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JEE • CHEMISTRY • HYDROGEN

Hydrogen practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-179 of 179 questions
151 Easy
151 of 179
Application +4 | -1
The weight percentage of deuterium in heavy water is:
View answer and explanation
Correct option: D
20
Option D (20) is correct because the weight percentage of deuterium in heavy water (D2O) is calculated based on the molar mass ratio.
152 Easy
152 of 179
Remembering +4 | -1
The method used to remove temporary hardness of water is:
View answer and explanation
Correct option: B
Clark’s method
Option B (Clark’s method) is correct because Clark's method is specifically used for removing temporary hardness of water by reacting bicarbonates with slaked lime.
153 Easy
153 of 179
Understanding +4 | -1
Hydrogen peroxide does not:
View answer and explanation
Correct option: C
Give silver peroxide with moist silver oxide
Option C (Give silver peroxide with moist silver oxide) is correct because hydrogen peroxide does not react with moist silver oxide to give silver peroxide.
154 Medium
154 of 179
Understanding +4 | -1
Determine the total number of neutrons in three isotopes of Hydrogen
View answer and explanation
Correct option: C
3
Option C (3) is correct because the total number of neutrons in protium (0), deuterium (1), and tritium (2) is 0 + 1 + 2 = 3.
155 Medium
155 of 179
Remembering +4 | -1
The gas produced by the passage of air over hot coke is
View answer and explanation
Correct option: C
Producer gas
Option C (Producer gas) is correct because producer gas is formed by passing air over hot coke, resulting in a mixture of carbon monoxide and nitrogen.
156 Medium
156 of 179
Application +4 | -1
The label on a bottle of H2O2{H}_2 {O}_2 solution reads as ' 10 volume'. The concentration of H2O2{H}_2 {O}_2 in percentage by volume is
View answer and explanation
Correct option: B
3.03%3.03 \%
Option B (3.03%3.03 \%) is correct because '10 volume' means 1 mL of H2O2 gives 10 mL of O2 at STP, and the calculation converts this to a percentage by volume.
157 Easy
157 of 179
Remembering +4 | -1
Which hydride is neutral?
View answer and explanation
Correct option: B
H2O{\mathrm{H}_2}\mathrm{O}
Option B (H2O{\mathrm{H}_2}\mathrm{O}) is correct because water (H2O{\mathrm{H}_2}\mathrm{O}) is a neutral hydride with a pH of 7.
158 Medium
158 of 179
Remembering +4 | -1
Zeolites are extensively used in:
View answer and explanation
Correct option: A
Softening of water and catalyst
Option A (Softening of water and catalyst) is correct because zeolites are used for water softening and as catalysts in various industrial processes.
159 Easy
159 of 179
Remembering +4 | -1
In the preparation of hydrogenated oil the chemical reaction involving hydrogen is called:
View answer and explanation
Correct option: A
Hydrogenation
Option A (Hydrogenation) is correct because the addition of hydrogen to unsaturated fats to produce hydrogenated oil is specifically called hydrogenation.
160 Hard
160 of 179
Application +4 | -1
The hardness of a water sample (in terms of equivalents of CaCO3)CaC{O_3}) containing 10−3M CaSO4{10^{ - 3}}M\,CaS{O_4} (Molar mass of CaSO4=136  g  mol−1)CaS{O_4} = 136\,\,g\,\,mo{l^{ - 1}})
View answer and explanation
Correct option: A
100 ppm
Option A (100 ppm) is correct because the hardness is calculated based on the molarity of CaSO4CaSO_4 and expressed as ppm of CaCO3CaCO_3.
161 Easy
161 of 179
Remembering +4 | -1
In Bosch’s process which gas is utilised for the production of hydrogen gas?
View answer and explanation
Correct option: B
Water gas
Option B (Water gas) is correct because the Bosch process uses water gas (CO + H₂) to produce hydrogen gas.
162 Medium
162 of 179
Analyzing +4 | -1
Following are some properties of hydrogen. Which of the following properties resemble with alkali metals and which with halogens

