathrm{l}_3}\mathrm{CHO}
Option B (C6H5CH2OH  and  CCl3CHO{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH\;}{\kern 1pt} {\kern 1pt} \mathrm{and}{\kern 1pt} \mathrm{\;CC}{\mathrm{l}_3}\mathrm{CHO}) is correct because it correctly represents the structures of phenyl carbinol and chloral.
62 Medium
62 of 195
Understanding +4 | -1
Which of the following is the most powerful meta directing group?
View answer and explanation
Correct option: A
−NO2- N{O_2}
Option A is correct because MnO2 reacts with HCl to produce Cl2, which reacts with NH3 to form NCl3.
63 Medium
63 of 195
Remembering +4 | -1
During the quantitative analysis of salt cation y2+,{\mathrm{y}^{2 + }}, addition of a reagent (X) to alkaline solution of the salt gives a bright red precipitate. The reagent (X) and the cation (y2+)\left( {{\mathrm{y}^{2 + }}} \right) present respectively are:
View answer and explanation
Correct option: A
Dimethylglyoxime and Ni2+N{i^{2 + }}
Option A (Dimethylglyoxime and Ni2+N{i^{2 + }}) is correct because dimethylglyoxime (DMG) reacts with Ni2+N{i^{2 + }} in alkaline solution to form a bright red precipitate.
64 Medium
64 of 195
Analyzing +4 | -1
The most stable free radical is
View answer and explanation
Correct option: D
PhC∙HMe{\text{Ph}}\mathop {\text{C}}\limits^ \bullet {\text{HMe}}
Option D is correct because PhC∙HMe{\text{Ph}}\mathop {\text{C}}\limits^ \bullet {\text{HMe}} is the most stable free radical due to resonance stabilization from the phenyl group and hyperconjugation from the methyl group.
65 Medium
65 of 195
Analyzing +4 | -1
In which of the following p−p -electrons of the halogens are not involved in delocalisation?
View answer and explanation
Correct option: C
Allyl chloride
Option C (Allyl chloride) is correct because in allyl chloride, the p-electrons of chlorine are not directly involved in delocalization with the pi system of the double bond.
66 Medium
66 of 195
Remembering +4 | -1
Examples of electron withdrawing groups relative to hydrogen are
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because −NO2-\mathrm{NO}_2, −COOH-\mathrm{COOH}, and −COOR-\mathrm{COOR} are all electron-withdrawing groups relative to hydrogen.
67 Medium
67 of 195
Remembering +4 | -1
The energy of C−C\mathrm{C}-\mathrm{C} triple bond in acetylene in kcal is :
View answer and explanation
Correct option: B
192
Option B (192) is correct because the bond energy of a C-C triple bond is approximately 192 kcal/mol.
68 Medium
68 of 195
Application +4 | -1
0.4 g of a silver salt of a monobasic orgainc acid gave 0.26 g pure silver on ignition. the molecular weight of the acid is (atomic weight of silver=108)
View answer and explanation
Correct option: A
58
Option A (58) is correct because the equivalent weight of the acid is calculated from the mass of silver obtained from the silver salt.
69 Medium
69 of 195
Analyzing +4 | -1
Which of the following is the strongest base?
View answer and explanation
Correct option: A
C2H5−{\mathrm{C}_2}\mathrm{H}_5^ -
Option A (HCOOCH(CH3)2{HCOOCH}({CH}_3)_2) is correct because NaAlH4NaAlH_4 reduces the ester to HCHOHCHO and (CH3)2CHOH(CH_3)_2CHOH, indicating the ester was derived from formic acid and isopropanol.
70 Medium
70 of 195
Understanding +4 | -1
The sulphur present in an organic compound is oxidized by fuming nitric acid into:
View answer and explanation
Correct option: B
H2SO4{H_2}S{O_4}
Option B (H2SO4{H_2}S{O_4}) is correct because fuming nitric acid is a strong oxidizing agent that oxidizes sulfur to sulfuric acid.
71 Medium
71 of 195
Analyzing +4 | -1
Assertion (A): The order of stability of carbanion are (C6H5)C−>C6H5CH2−>allyl >CH3−>(CH3)2CH−\left(\mathrm{C}_6 \mathrm{H}_5\right) \mathrm{C}^{-} > \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2^{-} > \text {allyl } > \mathrm{CH}_3^{-} > \left(\mathrm{CH}_3\right)_2 \mathrm{CH}^{-}
Reason (R): The stability of carbanions is influenced by both resonance and inductive effects.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
The correct answer is A because both the assertion and the reason are true, and the reason correctly explains why the order of stability of carbanions is as stated, due to the influence of both resonance and inductive effects.
