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JEE • CHEMISTRY • HYDROGEN

Hydrogen practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 179 questions
31 Medium
31 of 179
Understanding +4 | -1
Water is :
View answer and explanation
Correct option: A
more polar than H2S\mathrm{H}_2 \mathrm{S}
Option A (more polar than H2S\mathrm{H}_2 \mathrm{S}) is correct because oxygen is more electronegative than sulfur, leading to a greater dipole moment in water.
32 Easy
32 of 179
Remembering +4 | -1
The bleaching properties of H2O2{\mathrm{H}_2}{\mathrm{O}_2} are due to its:
View answer and explanation
Correct option: B
Oxidizing properties
Option B (Oxidizing properties) is correct because hydrogen peroxide acts as a bleaching agent due to its ability to oxidize colored substances.
33 Easy
33 of 179
Remembering +4 | -1
The exhausted Permutit is generally regenerated by percolating through it a solution of:
View answer and explanation
Correct option: A
Sodium chloride
Option A (Sodium chloride) is correct because sodium chloride solution is used to regenerate exhausted Permutit by replacing calcium and magnesium ions with sodium ions.
34 Medium
34 of 179
Understanding +4 | -1
Statements about heavy water are given below.
A. Heavy water is used in exchange reactions for the study of reaction mechanisms.
B. Heavy water is prepared by exhaustive electrolysis of water
C. Heavy water has higher boiling point than ordinary water.
D. Viscosity of H2O{H_2}O is greater than D2O{D_2}O.
which ococ the given statement are correct
View answer and explanation
Correct option: A
A, B and C
The correct answer is A, B and C because statements A, B, and C about heavy water are accurate, while statement D is incorrect.
35 Easy
35 of 179
Understanding +4 | -1
10 Volume H2O2{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}} means
View answer and explanation
Correct option: A
1 ml H2O21\,ml\,{H_2}{O_2} gives 10 ml O210\,ml\,{O_2} at NTP
Option A (1 ml H2O21\,ml\,{H_2}{O_2} gives 10 ml O210\,ml\,{O_2} at NTP) is correct because it accurately defines the volume strength of hydrogen peroxide.
36 Medium
36 of 179
Understanding +4 | -1
In alkaline medium, H2O2{H_2}{O_2} reacts with Fe+3F{e^{ + 3}} and Mn+2M{n^{ + 2}} respectively to give
View answer and explanation
Correct option: C
Fe+2andMn+4F{e^{ + 2}}\mathrm{ and }M{n^{ + 4}}
Option C (Fe+2andMn+4F{e^{ + 2}}\mathrm{ and }M{n^{ + 4}}) is correct because H2O2{H_2}{O_2} reduces Fe+3F{e^{ + 3}} to Fe+2F{e^{ + 2}} and oxidizes Mn+2M{n^{ + 2}} to Mn+4M{n^{ + 4}}.
37 Easy
37 of 179
Remembering +4 | -1
Tritium is obtained by:
View answer and explanation
Correct option: A
Nuclear reactions
Option A (Nuclear reactions) is correct because Tritium is a radioactive isotope of hydrogen produced through nuclear reactions.
38 Medium
38 of 179
Understanding +4 | -1
The number of Hydrogen bonded water molecules associated with CuSO4.5H2OCuS{O_4}.5{H_2}O is
View answer and explanation
Correct option: B
1
Option B (1) is correct because only one water molecule in CuSO4.5H2OCuSO_4.5H_2O is directly hydrogen-bonded.
39 Medium
39 of 179
Understanding +4 | -1
Given below are two statements
Statement I: H2O2\mathrm{H}_{2} \mathrm{O}_{2} is used in the synthesis of Cephalosporin
Statement II: H2O2\mathrm{H}_{2} \mathrm{O}_{2} is used for the restoration of aerobic conditions to sewage wastes.
In the light of the above statements, choose the most appropriate answer from the options given below
View answer and explanation
Correct option: D
Both Statement I and Statement II are correct
Option D (Both Statement I and Statement II are correct) is correct because hydrogen peroxide is used in the synthesis of Cephalosporin and for restoring aerobic conditions to sewage wastes.
40 Hard
40 of 179
Application +4 | -1
The volume strength of 1.5N H2O21.5N\,{H_2}{O_2} solution is
View answer and explanation
Correct option: B
8.4
Option B (8.4) is correct because volume strength is calculated by multiplying normality by 5.6.
41 Hard
41 of 179
Application +4 | -1
The percentage by weight of hydrogen in H2O2{\mathrm{H}_2}{\mathrm{O}_2} is:
View answer and explanation
Correct option: A
5.88
Option A (5.88) is correct because the percentage by weight of hydrogen in H2O2 is calculated by dividing the total weight of hydrogen atoms by the molecular weight of H2O2 and multiplying by 100.
42 Medium
42 of 179
Understanding +4 | -1
H2O2{\mathrm{H}_2}{\mathrm{O}_2} reduces K3Fe(CN)6{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} in:
View answer and explanation
Correct option: C
Alkaline solution
Option C (Alkaline solution) is correct because H2O2{\mathrm{H}_2}{\mathrm{O}_2} reduces K3Fe(CN)6{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} to potassium ferrocyanide in alkaline medium.
43 Easy
43 of 179
Application +4 | -1
Given

