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JEE • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 269 questions

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181 Hard
181 of 269
Remembering +4 | -1
Angle strain in cyclopropane is
View answer and explanation
Correct option: A
24∘44′24^\circ 44'
Option A (24∘44′24^\circ 44') is correct because it represents the calculated angle strain in cyclopropane based on its geometry.
182 Easy
182 of 269
Application +4 | -1
The mass of CO2C{O_2} produced by the combustion of 60 g of C2H6{C_2}{H_6} in excess of oxygen is
View answer and explanation
Correct option: D
176 g
Option D (176 g) is correct because it is calculated based on the stoichiometry of the combustion reaction of ethane.
183 Medium
183 of 269
Application +4 | -1
A mixture of CS2\mathrm{C}{\mathrm{S}_2} and H2S{\mathrm{H}_2}\mathrm{S} on passing over heated CuCu gives:
View answer and explanation
Correct option: B
CH4\mathrm{C}{\mathrm{H}_4}
Option B (CH4\mathrm{C}{\mathrm{H}_4}) is correct because the reaction of CS2 and H2S over heated Cu produces methane and sulfur.
184 Easy
184 of 269
Analyzing +4 | -1
A hydrocarbon has the formula C3H4{\mathrm{C}_3}{\mathrm{H}_4}. To find out whether it contains two double bonds or triple bonds, the following test is performed:
View answer and explanation
Correct option: A
Passed through ammoniacalAgNO3\mathrm{AgN}{\mathrm{O}_3}
Option A is correct because passing the hydrocarbon through ammoniacal AgNO3 will identify terminal alkynes (containing a triple bond at the end of the chain).
185 Easy
185 of 269
Understanding +4 | -1
Which of these does not follow anti-Markownikoff’s rule?
View answer and explanation
Correct option: A
2-butene
Option A (2-butene) is correct because anti-Markownikoff's rule applies only to asymmetric alkenes, and 2-butene is a symmetric alkene.
186 Medium
186 of 269
Application +4 | -1
Major product formed in the following reaction is
CH3−CH=CH−CH∣CH3−CH3→HBrC{H_3} - CH = CH - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {C{H_3}} \end{array}} - C{H_3}\xrightarrow{{HBr}}
View answer and explanation
Correct option: D
CH3−CH2−CH2−Br∣C∣CH3−CH3C{H_3} - C{H_2} - C{H_2} - \begin{array}{cccccccccccccccccccc} {Br} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - C{H_3}
Option D (CH3−CH2−CH2−Br∣C∣CH3−CH3C{H_3} - C{H_2} - C{H_2} - \begin{array}{cccccccccccccccccccc} {Br} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - C{H_3}) is correct because it follows Markovnikov's rule, where the bromine adds to the more substituted carbon.
187 Medium
187 of 269
Understanding +4 | -1
On passing electric discharge through graphite in presence of H2{\mathrm{H}_2} the compound formed is:
View answer and explanation
Correct option: D
All of these
Option D is correct because passing an electric discharge through graphite in the presence of hydrogen can lead to the formation of methane, ethane, and acetylene.
188 Easy
188 of 269
Understanding +4 | -1
The number of isomeric xylenes is:
View answer and explanation
Correct option: B
3
Option B (3) is correct because there are three possible isomers of xylene: ortho-xylene, meta-xylene, and para-xylene.
189 Medium
189 of 269
Remembering +4 | -1
n-hexadecane (cetane) has cetane number:
View answer and explanation
Correct option: A
100
Option A (100) is correct because n-hexadecane (cetane) is assigned a cetane number of 100 by definition.
190 Easy
190 of 269
Understanding +4 | -1
Propadiene, C3H4{\mathrm{C}_3}{\mathrm{H}_4} molecule contains:
View answer and explanation
Correct option: A
Two sp2s{p^2} and one   sp\;sp-hybrid carbon
Option A (Two sp2s{p^2} and one   sp\;sp-hybrid carbon) is correct because the propadiene molecule has two terminal carbons with sp2s{p^2} hybridization and one central carbon with   sp\;sp hybridization.
