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JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 345 questions

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241 Medium
241 of 345
Application +4 | -1
An organic compound contains C=40%,H=13.33%\mathrm{C}=40 \%, \mathrm{H}=13.33 \% and N=46.67%\mathrm{N}=46.67 \%. Its empirical formula would be
View answer and explanation
Correct option: C
CH4 N\mathrm{CH}_4 \mathrm{~N}
Option C (CH4N) is correct because it represents the simplest whole-number ratio of elements in the compound.
242 Easy
242 of 345
Remembering +4 | -1
The homolytic fission of a covalent bond liberates
View answer and explanation
Correct option: C
Free radicals
Option C (Free radicals) is correct because homolytic fission involves the equal sharing of electrons, resulting in the formation of free radicals.
243 Medium
243 of 345
Understanding +4 | -1
Assertion: Gravimetric analysis is a time-consuming method of analysis.

Reason: Gravimetric analysis requires the isolation and weighing of a product formed from the analyte, which can be a time-consuming process.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
The correct answer is B (Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion) because while both statements are true, the reason doesn't fully explain why gravimetric analysis is time-consuming.
244 Medium
244 of 345
Understanding +4 | -1
dd- tartaric acid and ll- tartaric acid are :
View answer and explanation
Correct option: D
Enantiomers
Option D (Enantiomers) is correct because d-tartaric acid and l-tartaric acid are non-superimposable mirror images of each other.
245 Medium
245 of 345
Analyzing +4 | -1
Ammonium salts on heating with slaked lime liberate a colourless gas (X)(X). Identify the incorrect statement for gas (X)(X).
View answer and explanation
Correct option: D
(X)(X) does not give clear solution with Ag2O{Ag}_2{O}
Option D ((X)(X) does not give clear solution with Ag2O{Ag}_2{O}) is correct because ammonia reacts with silver oxide to form a complex, resulting in a clear solution, not a precipitate.
246 Medium
246 of 345
Analyzing +4 | -1
Assertion: Tautomerism is shown by all nitro alkanes.

Reason: Tautomerism is shown only when mobile H{H} is present, so 1∘1^{\circ} and 2∘2^{\circ} nitro alkanes show tautomerism.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because not all nitro alkanes show tautomerism, and the presence of alpha-hydrogens is essential for tautomerism.
247 Medium
247 of 345
Understanding +4 | -1
Hyperconjugation is:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because hyperconjugation involves σ−π\sigma - \pi conjugation, delocalization of σ\sigma and π\pi bonds, and is also known as no-bond resonance.
248 Medium
248 of 345
Remembering +4 | -1
In sodium extract test of organic compounds, the nitrogen of an organic compound is converted into:
View answer and explanation
Correct option: B
Sodium cyanide
Option B (Sodium cyanide) is correct because in the Lassaigne's test, nitrogen in the organic compound is converted to sodium cyanide.
249 Medium
249 of 345
Understanding +4 | -1
Strongest nucleophile among the following is
View answer and explanation
Correct option: D
CH3O−\mathrm{CH}_3 \mathrm{O}^{-}
Option D (CH3O−\mathrm{CH}_3 \mathrm{O}^{-}) is correct because it is a strong nucleophile due to the negative charge and the electron-donating inductive effect of the methyl group, which increases electron density.
250 Medium
250 of 345
Analyzing +4 | -1
Assertion (A): The percentage of oxygen in an organic compound is usually found by difference between the total percentage composition (100) and the percentages of all other elements.

Reason (R): Oxygen is present everywhere.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct ; R\mathrm{R} is the correct explanation of AA.
Option A (Both A and R are correct; R is the correct explanation of A) is correct because the percentage of oxygen is often found by difference due to its ubiquitous presence.
251 Medium
251 of 345
Analyzing +4 | -1
An organic compound A is oxidised with Na2O2N{a_2}{O_2} followed by boiling with HNO3HN{O_3}. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation, the element present in the given compound is
View answer and explanation
Correct option: B
Phosphorus
Option B (Phosphorus) is correct because the formation of a yellow precipitate with ammonium molybdate indicates the presence of phosphate ions, which originate from phosphorus in the organic compound.
252 Medium
252 of 345
Application +4 | -1
0.5 g of hydrocarbon gave 0.9 g water on combustion. The percentage of carbon hydrocarbon is
View answer and explanation
Correct option: C
80.080.0
Option C (80.0) is correct because it calculates the percentage of carbon by subtracting the percentage of hydrogen from 100%.
253 Medium
253 of 345
Understanding +4 | -1
The correct order of acidic strength is:
View answer and explanation
Correct option: A
CH3CF2COOH>CH3CCl2COOH>CH3CBr2COOHC{H_3}C{F_2}COOH > C{H_3}CC{l_2}COOH > C{H_3}CB{r_2}COOH
The correct answer is CH3CF2COOH>CH3CCl2COOH>CH3CBr2COOHC{H_3}C{F_2}COOH > C{H_3}CC{l_2}COOH > C{H_3}CB{r_2}COOH because the acidity increases with the electron-withdrawing inductive effect (-I effect) of the halogens, and the -I effect decreases down the group (F > Cl > Br).
254 Medium
254 of 345
Understanding +4 | -1
Given below are two statements.
Statement I: The presence of weaker π - \pi {\text{ - }} bonds make alkenes less stable than alkanes.
Statement II: The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct.
Option A (Both Statement I and Statement II are correct) is correct because alkenes are indeed less stable than alkanes due to the weaker pi bond, and the strength of a double bond is greater than that of a single bond.
255 Easy
255 of 345
Analyzing +4 | -1
Assertion (A) : SO3\mathrm{SO}_3 is a nucleophile.

