Skip to main content
Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Your Progress

0 / 345 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 121-150 of 345 questions

Preparing practice and saved progress…

121 Medium
121 of 345
Understanding +4 | -1
During AgNO3\mathrm{AgN}{\mathrm{O}_3} test for detection of halogens, sodium extract is boiled with few drops of conc. HNO3\mathrm{HN}{\mathrm{O}_3} to decompose
View answer and explanation
Correct option: C
Both (a) and (b)
The correct answer is C (Both (a) and (b)) because both sodium cyanide and sodium sulfide can interfere with the silver nitrate test and need to be removed by boiling with nitric acid.
122 Medium
122 of 345
Analyzing +4 | -1
A metal M\mathrm{M} and its compound can give the following observable changes in a consequences of reactions

M→HNO3 dilute [ Colourless  solutions ]→NaOH aqueous [ White  precipitate ]→NaOH(aq.)excess[Colourlesssolutions]→H2S[ White  precipitate ]{\text{M}}\xrightarrow[{{\text{HN}}{{\text{O}}_{\text{3}}}}]{{{\text{ dilute }}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ Colourless }}} \\ {{\text{ solutions }}} \end{array}} \right]\xrightarrow[{{\text{NaOH}}}]{{{\text{ aqueous }}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ White }}} \\ {{\text{ precipitate }}} \end{array}} \right]\xrightarrow[{{\text{NaOH}}\left( {{\text{aq}}{\text{.}}} \right)}]{{{\text{excess}}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{Colourless}}} \\ {{\text{solutions}}} \end{array}} \right]\xrightarrow{{{{\text{H}}_2}{\text{S}}}}\left[ {\begin{array}{cccccccccccccccccccc} {{\text{ White }}} \\ {{\text{ precipitate }}} \end{array}} \right]
View answer and explanation
Correct option: C
Zn\mathrm{Zn}
Option C (Zn) is correct because Zinc (Zn) exhibits the described reaction sequence with dilute HNO3, NaOH, and H2S.
123 Medium
123 of 345
Analyzing +4 | -1
A compound with molecular formula, C7H16{C_7}{H_{16}} shows optical isomerism, the compound will be:
View answer and explanation
Correct option: A
2, 3-dimethylpentane
Option A (2, 3-dimethylpentane) is correct because it is the only structure listed that contains a chiral carbon, allowing for optical isomerism.
124 Hard
124 of 345
Application +4 | -1
In the estimation of nitrogen by Duma’s method 1.18 g of an organic compound gave 224 mL of N2{\mathrm{N}_2} at NTP. The percentage of nitrogen in the compound is about:
View answer and explanation
Correct option: D
23.723.7
Option D (23.723.7) is correct because it is the percentage of nitrogen calculated using Duma\'s method formula with the given values.
125 Medium
125 of 345
Application +4 | -1
Which one of the following will show optical isomerism?
View answer and explanation
Correct option: B
H3C−C∣∣OHH−CO2H{\mathrm{H}_3}\mathrm{C} - \mathop {\mathop \mathrm{C}\limits_|^| }\limits_{OH}^\mathrm{H} - \mathrm{C}{\mathrm{O}_2}\mathrm{H}
Option B (H3C−C∣∣OHH−CO2H{\mathrm{H}_3}\mathrm{C} - \mathop {\mathop \mathrm{C}\limits_|^| }\limits_{OH}^\mathrm{H} - \mathrm{C}{\mathrm{O}_2}\mathrm{H}) is correct because it contains a chiral carbon atom bonded to four different groups (H, OH, CH3CH_3, COOHCOOH).
126 Hard
126 of 345
Analyzing +4 | -1