191 Easy
191 of 269
Understanding +4 | -1
In chlorobenzene, the −Cl- \mathrm{Cl} group:
View answer and explanation
Correct option: B
Deactivates the benzene ring more via inductive effect than activating it via resonance effect
Option B (Deactivates the benzene ring more via inductive effect than activating it via resonance effect) is correct because the inductive effect of chlorine is stronger than its resonance effect, leading to overall deactivation.
192 Easy
192 of 269
Analyzing +4 | -1
(A): In the Kolbe's electrolysis of two moles of CH3COOK\mathrm{CH}_3 \mathrm{COOK} in aqueous solution, 89.689.6 lit of gases evolved at 1 atm1 \mathrm{~atm} pressure and 273 K273 \mathrm{~K}.
(R) Kolbe's electrolysis of aqueous solution of CH3COOK\mathrm{CH}_3 \mathrm{COOK} involves free radical mechanism.
View answer and explanation
Correct option: B
Both A and R are correct, R is not the correct explanation of A
The correct answer is B because both the assertion and the reason are correct, but the reason is not the correct explanation for the assertion.
193 Medium
193 of 269
Application +4 | -1
Which of the following compounds react with, an aqueous solution of Ag(NH2)2OH\mathrm{Ag}{\left( {\mathrm{N}{\mathrm{H}_2}} \right)_2}\mathrm{OH}?
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Correct option: C
1-butyne
Option C (1-butyne) is correct because terminal alkynes react with ammoniacal silver nitrate due to the acidity of the terminal hydrogen.
194 Medium
194 of 269
Application +4 | -1
CH3−HC=CH2+HCl→PeroxideBenzoyl?C{H_3} - HC= C{H_2} + HCl\xrightarrow[{{\text{Peroxide}}}]{{{\text{Benzoyl}}}}?
View answer and explanation
Correct option: A
2 – chloropropane
Option A (2 – chloropropane) is correct because the reaction follows Markovnikov's rule in the presence of peroxide.
195 Medium
195 of 269
Analyzing +4 | -1
2-methylpropene is isomeric with butane-1. They can be distinguished by:
View answer and explanation
Correct option: D
O3,Zn/H2O{\mathrm{O}_3},\mathrm{Zn}/{\mathrm{H}_2}\mathrm{O}
Option D (O3,Zn/H2O{\mathrm{O}_3},\mathrm{Zn}/{\mathrm{H}_2}\mathrm{O}) is correct because ozonolysis followed by reductive workup produces different carbonyl compounds for 2-methylpropene and butane-1.
196 Easy
196 of 269
Remembering +4 | -1
The preparation of ethane by electrolysis of aqueous solution of potassium acetate is called as
View answer and explanation
Correct option: D
Kolbe's synthesis
Option D (Kolbe's synthesis) is correct because the electrolysis of aqueous potassium acetate results in the formation of ethane via Kolbe's electrolysis.
197 Medium
197 of 269
Analyzing +4 | -1
Which of the following will not produce ethane
View answer and explanation
Correct option: B
reduction of CH3COCH3C{H_3}COC{H_3} with HI/P4HI/{P_4}
Option B (reduction of CH3COCH3C{H_3}COC{H_3} with HI/P4HI/{P_4}) will produce propane, not ethane.
198 Easy
198 of 269
Remembering +4 | -1
The carbide which reacts with water to form ethyne is
View answer and explanation
Correct option: A
CaC2\mathrm{Ca}{\mathrm{C}_2}
Option A (CaC2) is correct because calcium carbide (CaC2) reacts with water to produce ethyne (acetylene).
199 Easy
199 of 269
Remembering +4 | -1
Paraffin dissolves in:
View answer and explanation
Correct option: B
Benzene
Option B (Benzene) is correct because paraffin (alkanes) and benzene are both non-polar substances, and \"like dissolves like.\"
200 Medium
200 of 269
Remembering +4 | -1
The most stable conformational isomer of cyclohexane is:
View answer and explanation
Correct option: A
Chair form
Option A (Chair form) is correct because the chair conformation of cyclohexane is the most stable due to minimal torsional and steric strain.