(i) Hydrogen lose one electron to form unipositive ions

(ii) Hydrogen gain one electron to form uninegative ions

(iii) Hydrogen forms oxides, halides and sulphides

(iv) Hydrogen has a very high ionization enthalpy

(v) Hydrogen forms a diatomic molecule, combines with elements to form hydrides and covalent compounds.
View answer and explanation
Correct option: C
Alkali metals resemble (i) and (iii)
Halogens resemble (ii), (iv) and (v)
The correct answer is B because alkali metals lose electrons and form oxides, while halogens gain electrons, form halides, and exist as diatomic molecules.
163 Medium
163 of 179
Understanding +4 | -1
LiAlH4LiAl{H_4} Is widely used a reducing agent. In this hydride AlAl is present in:
View answer and explanation
Correct option: B
Anionic part
Option B (Anionic part) is correct because in LiAlH4LiAl{H_4}, the aluminum is part of the AlH4−Al{H_4}^- anion.
164 Easy
164 of 179
Understanding +4 | -1
In one of these compounds does hydrogen have an oxidation state of −1- 1
View answer and explanation
Correct option: D
CaH2Ca{H_2}
Option D (CaH2Ca{H_2}) is correct because in metal hydrides like calcium hydride, hydrogen has an oxidation state of -1.
165 Easy
165 of 179
Remembering +4 | -1
Water is said to be permanently hard when it contains:
View answer and explanation
Correct option: A
Chlorides of Ca   and   MgCa\,\,\,{\text{and}}\,\,\,Mg
Option A (Chlorides of CaCa and MgMg) is the correct answer because permanent hardness in water is caused by the presence of chlorides and sulfates of calcium and magnesium.
166 Medium
166 of 179
Analyzing +4 | -1
Assertion: The volume strength of a solution of hydrogen peroxide decreases with an increase in the hardness of the water.

Reason: The hardness of water is caused by the presence of ions of calcium and magnesium. These ions react with hydrogen peroxide and reduce its volume strength.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation for Assertion
Option D is correct because azeotropic mixtures boil at a constant temperature and retain their composition upon distillation.
167 Medium
167 of 179
Analyzing +4 | -1
Assertion (A) : On passing H2\mathrm{H}_2 gas into aqueous Fe3+\mathrm{Fe}^{3+} solution, resulting solution gives test of Fe3+\mathrm{Fe}^{3+}.

Reason (R): H2(g)\mathrm{H}_2(g) reduces Fe3+\mathrm{Fe}^{3+} to Fe2+\mathrm{Fe}^{2+} but Fe2+\mathrm{Fe}^{2+} is oxidised to Fe3+\mathrm{Fe}^{3+} by atmospheric oxygen.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option C (A is true, R is false) is correct because while the initial solution might contain Fe3+, the H2 gas reduces it to Fe2+, and the atmospheric oxidation to Fe3+ is too slow to be noticeable in a typical test.
168 Medium
168 of 179
Remembering +4 | -1
The synonym for water gas when used in the production of methanol is
View answer and explanation
Correct option: C
syn gas
Option C (syn gas) is correct because "syn gas" is the synonym for water gas when used in the production of methanol.
169 Medium
169 of 179
Understanding +4 | -1
Which of the following equation depicts the oxidising nature of H2O2{H_2}{O_2} ?
View answer and explanation
Correct option: C
2I−+H2O2+2H+→I2+2H2O2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O
Option C (2I−+H2O2+2H+→I2+2H2O2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O) is correct because in this reaction, H2O2 oxidizes I- to I2, demonstrating its oxidizing nature.
170 Medium
170 of 179
Understanding +4 | -1
The product obtained in the given reaction is