72 Medium
72 of 195
Understanding +4 | -1
During AgNO3\mathrm{AgN}{\mathrm{O}_3} test for detection of halogens, sodium extract is boiled with few drops of conc. HNO3\mathrm{HN}{\mathrm{O}_3} to decompose
View answer and explanation
Correct option: C
Both (a) and (b)
The correct answer is C (Both (a) and (b)) because both sodium cyanide and sodium sulfide can interfere with the silver nitrate test and need to be removed by boiling with nitric acid.
73 Medium
73 of 195
Analyzing +4 | -1
A metal M\mathrm{M} and its compound can give the following observable changes in a consequences of reactions

M→HNO3 dilute [ Colourless  solutions ]→NaOH aqueous [ White  precipitate ]→NaOH(aq.)excess[Colourlesssolutions]→H2S[ White  precipitate ]{\text{M}}\xrightarrow[{{\text{HN}}{{\text{O}}_{\text{3}}}}]{{{\text{ dilute }}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ Colourless }}} \\ {{\text{ solutions }}} \end{array}} \right]\xrightarrow[{{\text{NaOH}}}]{{{\text{ aqueous }}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ White }}} \\ {{\text{ precipitate }}} \end{array}} \right]\xrightarrow[{{\text{NaOH}}\left( {{\text{aq}}{\text{.}}} \right)}]{{{\text{excess}}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{Colourless}}} \\ {{\text{solutions}}} \end{array}} \right]\xrightarrow{{{{\text{H}}_2}{\text{S}}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ White }}} \\ {{\text{ precipitate }}} \end{array}} \right]
View answer and explanation
Correct option: C
Zn\mathrm{Zn}
Option C (Zn) is correct because Zinc (Zn) exhibits the described reaction sequence with dilute HNO3, NaOH, and H2S.
74 Medium
74 of 195
Analyzing +4 | -1
A compound with molecular formula, C7H16{C_7}{H_{16}} shows optical isomerism, the compound will be:
View answer and explanation
Correct option: A
2, 3-dimethylpentane
Option A (2, 3-dimethylpentane) is correct because it is the only structure listed that contains a chiral carbon, allowing for optical isomerism.
75 Medium
75 of 195
Application +4 | -1
Which one of the following will show optical isomerism?
View answer and explanation
Correct option: B
H3C−C∣∣OHH−CO2H{\mathrm{H}_3}\mathrm{C} - \mathop {\mathop \mathrm{C}\limits_|^| }\limits_{OH}^\mathrm{H} - \mathrm{C}{\mathrm{O}_2}\mathrm{H}
Option B (H3C−C∣∣OHH−CO2H{\mathrm{H}_3}\mathrm{C} - \mathop {\mathop \mathrm{C}\limits_|^| }\limits_{OH}^\mathrm{H} - \mathrm{C}{\mathrm{O}_2}\mathrm{H}) is correct because it contains a chiral carbon atom bonded to four different groups (H, OH, CH3CH_3, COOHCOOH).
76 Medium
76 of 195
Analyzing +4 | -1
Assertion: Cyclo hexane floats over water.

Reason: Cyclohexane generally exists as boat conformers.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because cyclohexane floats on water due to its lower density, but the reason is false because cyclohexane predominantly exists in the chair conformation, not the boat conformation.
77 Medium
77 of 195
Understanding +4 | -1
In which of the following functional group isomerism is not possible?
View answer and explanation
Correct option: C
Alkyl halides
The correct answer is C (Alkyl halides) because alkyl halides typically do not exhibit functional group isomerism.
78 Medium
78 of 195
Analyzing +4 | -1
When thiourea is heated with metallic sodium, the compound which can't be formed is
View answer and explanation
Correct option: C
Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}
Option C (Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}) is correct because thiourea contains only N, H, C, and S, so it cannot form a sulfate.
79 Medium
79 of 195
Analyzing +4 | -1
Metal chloride AA is soluble in hot water but insoluble in cold water. Select correct statement about AA thus
View answer and explanation
Correct option: D
All of the above are correct statements
Option D (All of the above are correct statements) is correct because PbCl2 reacts with K2CrO4, K2SO4, and KI to form yellow, white, and yellow precipitates, respectively.
