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JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 345 questions

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151 Medium
151 of 345
Remembering +4 | -1
Halogens in an organic compound can be detected by:
View answer and explanation
Correct option: B
Carius method
Option B (Carius method) is correct because the Carius method is specifically designed to quantitatively determine the amount of halogens present in an organic compound by converting them to silver halides.
152 Medium
152 of 345
Analyzing +4 | -1
Assertion: The compounds having double bond between carbon atoms always show geometrical isomerism.

Reason: The rotation of groups or atom about carbon-carbon double bond is restricted.
View answer and explanation
Correct option: C
If the assertion is false but the reason is true
The correct answer is C (If the assertion is false but the reason is true) because not all compounds with double bonds show geometrical isomerism, but the restricted rotation is the reason geometrical isomerism can occur.
153 Easy
153 of 345
Remembering +4 | -1
Lassaigne's test is not used for the detection of the element_______in the organic compound
View answer and explanation
Correct option: D
O\mathrm{O}
Option D (O) is correct because Lassaigne's test is specifically designed to detect the presence of nitrogen, sulfur, and halogens (chlorine, bromine, iodine), but not oxygen, in organic compounds.
154 Medium
154 of 345
Remembering +4 | -1
Petroleum refining involves:
View answer and explanation
Correct option: C
Fractional distillation
Option C (Fractional distillation) is correct because petroleum refining uses fractional distillation to separate crude oil into different components based on their boiling points.
155 Easy
155 of 345
Remembering +4 | -1
For esters, prefix used in IUPAC nomenclature is
View answer and explanation
Correct option: D
Alkoxycarbonyl
Option D (Alkoxycarbonyl) is correct because alkoxycarbonyl is the prefix used in IUPAC nomenclature for esters when they are substituents.
156 Hard
156 of 345
Application +4 | -1
0.58 g of hydrocarbon on combustion gave 0.9 g water. The percentage of carbon is about :
View answer and explanation
Correct option: B
82.782.7
Option B (82.782.7) is correct because it is the percentage of carbon calculated from the mass of water produced during combustion.
157 Easy
157 of 345
Analyzing +4 | -1
The correct order of increasing acid strength of the compounds (A) CH3COOH,\mathrm{CH}_3 \mathrm{COOH},
(B) MeOCH2COOH,\mathrm{MeOCH}_2 \mathrm{C O O H}, (C) CF3COOH,\mathrm{CF}_3 \mathrm{COOH}, (D) (CH3)2CHCOOH\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH} is
View answer and explanation
Correct option: C
D << A << B << C
Option C is correct because the electron-withdrawing groups increase acidity, and electron-donating groups decrease acidity, leading to the order D < A < B < C.
158 Hard
158 of 345
Analyzing +4 | -1
An organic compound on heating with CuO produces CO2\mathrm{C}{\mathrm{O}_2} but no water. The organic compound may be
View answer and explanation
Correct option: A
Carbon tetrachloride
The correct answer is A (Carbon tetrachloride) because it contains carbon but no hydrogen, thus producing CO2CO_2 but no water upon heating with CuO.
159 Medium
159 of 345
Analyzing +4 | -1
Statement I: Diffrent number of electron pairs are present in resonance structures.

