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JEE • CHEMISTRY • HYDROGEN

Hydrogen practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard

1 of 9

Application +4 | -1

The molecular formula of a commercial resin used for exchanging ions in water softening is

{C_8}{H_7}S{O_3}Na

(mol. wt. = 206). What would be the maximum uptake of

C{a^{2 + }}

ions by the resin when expressed in mole per gram resin?

View answer and explanation

Correct option: D

\frac{2}{{412}}

Option D (2/412) is correct because the maximum uptake of Ca²⁺ ions by the resin is calculated based on the stoichiometry of the ion exchange reaction.

2 Hard

2 of 9

Application +4 | -1

A sample of hard water containing

{Ca}^{2+}(\mathrm{aq})

ions, having concentration

400 \, \mathrm{ppm}

is passed through cation exchange resin

({RH})

which exchanges

{Ca}^{2+}(\mathrm{aq})

ions for

{H}^{+}(\mathrm{aq})

. What is the volume of

1 \, \mathrm{M}

{NaOH}

required to neutralise

1 \mathrm{~L}

of water obtained from cation exchange resin after exchange of

{Ca}^{2+}

of hard water?

View answer and explanation

Correct option: A

20 \mathrm{~mL}

Option A (20 mL) is correct because the volume of NaOH required is calculated based on the concentration of Ca2+ ions and the stoichiometry of the neutralization reaction.

3 Hard

3 of 9

Application +4 | -1

The volume strength of

1.5N\,{H_2}{O_2}

solution is

View answer and explanation

Correct option: B

8.4

Option B (8.4) is correct because volume strength is calculated by multiplying normality by 5.6.

4 Hard

4 of 9

Application +4 | -1

The percentage by weight of hydrogen in

{\mathrm{H}_2}{\mathrm{O}_2}

is:

View answer and explanation

Correct option: A

5.88

Option A (5.88) is correct because the percentage by weight of hydrogen in H2O2 is calculated by dividing the total weight of hydrogen atoms by the molecular weight of H2O2 and multiplying by 100.

5 Hard

5 of 9

Analyzing +4 | -1

In which of the following reactions,

\mathrm{H}_2 \mathrm{O}_2

does not act as reductant?

View answer and explanation

Correct option: A

2 \mathrm{KBr}+\mathrm{H}_2 \mathrm{O}_2 \longrightarrow \mathrm{Br}_2+2 \mathrm{KOH}

Option A (

2 \mathrm{KBr}+\mathrm{H}_2 \mathrm{O}_2 \longrightarrow \mathrm{Br}_2+2 \mathrm{KOH}

) is correct because in this reaction,

\mathrm{H}_2 \mathrm{O}_2

acts as an oxidizing agent, not a reducing agent.

6 Hard

6 of 9

Application +4 | -1

The molecular formula of a commercial resin used for exchanging ions in water softening is

{C_8}{H_7}S{O_3}Na

(mol. wt. = 206). What would be the maximum uptake of

C{a^{2 + }}

ions by the resin when expressed in mole per gram resin?

View answer and explanation

Correct option: D

\frac{2}{{412}}

Option D (2/412) is correct because the maximum uptake of Ca²⁺ ions by the resin is calculated based on the stoichiometry of the ion exchange reaction.

7 Hard

7 of 9

Remembering +4 | -1

In industrial method,

1 \% \mathrm{~H}_2 \mathrm{O}_2

is obtained by auto oxidation of 2-ethyl anthraquinol.

1 \% \mathrm{~H}_2 \mathrm{O}_2

so formed is extracted with

View answer and explanation

Correct option: A

\mathrm{H}_2 \mathrm{O}

The correct answer is A (

\mathrm{H}_2 \mathrm{O}

) because the

1 \% \mathrm{H}_2 \mathrm{O}_2

formed by auto-oxidation of 2-ethyl anthraquinol is extracted with water.

8 Hard

8 of 9

Analyzing +4 | -1

Assertion (A) : On adding zinc pieces to

{FeCl}_3(a q)

solution, colour changes from deep yellow to light green.

Reason (R) : Aqueous

{FeCl}_3

solution is acidic and on adding zinc, nascent hydrogen is produced which reduces deep yellow

m{FeCl}_3

solution to light green

{FeCl}_2

solution.

View answer and explanation

Correct option: A

Both

\mathbf{A}

and

\mathbf{R}

are true and

\mathbf{R}

is the correct explanation of

\mathbf{A}

The correct answer is A (Both A and R are true and R is the correct explanation of A) because zinc reduces

FeCl_3

FeCl_2

, causing the color change, and the nascent hydrogen produced facilitates this reduction.

9 Hard

9 of 9

Application +4 | -1

The hardness of a water sample (in terms of equivalents of

CaC{O_3})

containing

{10^{ - 3}}M\,CaS{O_4}

(Molar mass of

CaS{O_4} = 136\,\,g\,\,mo{l^{ - 1}})

View answer and explanation

Correct option: A

100 ppm

Option A (100 ppm) is correct because the hardness is calculated based on the molarity of

CaSO_4

and expressed as ppm of

CaCO_3

Revision notes and key takeaways

Review HYDROGEN in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 9 single-correct-answer MCQs on HYDROGEN.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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