80 Medium
80 of 195
Understanding +4 | -1
In Lassaigne's test, the organic compound is fused with a piece of sodium metal in order to
View answer and explanation
Correct option: D
Convert the covalent compound into a mixture of ionic compounds
The correct answer is D (Convert the covalent compound into a mixture of ionic compounds) because fusing the organic compound with sodium converts covalent bonds to ionic bonds, facilitating the detection of elements.
81 Medium
81 of 195
Remembering +4 | -1
In paper chromatography:
View answer and explanation
Correct option: A
Mobile phase is liquid and stationary phase is solid
The correct answer is A (Mobile phase is liquid and stationary phase is solid) because in paper chromatography, the mobile phase is a liquid solvent and the stationary phase is the paper itself, which acts as a solid support.
82 Medium
82 of 195
Remembering +4 | -1
In Carius method, halogen containing organic compound is heated with fuming nitric acid in the presence of
View answer and explanation
Correct option: B
AgNO3AgN{O_3}
Option B (AgNO3AgN{O_3}) is correct because in the Carius method, silver nitrate (AgNO3AgNO_3) is used to precipitate the halogen as a silver halide.
83 Medium
83 of 195
Analyzing +4 | -1
Which of the following compound chiral?
View answer and explanation
Correct option: C
DCH2CH2CH2Cl{DCH}_2 {CH}_2{CH}_2 {Cl}
The correct answer is D (CH3CHClCH2D) because it is the only option with a carbon atom bonded to four different groups (H, D, Cl, and CH3).
84 Medium
84 of 195
Remembering +4 | -1
Halogens in an organic compound can be detected by:
View answer and explanation
Correct option: B
Carius method
Option B (Carius method) is correct because the Carius method is specifically designed to quantitatively determine the amount of halogens present in an organic compound by converting them to silver halides.
85 Medium
85 of 195
Analyzing +4 | -1
Assertion: The compounds having double bond between carbon atoms always show geometrical isomerism.

Reason: The rotation of groups or atom about carbon-carbon double bond is restricted.
View answer and explanation
Correct option: C
If the assertion is false but the reason is true
The correct answer is C (If the assertion is false but the reason is true) because not all compounds with double bonds show geometrical isomerism, but the restricted rotation is the reason geometrical isomerism can occur.
86 Medium
86 of 195
Remembering +4 | -1
Petroleum refining involves:
View answer and explanation
Correct option: C
Fractional distillation
Option C (Fractional distillation) is correct because petroleum refining uses fractional distillation to separate crude oil into different components based on their boiling points.
87 Medium
87 of 195
Analyzing +4 | -1
Statement I: Diffrent number of electron pairs are present in resonance structures.

Statement II: Resonance structures do not differ in the location of electrons around the constituent atoms.
View answer and explanation
Correct option: D
Statement II is correct but statement I is incorrect
The correct answer is D (Statement II is correct but statement I is incorrect) because resonance structures must have the same number of electron pairs, and they differ only in the location of electrons.
88 Medium
88 of 195
Analyzing +4 | -1
Statement I : CH3−CH∣OH−CH=CH−CH3C{H_3} - \mathop {\mathop {CH}\limits_| }\limits_{OH} - CH = CH - C{H_3} compound has three stereocentres
Statement II : Chiral centres have four different C-atoms
View answer and explanation
Correct option: B
Only Statement II is correct
Only Statement II is correct because chiral centers require four different atoms or groups, and Statement I incorrectly identifies the number of stereocenters.
89 Medium
89 of 195
Understanding +4 | -1
Which of the following fact(s) explain as to why p-nitrophenol is more acidic than phenol?
i) –I effect of nitro group
ii) Greater resonance effect of p-nitrophenoxy group
iii) Steric effect of bulky nitro group.
View answer and explanation
Correct option: A
i and ii
The correct answer is A (i and ii) because both the -I effect of the nitro group and resonance effect of p-nitrophenoxide ion contribute to the higher acidity of p-nitrophenol.
90 Medium
90 of 195
Analyzing +4 | -1
Aqueous solution of a salt +MgSO4+{MgSO}_4 solution →\rightarrow no ppt. in cold →Heating\xrightarrow{{{\text{Heating}}}} a white ppt. appears. The salt contains the acidic radical:
View answer and explanation
Correct option: B
HCO3−{HCO}_3^{-}
Option B (HCO3−HCO_3^−) is correct because bicarbonate ions react with MgSO4MgSO_4 upon heating to form a white precipitate of MgCO3MgCO_3.
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