Statement II: Resonance structures do not differ in the location of electrons around the constituent atoms.
View answer and explanation
Correct option: D
Statement II is correct but statement I is incorrect
The correct answer is D (Statement II is correct but statement I is incorrect) because resonance structures must have the same number of electron pairs, and they differ only in the location of electrons.
160 Easy
160 of 345
Analyzing +4 | -1
Strongest acid among the following
View answer and explanation
Correct option: C
CF3COOHC{F_3}COOH
Option C (CF3COOHC{F_3}COOH) is correct because the presence of three highly electronegative fluorine atoms increases the acidity due to their strong -I effect.
161 Medium
161 of 345
Analyzing +4 | -1
Statement I : CH3−CH∣OH−CH=CH−CH3C{H_3} - \mathop {\mathop {CH}\limits_| }\limits_{OH} - CH = CH - C{H_3} compound has three stereocentres
Statement II : Chiral centres have four different C-atoms
View answer and explanation
Correct option: B
Only Statement II is correct
Only Statement II is correct because chiral centers require four different atoms or groups, and Statement I incorrectly identifies the number of stereocenters.
162 Easy
162 of 345
Understanding +4 | -1
The minimum number of carbon atoms which a ketone may contain is :
View answer and explanation
Correct option: C
3
Option C (3) is correct because a ketone requires a carbonyl group (C=O) bonded to two other carbon atoms, making the smallest ketone acetone (CH3COCH3).
163 Easy
163 of 345
Understanding +4 | -1
CH3−CH|CH3−CHO and CH3−CH2−CH∣CH3−CHO{\text{C}}{{\text{H}}_3} - \mathop {{\text{CH}}}\limits_{\begin{array}{cccccccccccccccccccc} {\text{|}} \\ {{\text{C}}{{\text{H}}_{\text{3}}}} \end{array}} - {\text{CHO and C}}{{\text{H}}_3} - {\text{C}}{{\text{H}}_2} - \mathop {{\text{CH}}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{\text{C}}{{\text{H}}_{\text{3}}}} \end{array}} - {\text{CHO}} are a pair of
View answer and explanation
Correct option: D
Homologues
Option A (Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)) is correct because the dipole moment is directly proportional to the electronegativity difference between the bonded atoms.
164 Easy
164 of 345
Understanding +4 | -1
The structures,

CH3−CH(NH2)−CH2−CH2CH3\mathrm{C}{\mathrm{H}_3}-\mathrm{CH}\left( {\mathrm{N}{\mathrm{H}_2}} \right)-\mathrm{C}{\mathrm{H}_2}-\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3} and

CH3−CH2−CH(NH2)−CH2CH3\mathrm{C}{\mathrm{H}_3}-\mathrm{C}{\mathrm{H}_2}-\mathrm{CH}\left( {\mathrm{N}{\mathrm{H}_2}} \right)-\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3} represent:
View answer and explanation
Correct option: B
Position isomers
Option B (Position isomers) is correct because the position of the amino group (NH2NH_2) is different in the two structures.
165 Medium
165 of 345
Understanding +4 | -1
Which of the following fact(s) explain as to why p-nitrophenol is more acidic than phenol?
i) &ndash;I effect of nitro group
ii) Greater resonance effect of p-nitrophenoxy group
iii) Steric effect of bulky nitro group.
View answer and explanation
Correct option: A
i and ii
The correct answer is A (i and ii) because both the -I effect of the nitro group and resonance effect of p-nitrophenoxide ion contribute to the higher acidity of p-nitrophenol.
166 Medium
166 of 345
Analyzing +4 | -1
Aqueous solution of a salt +MgSO4+{MgSO}_4 solution →\rightarrow no ppt. in cold →Heating\xrightarrow{{{\text{Heating}}}} a white ppt. appears. The salt contains the acidic radical:
View answer and explanation
Correct option: B
HCO3−{HCO}_3^{-}
Option B (HCO3−HCO_3^−) is correct because bicarbonate ions react with MgSO4MgSO_4 upon heating to form a white precipitate of MgCO3MgCO_3.
167 Easy
167 of 345
Remembering +4 | -1
A neutral divalent carbon intermediate produced by the removal of two attached atoms is called :
View answer and explanation
Correct option: D
Carbine
Option D (Carbine) is correct because a carbene is a neutral divalent carbon species with two unshared electrons.
168 Medium
168 of 345
Understanding +4 | -1
Correct IUPAC name of [Ni(en)Br2(PPh3)2]\left[ {Ni(en)B{r_2}{{(PP{h_3})}_2}} \right] is
View answer and explanation
Correct option: C
Dibromido ethylene diamine bis (triphenyl phosphine) nickel (II)
Option C is correct because it accurately names the complex using IUPAC nomenclature, correctly identifying the ligands and oxidation state of the nickel ion.
169 Hard
169 of 345
Understanding +4 | -1
Assertion (A): Components of a mixture of red and blue inks can be separated by distributing the components between stationary and mobile phases in paper chromatography.

