$10\% \,\left( {W/V} \right){H_2}{O_2}$

$3\% \,\left( {W/V} \right){H_2}{O_2}$

$100\% \,\left( {W/V} \right){H_2}{O_2}$

more or less identical in polarity with $\mathrm{H}_2 \mathrm{S}$

less polar than $\mathrm{H}_2 \mathrm{S}$

Decolourisation of acidified potassium permanganate occurs when ${{\rm{H}}_2}{{\rm{O}}_2}$ is added to it. This is due to:

Reduction of ${\rm{KMn}}{{\rm{O}}_4}$

Oxidation of ${\rm{KMn}}{{\rm{O}}_4}$

Both oxidation and reduction of ${\rm{KMn}}{{\rm{O}}_4}$

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JEE • CHEMISTRY • HYDROGEN

Hydrogen practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 94 questions

1 Medium

1 of 94

Remembering +4 | -1

Hydrogen is prepared on large scale for industrial use

View answer and explanation

Correct option: D

From water gas

Option D (From water gas) is correct because hydrogen is industrially produced on a large scale from water gas through processes like the Bosch process.

2 Medium

2 of 94

Understanding +4 | -1

10 volumes of

{H_2}{O_2}

has a strength of

View answer and explanation

Correct option: A

0.03

Option B (0.3) is correct because the percentage strength is calculated by dividing 17 by 56 and multiplying by the volume strength, which gives approximately 0.3.

3 Medium

3 of 94

Analyzing +4 | -1

The pH of a solution of

{\mathrm{H}_2}{\mathrm{O}_2}

is 6.0. Some chloride gas is bubbled into this solution. Which of the following is correct?

View answer and explanation

Correct option: C

The pH of resultant solution becomes less than 6.0 and oxygen gas is liberated

Option C (The pH of resultant solution becomes less than 6.0 and oxygen gas is liberated) is correct because the reaction between H2O2 and Cl2 produces HCl, which lowers the pH, and O2.

4 Medium

4 of 94

Analyzing +4 | -1

The pair that yields the same gaseous product on reaction with water:

View answer and explanation

Correct option: B

\mathrm{Ca}\;\mathrm{ and}\;\mathrm{Ca}{\mathrm{H}_2}

Option B is correct because both Calcium (Ca) and Calcium Hydride (CaH₂) react with water to produce Calcium Hydroxide (Ca(OH)₂) and Hydrogen gas (H₂).

5 Medium

5 of 94

Understanding +4 | -1

S-I: The unsaturated fat (oils) are changed to saturated fat by

{H}_2

in presence of finely divided

{Ni}

.

S-II:

{H}_2

Shows addition around doubly bonded carbon atoms.

View answer and explanation

Correct option: A

Both S-I and S-II are correct

Option A (Both S-I and S-II are correct) is correct because unsaturated fats are indeed hydrogenated to saturated fats using Ni as a catalyst, and the hydrogenation occurs at the double bonds.

6 Medium

6 of 94

Remembering +4 | -1

Perhydrol is

View answer and explanation

Correct option: B

30\% \,\left( {W/V} \right){H_2}{O_2}

Option B (

30\% \,\left( {W/V} \right){H_2}{O_2}

) is correct because Perhydrol is a

30\% \,\left( {W/V} \right)

solution of hydrogen peroxide (

H_2O_2

7 Medium

7 of 94

Remembering +4 | -1

Commercial 10 volume

\mathrm{H}_2 \mathrm{O}_2

is a solution with a strength of approximately

View answer and explanation

Correct option: B

3 \%

Option B (

3 \%

) is correct because commercial 10 volume

\mathrm{H}_2 \mathrm{O}_2

solution has a strength of approximately 3%.

8 Medium

8 of 94

Understanding +4 | -1

S-I:

{H}_2 {O}_2

has higher boiling point than water

S-II:

{H}_2 {O}_2

has stronger hydrogen bonding interactions than that shown by water

View answer and explanation

Correct option: A

Both S-I and S-II are correct

The correct answer is A (Both S-I and S-II are correct) because hydrogen peroxide has a higher boiling point than water due to stronger hydrogen bonding interactions.

9 Medium

9 of 94

Understanding +4 | -1

When different metals like

Zn,\mathrm{ }Sn,\mathrm{ }Fe

are added to dilute sulphuric acid, same gas, which burns explosively in air, is evolved. The gas is:

View answer and explanation

Correct option: D

{\mathrm{H}_2}

Option D (

{\mathrm{H}_2}

) is correct because all the metals listed react with dilute sulfuric acid to produce hydrogen gas, which is known to burn explosively in air.