Reason (R): SO3\mathrm{SO}_3 has lone-pair of electrons.
View answer and explanation
Correct option: D
A\mathbf{A} and R\mathbf{R} both are false.
Option D (A and R both are false) is correct because SO3 is an electrophile, not a nucleophile, and while it has pi bonds, it doesn't have a lone pair of electrons on the sulfur atom.
256 Easy
256 of 345
Understanding +4 | -1
Which of the following techniques is based on adsorption of organic compounds on an adsorbent to different degrees?
View answer and explanation
Correct option: D
Chromatography
Option D (Chromatography) is correct because chromatography separates compounds based on their differential adsorption on an adsorbent.
257 Medium
257 of 345
Remembering +4 | -1
Which of the following chromates is not yellow in colour?
View answer and explanation
Correct option: C
Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4
Option C (Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4) is correct because silver chromate (Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4) is red, while the other chromates listed are yellow.
258 Medium
258 of 345
Analyzing +4 | -1
The compound C4H10O{C_4}{H_{10}}O can show
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because C4H10O{C_4}{H_{10}}O can exhibit metamerism, functional isomerism, and position isomerism.
259 Hard
259 of 345
Application +4 | -1
In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBrAgBr. The percentage of bromine in the compound is (at. Mass AgAg = 108, BrBr = 80)
View answer and explanation
Correct option: A
24
Option A (24) is correct because the percentage of bromine is calculated correctly using Carius method formula.
260 Medium
260 of 345
Analyzing +4 | -1
Which of the following compound is not chiral?
View answer and explanation
Correct option: A
1-Chloropentane
The correct answer is A (1-Chloropentane) because it does not have any chiral carbon atoms, meaning no carbon atom is bonded to four different groups.
261 Easy
261 of 345
Understanding +4 | -1
Fluorine is not tested by Beilstein’s test because
View answer and explanation
Correct option: B
Copper fluoride is not volatile
Option B (Copper fluoride is not volatile) is correct because Beilstein's test relies on the volatility of copper halides, and copper fluoride is not volatile.
262 Easy
262 of 345
Understanding +4 | -1
The percentage of ′s′'s' character of the hybrid orbital of carbon in ethane, ethane and ethyne respectively are:
View answer and explanation
Correct option: A
25, 33, 50
Option A (25, 33, 50) is correct because ethane is sp3 hybridized (25% s character), ethene is sp2 hybridized (33% s character), and ethyne is sp hybridized (50% s character).
263 Medium
263 of 345
Analyzing +4 | -1
How many isomers are possible for the compound having molecular formula C3H5Br3{\mathrm{C}_3}{\mathrm{H}_5}\mathrm{B}{\mathrm{r}_3}?
View answer and explanation
Correct option: A
5
Option A (5) is correct because there are 5 possible isomers for the given molecular formula.
264 Medium
264 of 345
Analyzing +4 | -1
Consider the following:

I. SH− II. F− III. N¨H3 IV. OH− V. OR−\text{I. }\mathrm{S H}^{-} \quad \text{ II. }\mathrm{F}^{-} \quad \text{ III. }{{\ddot{\text{N}}}}{{\text{H}}_3}\quad \text{ IV. }\mathrm{OH}^{-} \quad \text{ V. }\mathrm{OR}^{-}

What is the correct order of decreasing nucleophilicity in water?
View answer and explanation
Correct option: D
III >> I >> V >> IV >> II
Option D (III >> I >> V >> IV >> II) is correct because it reflects the correct order of nucleophilicity considering factors like charge, size, and solvent effects.
265 Medium
265 of 345
Remembering +4 | -1
Fischer projection indicates :
View answer and explanation
Correct option: A
Horizontal substituents above the plane
Option A (Horizontal substituents above the plane) is correct because in Fischer projections, horizontal lines represent bonds coming out of the plane towards the viewer.
266 Medium
266 of 345
Remembering +4 | -1
A Dewar flask is usually used to:
View answer and explanation
Correct option: D
Store liquid air
Option D (Store liquid air) is correct because a Dewar flask is designed to provide excellent thermal insulation, making it suitable for storing extremely cold liquids like liquid air.
267 Medium
267 of 345
Remembering +4 | -1
Racemic mixture is formed by mixing two
View answer and explanation
Correct option: D
Optical isomers
Option D (Optical isomers) is correct because a racemic mixture is formed by mixing equal amounts of two enantiomers, which are optical isomers.
268 Medium
268 of 345
Analyzing +4 | -1
Assertion: The IUPAC name of HC≡C−CH2−CH=CH2HC \equiv C - C{H_2} - CH = C{H_2} is pent-4-en-1-yne.

Reason: A triple bond is always given a lower locant than a double bond.
View answer and explanation
Correct option: D
If both the assertion and reason are false
Option A (Li) is correct because after the removal of one electron, Lithium attains a noble gas configuration, requiring significantly higher energy for the second ionization.
269 Medium
269 of 345
Understanding +4 | -1
The pair of electrons in the given carbanion, CH3 C≡C−C{H_3}\,C \equiv {C^ - } , is present in which of the following orbitals
View answer and explanation
Correct option: B
SPSP
Option B (SPSP) is correct because the carbanion is attached to a triply bonded carbon, which is sp hybridized, and the lone pair resides in the sp hybrid orbital.
270 Easy
270 of 345
Remembering +4 | -1
The phenomenon of existence of two or more compounds possessing the same molecular formula but different properties is called
View answer and explanation
Correct option: D
isomerism
Option D (isomerism) is correct because isomerism is the phenomenon where two or more compounds have the same molecular formula but different structural arrangements, leading to different properties.
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