Reason (R): The coloured components of inks migrate at different rates because paper selectively retains different components according to the difference in their partition between two phases.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct ; R\mathrm{R} is the correct explanation of AA.
Option A is correct because both the assertion and reason are true, and the reason correctly explains why paper chromatography can separate ink components based on their differential partitioning.
170 Medium
170 of 345
Analyzing +4 | -1
Among the following the most stable compound is:
View answer and explanation
Correct option: D
trans-1,3-cyclohexanediol
Option D (trans-1,3-cyclohexanediol) is correct because trans isomers are generally more stable than cis isomers due to reduced steric hindrance, and 1,3-interactions are less destabilizing than 1,2-interactions.
171 Hard
171 of 345
Analyzing +4 | -1
Increasing order of expected keto content
View answer and explanation
Correct option: C
CH3CHO>CH3COC2H5>CH3COCH3>CH3COCH2COCH3\mathrm{C}{\mathrm{H}_3}\mathrm{CHO} > C{\mathrm{H}_3}\mathrm{CO}{\mathrm{C}_2}{\mathrm{H}_5} > C{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3} > C{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_2}\mathrm{COC}{\mathrm{H}_3}
Option C is correct because it accurately reflects the increasing order of keto content based on the stability of the enol form.
172 Medium
172 of 345
Application +4 | -1
In Dumas&rsquo; method of estimation of nitrogen 0.35 g of an organic compound gave 55mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be: (Aqueous tension at 300 K = 15 mm)
View answer and explanation
Correct option: C
16.45
Option C (16.45) is correct because it accurately calculates the percentage composition of nitrogen in the organic compound using Dumas' method.
173 Easy
173 of 345
Remembering +4 | -1
Which of the following organic compound was synthesised by F\mathrm{F}. Wohler from an inorganic compound?
View answer and explanation
Correct option: B
Urea
Option B (Urea) is correct because Friedrich Wöhler synthesized urea from ammonium cyanate, an inorganic compound.
174 Easy
174 of 345
Remembering +4 | -1
The effect involving the complete transfer of a shared pair of electrons to one of the atoms joined by a multiple bond at the requirement of attacking reagent is called :
View answer and explanation
Correct option: C
Electromeric effect
Option C (Electromeric effect) is correct because the electromeric effect involves the complete transfer of a shared pair of electrons to one of the atoms joined by a multiple bond upon the approach of a reagent.
175 Easy
175 of 345
Remembering +4 | -1
Benedict’s solution provides:
View answer and explanation
Correct option: B
Cu2+\mathrm{C}{\mathrm{u}^{2 + }}
Option B (Cu2+\mathrm{C}{\mathrm{u}^{2 + }}) is correct because Benedict's solution contains copper(II) ions (Cu2+), which are responsible for the color change when reducing sugars are present.
176 Easy
176 of 345
Understanding +4 | -1
In which of the following ways does the hydride ion tend to function?
View answer and explanation
Correct option: B
A nucleophile
Option B (A nucleophile) is correct because the hydride ion (H-) has a lone pair of electrons and donates them to electron-deficient species.
177 Easy
177 of 345
Application +4 | -1
The IUPAC name of the compound having the formulaCH≡  C  −  CH=CH2\mathrm{CH} \equiv \mathrm{\;C\;}-\mathrm{\;CH} = \mathrm{C}{\mathrm{H}_2} is :
View answer and explanation
Correct option: A
1-butene-3-yne
Option A (1-butene-3-yne) is correct because it follows the IUPAC naming rules, prioritizing the double bond and numbering the carbon chain to give the lowest possible numbers to the multiple bonds.
178 Medium
178 of 345
Understanding +4 | -1
In sulphur detection of an organic compound, sodium nitroprusside solution is added to sodium extract.
Formation of violet colour is due to
View answer and explanation
Correct option: B
Na3[Fe(CN)5NOS]\mathrm{N}{\mathrm{a}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NOS}} \right]
Option B (Na3[Fe(CN)5NOS]\mathrm{N}{\mathrm{a}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NOS}} \right]) is correct because the violet color observed in the Lassaigne's test for sulfur is due to the formation of sodium pentacyanonitrosylferrate(III).
179 Medium
179 of 345
Remembering +4 | -1
Which of the following metal sulphite is white
colour?
View answer and explanation
Correct option: C
ZnS{ZnS}
Option C (ZnS{ZnS}) is correct because Zinc Sulfide is known to have a white color.
180 Easy
180 of 345
Remembering +4 | -1
Electromeric effect is a
View answer and explanation
Correct option: B
Temporary effect
Option B (Temporary effect) is correct because the electromeric effect occurs only in the presence of an attacking reagent and disappears when the reagent is removed.
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