CaC2+D2O⟶{CaC}_2+{D}_2{O} \longrightarrow
View answer and explanation
Correct option: A
C2D2{C}_2{D}_2
The correct answer is A (C2D2{C}_2{D}_2) because calcium carbide reacts with heavy water to produce ethyne with deuterium.
171 Medium
171 of 179
Remembering +4 | -1
Radioactive elements emit α,β\alpha, \beta and γ\gamma rays and are characterized by their half-lives. The radioactive isotope of hydrogen is
View answer and explanation
Correct option: C
Tritium
Option C (Tritium) is correct because Tritium is the only radioactive isotope of hydrogen.
172 Easy
172 of 179
Remembering +4 | -1
The number of radioactive isotopes of hydrogen is:
View answer and explanation
Correct option: A
1
Option A (1) is correct because only tritium (3H^3H) is a radioactive isotope of hydrogen.
173 Medium
173 of 179
Remembering +4 | -1
H2O2\mathrm{H}_2 \mathrm{O}_2 and heavy water was discovered by respectively:-
View answer and explanation
Correct option: A
Thenard, Urey
Option A (Thenard, Urey) is correct because H2O2\mathrm{H}_2 \mathrm{O}_2 was discovered by Thenard, and heavy water was discovered by Urey.
174 Medium
174 of 179
Understanding +4 | -1
(A):CO from syn gas can be converted to CO2\mathrm{CO}_2 by reacting with steam in the presence of FeCrO4⋅673 K\mathrm{FeCrO}_4 \cdot 673 \mathrm{~K} or Fe2O3/Cr2O3/673 K\mathrm{Fe}_2 \mathrm{O}_3 / \mathrm{Cr}_2 \mathrm{O}_3 / 673 \mathrm{~K}.

(R): The conversion of CO\mathrm{CO} to CO2\mathrm{CO}_2 using steam is called water gas shift
View answer and explanation
Correct option: A
Both (A)(A) and (R)(R) are true and (R)(R) is the correct explnation of (A)(A)
Option A is correct because the conversion of CO to CO2 using steam is indeed called the water gas shift reaction, and this reaction is used to convert CO from syn gas.
175 Medium
175 of 179
Understanding +4 | -1
The bond energy of covalent O—H bond in water is:
View answer and explanation
Correct option: B
Greater than bond energy of hydrogen bond
Option B is correct because covalent bonds are significantly stronger than hydrogen bonds due to electron sharing.
176 Medium
176 of 179
Remembering +4 | -1
Permanent hardness of water can be removed by
View answer and explanation
Correct option: D
Treatment with sodium hexametaphosphate (Na6P6O18)\left(\mathrm{Na}_6 \mathrm{P}_6 \mathrm{O}_{18}\right)
Option D (Treatment with sodium hexametaphosphate (Na6P6O18)(\mathrm{Na}_6 \mathrm{P}_6 \mathrm{O}_{18})) is correct because this method sequesters the calcium and magnesium ions responsible for hardness.
177 Easy
177 of 179
Remembering +4 | -1
Which one of the following is used for reviving the
exhausted permutit?
View answer and explanation
Correct option: D
10% NaCl10 \% \mathrm{~NaCl} solution
Option D (10% NaCl10 \% \mathrm{~NaCl} solution) is correct because sodium chloride solution is used to regenerate exhausted permutit.
178 Easy
178 of 179
Remembering +4 | -1
D2O\mathrm{D}_{2} \mathrm{O} is used more in
View answer and explanation
Correct option: A
Nuclear reactor
Option A (Nuclear reactor) is correct because deuterium oxide (D2O) is commonly used as a moderator in nuclear reactors to slow down neutrons.
179 Medium
179 of 179
Remembering +4 | -1
Most common isotopes of hydrogen (non-radioactive) is
View answer and explanation
Correct option: A
Protium
Option A (Protium) is correct because Protium (11H^1_1H) is the most common and non-radioactive isotope of hydrogen.
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