201 Easy
201 of 269
Understanding +4 | -1
Sodium formate on heating with soda lime gives:
View answer and explanation
Correct option: C
H2{\mathrm{H}_2}
Option C (H2{\mathrm{H}_2}) is correct because sodium formate, when heated with soda lime, undergoes decarboxylation to produce hydrogen gas.
202 Easy
202 of 269
Remembering +4 | -1
Petroleum is formed by the chemical changes in:
View answer and explanation
Correct option: D
Both (b) and ©
Option D (Both (b) and (c)) is correct because petroleum is formed from the chemical changes in both vegetable and animal matter over millions of years.
203 Hard
203 of 269
Application +4 | -1
At constant temperature and pressure, the percentage of butane by volume in a mixture of butane, propane and propyne is 40%.40 \%. What will be the volume of CO2(g)\mathrm{CO}_{2(\mathrm{g})} (in ml) under same pressure and temperature produced, when 150 ml of gaseous mixture is burnt in excess of O2?\mathrm{O}_2?
View answer and explanation
Correct option: C
510 ml
Option C (510 ml) is correct because it's the total volume of CO2 produced from the combustion of the mixture.
204 Medium
204 of 269
Remembering +4 | -1
Among the following number of meta directing groups are:
−CN,−NO2,−COOH,−CH3,−SO3H,−N+H3,−F-\mathrm{CN},-\mathrm{NO}_2,-\mathrm{COOH},-\mathrm{CH}_3,-\mathrm{SO}_3 \mathrm{H},-\stackrel{+}{\mathrm{N}} \mathrm{H}_3,-\mathrm{F}
View answer and explanation
Correct option: A
5
Option A (5) is correct because there are five meta-directing groups among the listed substituents: -CN, -NO2, -COOH, -SO3H, and -NH3+.
205 Medium
205 of 269
Remembering +4 | -1
Which of the following has the least octane number?
View answer and explanation
Correct option: D
nn -heptane
Option D (nn -heptane) is correct because n-heptane is assigned an octane number of 0, representing very poor antiknock properties.
206 Medium
206 of 269
Understanding +4 | -1
The common name and IUPAC name of CH3CH2−C≡CH\mathrm{CH}_3 \mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}, respectively are
View answer and explanation
Correct option: B
ethylacetylene and but-1-yne
The correct answer is A (Liquid solvent, solid solvent) because during the depression of freezing point, the liquid solvent and solid solvent are in equilibrium.
207 Easy
207 of 269
Understanding +4 | -1
Electrophile in the case of chlorination of Benzene
View answer and explanation
Correct option: C
Cl+C{l^ + }
Option C (Cl+C{l^ + }) is correct because the electrophile in the chlorination of benzene is the chloronium ion (Cl+C{l^ + }).
208 Easy
208 of 269
Remembering +4 | -1
The tar which is used to make roads is a solid known as:
View answer and explanation
Correct option: A
Pitch
Option A (Pitch) is correct because pitch is a viscous, black, thermoplastic material derived from coal tar or petroleum and is used as a binder in road construction.
209 Easy
209 of 269
Application +4 | -1
In which of the following will Kharasch effectoperate?
View answer and explanation
Correct option: B
CH3CH2−CH=CH2+HBr\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}-\mathrm{CH} = \mathrm{C}{\mathrm{H}_2} + \mathrm{HBr}
Option B (CH3CH2−CH=CH2+HBr\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}-\mathrm{CH} = \mathrm{C}{\mathrm{H}_2} + \mathrm{HBr}) is correct because Kharasch effect (anti-Markovnikov addition) operates with HBr in the presence of peroxides.
210 Medium
210 of 269
Analyzing +4 | -1
In the reaction C2H6→(CH3COO)2MnA→NaOHB,{C_2}{H_6}\xrightarrow{{{{\left( {C{H_3}COO} \right)}_2}Mn}}A\xrightarrow{{NaOH}}B, the correct statement about BB is
View answer and explanation
Correct option: D
Both 1 and 2
Option D is correct because after the given reactions, A is acetic acid and B is sodium acetate, which on decarboxylation gives methane and on Kolbe's electrolysis gives ethane.
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