10 Medium

10 of 94

Understanding +4 | -1

Metal which does not react with cold water but evolves

{H_2}

with steam is:

View answer and explanation

Correct option: D

Fe

Option D (

Fe

) is correct because iron does not react with cold water but reacts with steam to produce hydrogen gas.

11 Medium

11 of 94

Remembering +4 | -1

\mathrm{LiAlH}_4

is used as :

View answer and explanation

Correct option: B

A reducing agent

Option B (A reducing agent) is correct because LiAlH4 is a strong reducing agent commonly used in organic chemistry.

12 Medium

12 of 94

Understanding +4 | -1

Which of the following statements in relation to the hydrogen atom is correct?

View answer and explanation

Correct option: A

3 \mathrm{~s}, 3 \mathrm{p}

and

3 \mathrm{~d}

orbitals all have the same energy

Option A (

3 \mathrm{~s}, 3 \mathrm{p}

and

3 \mathrm{~d}

orbitals all have the same energy) is correct because in a hydrogen atom, the energy of an orbital depends only on the principal quantum number (n).

13 Medium

13 of 94

Analyzing +4 | -1

In which of the following reactions does hydrogen act as an oxidising agent:-

View answer and explanation

Correct option: C

\mathrm{Na}+\mathrm{H}_2 \longrightarrow

Option C is correct because in the reaction with Na, hydrogen gains an electron and its oxidation state changes from 0 to -1, thus acting as an oxidizing agent.

14 Medium

14 of 94

Remembering +4 | -1

In solid hydrogen the intermolecular bonding is

View answer and explanation

Correct option: B

Vander waals

Option B (Vander waals) is correct because solid hydrogen molecules are held together by weak van der Waals forces.

15 Medium

15 of 94

Remembering +4 | -1

One of the electrolyte used for the manufacture of

{H_2}{O_2}

by electrolytic method

View answer and explanation

Correct option: C

50\% \,{H_2}S{O_4}

Option C (

50\% \,{H_2}S{O_4}

) is correct because the electrolysis of 50% sulfuric acid is a method used for the manufacture of hydrogen peroxide.

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16 Medium

16 of 94

Remembering +4 | -1

The chemical formula of zeolite is

View answer and explanation

Correct option: C

N{a_2}A{l_2}S{i_2}{O_8}x{H_2}O

Option C (

N{a_2}A{l_2}S{i_2}{O_8}x{H_2}O

) is correct because it represents the general formula for zeolites, which are hydrated aluminosilicates of alkali or alkaline earth metals.

17 Medium

17 of 94

Analyzing +4 | -1

The correct statements among (1) to (4) are:
1. Saline hydrides produce

{H_2}

gas when reacted with

{H_2}O

2) Reaction of

LiAl{H_4}

with

B{F_3}

leads to

{B_2}{H_6}

P{H_3}

and

C{H_4}

are electron rich and electron precise hydrides, respectively
4)

HF\mathrm{ }

and

C{H_4}

are called as molecular hydrides

View answer and explanation

Correct option: A

(1), (2), (3) and (4)

Option A is correct because all four statements about hydrides are accurate and well-established chemical facts.

18 Medium

18 of 94

Remembering +4 | -1

Which one of the following chemical agent is not being used for dry cleaning of clothes?

View answer and explanation

Correct option: B

CC{l_4}

Option B (

CC{l_4}

) is correct because carbon tetrachloride (

CC{l_4}

) is no longer used for dry cleaning due to its toxicity and corrosive properties; other options are used.

19 Medium

19 of 94

Understanding +4 | -1

Water is :

View answer and explanation

Correct option: A

more polar than

\mathrm{H}_2 \mathrm{S}

Option A (more polar than

\mathrm{H}_2 \mathrm{S}

) is correct because oxygen is more electronegative than sulfur, leading to a greater dipole moment in water.

20 Medium

20 of 94

Understanding +4 | -1

Statements about heavy water are given below.
A. Heavy water is used in exchange reactions for the study of reaction mechanisms.
B. Heavy water is prepared by exhaustive electrolysis of water
C. Heavy water has higher boiling point than ordinary water.
D. Viscosity of

{H_2}O

is greater than

{D_2}O

.
which

oc

the given statement are correct

View answer and explanation

Correct option: A

A, B and C

The correct answer is A, B and C because statements A, B, and C about heavy water are accurate, while statement D is incorrect.