(A) 2CO(g)+O2( g)→2CO2( g)ΔH1θ=−xkJmol−12 \mathrm{CO}(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{CO}_2(\mathrm{~g}) \quad \Delta \mathrm{H}_1^\theta=-\mathrm{xkJ} \mathrm{mol}^{-1}

(B) C\mathrm{C} (graphite )+O2( g)→CO2( g)ΔH2θ=−ykmol−1)+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g}) \quad \Delta \mathrm{H}_2^\theta=-\mathrm{ykmol}^{-1}

The ΔHθ\Delta \mathrm{H}^\theta for the reaction

C(\mathrm{C}( graphite )+12O2( g)→CO(g))+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}(\mathrm{g}) is
View answer and explanation
Correct option: C
x−2y2\frac{x-2 y}{2}
Option C (x−2y2\frac{x-2 y}{2}) is correct because it is derived from Hess's Law by manipulating the given equations to obtain the desired reaction.
44 Medium
44 of 179
Remembering +4 | -1
Ka  for  H2O2{K_\mathrm{a}}\;\mathrm{for}\;{\mathrm{H}_2}{\mathrm{O}_2} is of the order of:
View answer and explanation
Correct option: A
10−12{10^{ - 12}}
Option A (10−12{10^{ - 12}}) is correct because the acid dissociation constant (Ka{K_\mathrm{a}}) for H2O2{\mathrm{H}_2}{\mathrm{O}_2} is approximately 10−12{10^{ - 12}}.
45 Easy
45 of 179
Understanding +4 | -1
At absolute zero:
View answer and explanation
Correct option: A
Only para hydrogen exists
Option A (Only para hydrogen exists) is correct because at absolute zero, the lowest energy state is favored, and para-hydrogen has a lower energy state than ortho-hydrogen.
46 Easy
46 of 179
Remembering +4 | -1
Density of water is maximum at :
View answer and explanation
Correct option: C
4∘C4^\circ \mathrm{C}
Option C (4∘C4^{\circ} \mathrm{C}) is correct because water has its maximum density at 4 degrees Celsius.
47 Easy
47 of 179
Remembering +4 | -1
Which of the following is used as a moderator in nuclear reactors.
View answer and explanation
Correct option: B
heavy water
Option B (heavy water) is the correct answer because heavy water (D2O) is an effective moderator due to its ability to slow down neutrons without significant absorption.
48 Medium
48 of 179
Analyzing +4 | -1
Assertion : We feel cold on touching the ice.