Which of the following resonance structure is least stable?
View answer and explanation
Correct option: B
CH2=CH−C + H−C−H−OCH3{\text{C}}{{\text{H}}_{\text{2}}} = {\text{CH}} - \mathop {\text{C}}\limits^{\text{ + }} {\text{H}} - \mathop {\text{C}}\limits^ - {\text{H}} - {\text{OC}}{{\text{H}}_{\text{3}}}
Option B (CH2=CH−C + H−C−H−OCHext3{\text{C}}{{\text{H}}_{\text{2}}} = {\text{CH}} - \mathop {\text{C}}\limits^{\text{ + }} {\text{H}} - \mathop {\text{C}}\limits^ - {\text{H}} - {\text{OC}}{{\text{H}}_{ ext{3}}}) is the least stable because it has adjacent positive and negative charges on carbon atoms.
127 Easy
127 of 345
Analyzing +4 | -1
Which among the following has maximum stability
View answer and explanation
Correct option: A
CH2=CHC∙H2C{H_2} = \mathrm{ }CH\mathrm{ }\mathop C\limits^ \bullet {H_2}
Option A (CH2=CHC∙H2C{H_2} = \mathrm{ }CH\mathrm{ }\mathop C\limits^ \bullet {H_2}) is correct because allylic free radicals are more stable than primary, secondary, or tertiary free radicals due to resonance stabilization.
128 Easy
128 of 345
Remembering +4 | -1
Electrophiles are :
View answer and explanation
Correct option: A
Electron loving species
Option A (Electron loving species) is correct because electrophiles are electron-deficient species that are attracted to electron-rich areas.
129 Easy
129 of 345
Remembering +4 | -1
Rotation of plane polarized light can be measured by :
View answer and explanation
Correct option: C
Polarimeter
The correct answer is C (Polarimeter) because a polarimeter is an instrument used to measure the angle of rotation of plane-polarized light by an optically active substance.
130 Easy
130 of 345
Remembering +4 | -1
The optical isomers, which are not enantiomers, are called
View answer and explanation
Correct option: B
Diastereomer
Option B (Diastereomer) is correct because diastereomers are stereoisomers that are not mirror images of each other.
131 Easy
131 of 345
Understanding +4 | -1
In the hydrocarbon .CH3   −C CH  =5 CH   −4 CH2−3 C   ≡ 2 CH1_{C{H_3}\,\,\, - }^C\,_{CH\,\, = }^5\,_{CH\,\,\, - }^4\,_{C{H_2} - }^3\,_{C\,\,\, \equiv \,}^2\,_{CH}^1 the state of hybridisation of 1, 3 and 5 are in the following sequence
View answer and explanation
Correct option: B
SP,SP3,SP2SP,S{P^3},S{P^2}
Option B (SP,SP3,SP2SP,S{P^3},S{P^2}) is correct because the hybridizations of carbons 1, 3, and 5 are SP, SP3, and SP2 respectively, based on the number of sigma bonds.
132 Easy
132 of 345
Analyzing +4 | -1
Which of the following is a pair of functional isomers?
View answer and explanation
Correct option: B
C2H5CO2H,  CH3CO2CH3{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{C}{\mathrm{O}_2}\mathrm{H},\mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{O}_2}\mathrm{C}{\mathrm{H}_3}
Option C is correct because carboxylic acids and esters with the same molecular formula are functional isomers, as seen in the pair C2H5CO2H{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{C}{\mathrm{O}_2}\mathrm{H} and   CH3CO2CH3\mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{O}_2}\mathrm{C}{\mathrm{H}_3}.
133 Medium
133 of 345
Analyzing +4 | -1
Assertion: Cyclo hexane floats over water.