21 Medium

21 of 94

Understanding +4 | -1

In alkaline medium,

{H_2}{O_2}

reacts with

F{e^{ + 3}}

and

M{n^{ + 2}}

respectively to give

View answer and explanation

Correct option: C

F{e^{ + 2}}\mathrm{ and }M{n^{ + 4}}

Option C (

F{e^{ + 2}}\mathrm{ and }M{n^{ + 4}}

) is correct because

{H_2}{O_2}

reduces

F{e^{ + 3}}

F{e^{ + 2}}

and oxidizes

M{n^{ + 2}}

M{n^{ + 4}}

22 Medium

22 of 94

Understanding +4 | -1

The number of Hydrogen bonded water molecules associated with

CuS{O_4}.5{H_2}O

View answer and explanation

Correct option: B

Option B (1) is correct because only one water molecule in

CuSO_4.5H_2O

is directly hydrogen-bonded.

23 Medium

23 of 94

Understanding +4 | -1

Given below are two statements
Statement I:

\mathrm{H}_{2} \mathrm{O}_{2}

is used in the synthesis of Cephalosporin
Statement II:

\mathrm{H}_{2} \mathrm{O}_{2}

is used for the restoration of aerobic conditions to sewage wastes.
In the light of the above statements, choose the most appropriate answer from the options given below

View answer and explanation

Correct option: D

Both Statement I and Statement II are correct

Option D (Both Statement I and Statement II are correct) is correct because hydrogen peroxide is used in the synthesis of Cephalosporin and for restoring aerobic conditions to sewage wastes.

24 Medium

24 of 94

Understanding +4 | -1

{\mathrm{H}_2}{\mathrm{O}_2}

reduces

{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

in:

View answer and explanation

Correct option: C

Alkaline solution

Option C (Alkaline solution) is correct because

{\mathrm{H}_2}{\mathrm{O}_2}

reduces

{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

to potassium ferrocyanide in alkaline medium.

25 Medium

25 of 94

Remembering +4 | -1

{K_\mathrm{a}}\;\mathrm{for}\;{\mathrm{H}_2}{\mathrm{O}_2}

is of the order of:

View answer and explanation

Correct option: A

{10^{ - 12}}

Option A (

{10^{ - 12}}

) is correct because the acid dissociation constant (

{K_\mathrm{a}}

) for

{\mathrm{H}_2}{\mathrm{O}_2}

is approximately

{10^{ - 12}}

26 Medium

26 of 94

Analyzing +4 | -1

Assertion : We feel cold on touching the ice.

Reason : Ice is a solid form of water.

View answer and explanation

Correct option: B

If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.

Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.) is correct because the assertion is true, and the reason is also true, but the reason does not explain the assertion.

27 Medium

27 of 94

Understanding +4 | -1

Heavy water is not used for dinking because:

View answer and explanation

Correct option: C

Its physiological action is different from ordinary water

Option C is correct because heavy water's physiological action differs from ordinary water, affecting biological processes.

28 Medium

28 of 94

Understanding +4 | -1

Hydrogen peroxide when added to a solution of potassium permanganate acidified with sulphuric acid

View answer and explanation

Correct option: C

Acts as a reducing agent

The correct answer is C (Acts as a reducing agent) because hydrogen peroxide reduces potassium permanganate in acidic medium, itself getting oxidized to oxygen.

29 Medium

29 of 94

Understanding +4 | -1

Decolourisation of acidified potassium permanganate occurs when

{\mathrm{H}_2}{\mathrm{O}_2}

is added to it. This is due to:

View answer and explanation

Correct option: B

Reduction of

\mathrm{KMn}{\mathrm{O}_4}

Option B is correct.

{H_2}{O_2}

reduces

KMnO_4

because it acts as a reducing agent, causing the decolourisation.

Mn^{7+}

is reduced to

Mn^{2+}

30 Medium

30 of 94

Application +4 | -1

The molarity of 20 volume

{H_2}{O_2}

is nearly

View answer and explanation

Correct option: D

1.8

Option D (1.8) is correct because the molarity of

H_2O_2

is calculated using the formula: Molarity = Volume Strength / 11.2.

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 94 single-correct-answer MCQs on HYDROGEN.
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