Reason : Ice is a solid form of water.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.) is correct because the assertion is true, and the reason is also true, but the reason does not explain the assertion.
49 Medium
49 of 179
Understanding +4 | -1
Heavy water is not used for dinking because:
View answer and explanation
Correct option: C
Its physiological action is different from ordinary water
Option C is correct because heavy water's physiological action differs from ordinary water, affecting biological processes.
50 Easy
50 of 179
Remembering +4 | -1
The O—O bond length in H2O2{\mathrm{H}_2}{\mathrm{O}_2} is:
View answer and explanation
Correct option: B
1.48A∘1.48\mathop \mathrm{A}\limits^ \circ
Option B (1.48A∘1.48\mathop \mathrm{A}\limits^ \circ) is correct because the O-O bond length in H2O2H_2O_2 is experimentally determined to be approximately 1.48 Angstroms.
51 Easy
51 of 179
Understanding +4 | -1
Which of the following gives H2O2{H_2}{O_2} on hydrolysis?
View answer and explanation
Correct option: B
H2SO5{H_2}S{O_5}
The correct answer is B (H2SO5{H_2}S{O_5}) because its hydrolysis yields sulphuric acid and hydrogen peroxide (H2O2{H_2}{O_2}).
52 Easy
52 of 179
Remembering +4 | -1
Which physical property of dihydrogen is wrong
View answer and explanation
Correct option: D
Non-inflammable gas
Option D (Non-inflammable gas) is correct because dihydrogen (H₂) is highly flammable and readily combusts with oxygen.
53 Medium
53 of 179
Understanding +4 | -1
Hydrogen peroxide when added to a solution of potassium permanganate acidified with sulphuric acid
View answer and explanation
Correct option: C
Acts as a reducing agent
The correct answer is C (Acts as a reducing agent) because hydrogen peroxide reduces potassium permanganate in acidic medium, itself getting oxidized to oxygen.
54 Easy
54 of 179
Application +4 | -1
The number of protons, electrons and neutrons respectively in a molecule of heavy water is:
View answer and explanation
Correct option: A
10,10,1010,\mathrm{ }10,\mathrm{ }10
The correct answer is 10,10,1010,\mathrm{ }10,\mathrm{ }10 because heavy water (D2OD_2O) has 2 deuterium atoms (1 proton, 1 neutron, 1 electron each) and 1 oxygen atom (8 protons, 8 neutrons, 8 electrons).
55 Medium
55 of 179
Understanding +4 | -1
Decolourisation of acidified potassium permanganate occurs when H2O2{\mathrm{H}_2}{\mathrm{O}_2} is added to it. This is due to:
View answer and explanation
Correct option: B
Reduction of KMnO4\mathrm{KMn}{\mathrm{O}_4}
Option B is correct. H2O2{H_2}{O_2} reduces KMnO4KMnO_4 because it acts as a reducing agent, causing the decolourisation. Mn7+Mn^{7+} is reduced to Mn2+Mn^{2+}.
56 Easy
56 of 179
Remembering +4 | -1
Which one of the following is called amphoteric solvent?
View answer and explanation
Correct option: D
Water
Option D (Water) is correct because water is an amphoteric solvent, meaning it can act as both an acid and a base.
57 Easy
57 of 179
Remembering +4 | -1
Permutit is:
View answer and explanation
Correct option: A
Hydrated sodium aluminium silicate
Option A (Hydrated sodium aluminium silicate) is correct because Permutit is a synthetic zeolite, which is a hydrated sodium aluminum silicate used for water softening.
58 Easy
58 of 179
Remembering +4 | -1
H2O2{\mathrm{H}_2}{\mathrm{O}_2} is stored in:
View answer and explanation
Correct option: C
Plastic container after addition of stabilizer
Option C is correct because H₂O₂ is stored in plastic containers with stabilizers to prevent decomposition, which can be catalyzed by metal ions.
59 Easy
59 of 179
Remembering +4 | -1
The maximum possible number of hydrogen bonds a water molecule can form is:
View answer and explanation
Correct option: D
4
Option D (4) is correct because a water molecule can form two hydrogen bonds through its two hydrogen atoms and accept two hydrogen bonds through its two lone pairs on the oxygen atom.
60 Easy
60 of 179
Remembering +4 | -1
The electronic configuration of deuterium is:
View answer and explanation
Correct option: D
1s11{s^1}
Option D (1s11{s^1}) is correct because deuterium is an isotope of hydrogen with one proton and one neutron, thus having only one electron with the electronic configuration of 1s11{s^1}.
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