Reason: Cyclohexane generally exists as boat conformers.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because cyclohexane floats on water due to its lower density, but the reason is false because cyclohexane predominantly exists in the chair conformation, not the boat conformation.
134 Easy
134 of 345
Remembering +4 | -1
The isomers observed in alkanes is
View answer and explanation
Correct option: B
Chain isomerism
Option B (Chain isomerism) is correct because alkanes can exhibit chain isomerism due to different arrangements of carbon atoms in the carbon chain.
135 Easy
135 of 345
Understanding +4 | -1
Which of the following species is not electrophilic in nature?
View answer and explanation
Correct option: C
H3O⊕{H_3}\mathop O\limits^ \oplus
The correct answer is C (H3O⊕{H_3}\mathop O\limits^ \oplus) because hydronium ion has a lone pair of electrons and a positive charge, making it a nucleophile rather than an electrophile.

Explore Other Chapters in CHEMISTRY

View All →
P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs
136 Medium
136 of 345
Understanding +4 | -1
In which of the following functional group isomerism is not possible?
View answer and explanation
Correct option: C
Alkyl halides
The correct answer is C (Alkyl halides) because alkyl halides typically do not exhibit functional group isomerism.
137 Easy
137 of 345
Understanding +4 | -1
Lactic acid in which a methyl group, a hydroxyl group, a carboxylic acid group and a hydrogen atom are attached to a central carbon atom shows optical isomerism due to the molecular geometry at the :
View answer and explanation
Correct option: C
Central carbon atom
Option C (Central carbon atom) is correct because the central carbon atom is chiral, meaning it is bonded to four different groups, leading to optical isomerism.
138 Easy
138 of 345
Understanding +4 | -1
Chloroacetic acid is a stronger acid than acetic acid. This can be explained using
View answer and explanation
Correct option: B
−I- I effect
Option B (-I effect) is correct because the chlorine atom in chloroacetic acid has a -I effect, which withdraws electron density and stabilizes the conjugate base, making the acid stronger.
139 Medium
139 of 345
Analyzing +4 | -1
When thiourea is heated with metallic sodium, the compound which can't be formed is
View answer and explanation
Correct option: C
Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}
Option C (Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}) is correct because thiourea contains only N, H, C, and S, so it cannot form a sulfate.
140 Medium
140 of 345
Analyzing +4 | -1
Metal chloride AA is soluble in hot water but insoluble in cold water. Select correct statement about AA thus
View answer and explanation
Correct option: D
All of the above are correct statements
Option D (All of the above are correct statements) is correct because PbCl2 reacts with K2CrO4, K2SO4, and KI to form yellow, white, and yellow precipitates, respectively.
141 Easy
141 of 345
Remembering +4 | -1
In the Grignard reaction, which metal forms an organometallic bond?
View answer and explanation
Correct option: C
Magnesium
Option C (Magnesium) is correct because in the Grignard reaction, magnesium metal reacts with an alkyl halide to form an organometallic bond, creating the Grignard reagent.
142 Easy
142 of 345
Remembering +4 | -1
The group named as benzal possesses ……nature.
View answer and explanation
Correct option: B
Bivalent
Option B (Bivalent) is correct because the benzal group, C6H5CH{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{CH}, has two valencies available for bonding.
143 Easy
143 of 345
Understanding +4 | -1
In which of the following species the central carbon atom is negatively charged?
View answer and explanation
Correct option: B
Carbanion
Option B (Carbanion) is correct because a carbanion is defined as a species where a carbon atom has a negative charge.
144 Medium
144 of 345
Understanding +4 | -1
In Lassaigne's test, the organic compound is fused with a piece of sodium metal in order to
View answer and explanation
Correct option: D
Convert the covalent compound into a mixture of ionic compounds
The correct answer is D (Convert the covalent compound into a mixture of ionic compounds) because fusing the organic compound with sodium converts covalent bonds to ionic bonds, facilitating the detection of elements.
145 Hard
145 of 345
Analyzing +4 | -1
Arrange the following in decreasing order of acidic strength.

(i) Benzoic acid

(ii) 4-nitrobenzoic acid

(iii) 3,4-dinitrobenzoic acid

(iv) 4-methoxy benzoic acid
View answer and explanation
Correct option: A
III >> II >> I >> IV
Option A (III >> II >> I >> IV) is correct because electron-withdrawing groups increase acidity, and electron-donating groups decrease acidity. More nitro groups lead to higher acidity.
146 Easy
146 of 345
Understanding +4 | -1
Ethers are isomeric with
View answer and explanation
Correct option: D
Alcohols
The correct answer is D. Ethers and alcohols have the same general formula (CnH2n+2OC_nH_{2n+2}O) and can be isomers.
147 Medium
147 of 345
Remembering +4 | -1
In paper chromatography:
View answer and explanation
Correct option: A
Mobile phase is liquid and stationary phase is solid
The correct answer is A (Mobile phase is liquid and stationary phase is solid) because in paper chromatography, the mobile phase is a liquid solvent and the stationary phase is the paper itself, which acts as a solid support.
148 Medium
148 of 345
Remembering +4 | -1
In Carius method, halogen containing organic compound is heated with fuming nitric acid in the presence of
View answer and explanation
Correct option: B
AgNO3AgN{O_3}
Option B (AgNO3AgN{O_3}) is correct because in the Carius method, silver nitrate (AgNO3AgNO_3) is used to precipitate the halogen as a silver halide.
149 Easy
149 of 345
Analyzing +4 | -1
Most stable carbanion
View answer and explanation
Correct option: A
C‾H2−CH2−NO2\overline C {H_2} - C{H_2} - N{O_2}
Option A (C‾H2−CH2−NO2\overline C {H_2} - C{H_2} - N{O_2}) is correct because the nitro group (-NO2) is a strong electron-withdrawing group, which stabilizes the carbanion through inductive effect.
150 Medium
150 of 345
Analyzing +4 | -1
Which of the following compound chiral?
View answer and explanation
Correct option: C
DCH2CH2CH2Cl{DCH}_2 {CH}_2{CH}_2 {Cl}
The correct answer is D (CH3CHClCH2D) because it is the only option with a carbon atom bonded to four different groups (H, D, Cl, and CH3).
Revision notes and key takeaways

Review ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES in your textbook or class notes, then use this set to check your understanding.

Showing 121-150 of 345 questions

Continue Your Practice

📚 More Sets in This Chapter

Try different difficulty levels to master this topic

→ ENGINEERING CHEMISTRY - ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES MCQs (Easy) 118 MCQs → ENGINEERING CHEMISTRY - ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES MCQs (Hard) 32 MCQs → ENGINEERING CHEMISTRY - ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES MCQs (Medium) 195 MCQs
🎯 Next Chapters to Practice

Continue building your subject mastery

→ P-BLOCK ELEMENTS 736 MCQs → Equilibrium 696 MCQs → STRUCTURE OF ATOM 634 MCQs → THERMODYNAMICS 536 MCQs

Your practice

0 / 345 answered · 345 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →