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JEE • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 269 questions

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211 Easy
211 of 269
Remembering +4 | -1
In benzene, C−CC - C bond length is 1.39 Ao\mathop \mathrm{A}\limits^\mathrm{o}; the C−HC - H bond length is:
View answer and explanation
Correct option: B
1.08
Option B (1.08) is correct because the typical C-H bond length in benzene is approximately 1.08 Å.
212 Medium
212 of 269
Understanding +4 | -1
Which of the following will decolourise alkaline KMnO4\mathrm{KMnO}_4 solution?
View answer and explanation
Correct option: D
C2H4\mathrm{C}_2 \mathrm{H}_4
Option D (C2H4\mathrm{C}_2 \mathrm{H}_4) is correct because it is an unsaturated compound (alkene) that can react with and decolorize alkaline KMnO4\mathrm{KMnO}_4 solution via oxidation.
213 Medium
213 of 269
Analyzing +4 | -1
In the following sequence the product D is,

CH≡CH→HBrA→HBrB→KOH(alc.)C→NaNH2D:\mathrm{CH} \equiv \mathrm{CH}\xrightarrow{{HBr}}A\xrightarrow{{HBr}}B\xrightarrow{{\mathrm{KOH}(\mathrm{alc}\mathrm{.})}}C\xrightarrow{{\mathrm{NaN}{\mathrm{H}_2}}}D:
View answer and explanation
Correct option: C
Ethyne
Option C (Ethyne) is correct because the sequence of reactions leads back to the starting material, ethyne.
214 Hard
214 of 269
Understanding +4 | -1
S-I: Friedal Crafts Acylation of benzene with acetic anhydride in presence of anhydrous AlCl3{AlCl}_3 yields acetophenone and not poly substituted products.
S-II: It is due to stearic hindrance of bulky actyl group CH3− CO∥−C{H_3} - \mathop {{\text{ }}C}\limits^{\begin{array}{cccccccccccccccccccc} O \\ \parallel \end{array}}- and also, it is a deactivating group.
View answer and explanation
Correct option: A
S-I &\& S-II are true
Option A is correct because Friedel-Crafts acylation indeed yields acetophenone and not polysubstituted products due to steric hindrance and the deactivating nature of the acyl group.
215 Easy
215 of 269
Analyzing +4 | -1
One mole of alkene on ozonalysis give one mole of acetaldehyde and one mole of acetone. The IUPAC name of alkene is
View answer and explanation
Correct option: A
2 – methyl – 2 - butene
Option A (2 – methyl – 2 - butene) is correct because ozonolysis of 2-methyl-2-butene yields acetaldehyde and acetone.
216 Medium
216 of 269
Analyzing +4 | -1
An unknown compound A has a molecular formula C4H6{\mathrm{C}_4}{\mathrm{H}_6}. When A is treated with excess of Br2\mathrm{B}{\mathrm{r}_2} a new substance B with formula C4H6Br4  {\mathrm{C}_4}{\mathrm{H}_6}\mathrm{B}{\mathrm{r}_4}\mathrm{\;} is formed. A forms a white ppt. with ammoniacal silver nitrate solution. A may be :
View answer and explanation
Correct option: A
But-1-yne
The correct answer is But-1-yne because it has a terminal alkyne which reacts with ammoniacal silver nitrate to form a white precipitate, and the formula C4H6 suggests two degrees of unsaturation.
217 Easy
217 of 269
Remembering +4 | -1
Kerosene is a mixture of:
View answer and explanation
Correct option: B
Alkanes
Option B (Alkanes) is correct because kerosene is a mixture of alkanes, primarily those with carbon chain lengths between C11 and C16.
218 Medium
218 of 269
Understanding +4 | -1
Which of the following can be sulphonated most easily
View answer and explanation
Correct option: B
toluene
Option B (toluene) is correct because the methyl group on toluene is an electron-donating group, activating the ring towards electrophilic substitution, such as sulfonation.
219 Medium
219 of 269
Understanding +4 | -1
Which of the following reagent is not involved in the halogenation of benzene
View answer and explanation
Correct option: C
Br2/CCl4B{r_2}/CC{l_4}
Option C (Br2/CCl4B{r_2}/CC{l_4}) is correct because CCl4CC{l_4} acts as a solvent but not as a halogen carrier to generate an electrophile, which is necessary for the halogenation of benzene.
220 Medium
220 of 269
Analyzing +4 | -1
CH3−C≡CH→H2SO4HgSO4A    CH3−CH=CH2→2⋅H2O2/OH−1.BH3,THFX→PCCB{\text{C}}{{\text{H}}_3} - {\text{C}} \equiv {\text{CH}}\xrightarrow[{{{\text{H}}_2}{\text{S}}{{\text{O}}_4}}]{{{\text{HgS}}{{\text{O}}_4}}}{\text{A}}\,\,\,\,{\text{C}}{{\text{H}}_3} - {\text{CH}} = {\text{C}}{{\text{H}}_2}\xrightarrow[{2 \cdot {{\text{H}}_2}{{\text{O}}_2}/{\text{O}}{{\text{H}}^ - }}]{{1.{\text{B}}{{\text{H}}_3},{\text{THF}}}}{\text{X}}\xrightarrow{{{\text{PCC}}}}{\text{B}}
Products A\mathrm{A} and B\mathrm{B} are differentiated by
View answer and explanation
Correct option: B
Tollen’s reagent
Option B is correct because Tollen's reagent can differentiate between a ketone (A) and an aldehyde (B).
221 Easy
221 of 269
Application +4 | -1
Kolbe’s synthesis on electrolysis of sodium salt of butanoic acid gives:
View answer and explanation
Correct option: A
n-hexane
Option A (n-hexane) is correct because Kolbe's electrolysis of sodium butanoate results in the formation of n-hexane.
222 Easy
222 of 269
Remembering +4 | -1
Which one of the following is the stable structure of cyclohexatriene?
View answer and explanation
Correct option: D
Planar form
Option D (Planar form) is correct because cyclohexatriene, also known as benzene, has a planar structure due to resonance and sp2 hybridization.
223 Easy
223 of 269
Understanding +4 | -1
Alkyl halides get converted to alkenes through:
View answer and explanation
Correct option: C
Elimination reaction
Option C (Elimination reaction) is correct because alkyl halides are converted to alkenes through dehydrohalogenation, which is an elimination reaction.
224 Easy
224 of 269
Remembering +4 | -1
Which of the following is produced when coal is subjected to destructive distillation?
View answer and explanation
Correct option: D
Coal gas
Option D (Coal gas) is correct because coal gas is one of the products obtained when coal undergoes destructive distillation.
225 Easy
225 of 269
Understanding +4 | -1
Which of the following is elimination reaction?
View answer and explanation
Correct option: D
All of the above are correct
Option D (All of the above are correct) is correct because all the given reactions involve the removal of a molecule from the substrate, which is the defining characteristic of an elimination reaction.
226 Medium
226 of 269
Remembering +4 | -1
Ethylene reacts with 1% alkaline KMnO4\mathrm{KMn}{\mathrm{O}_4} to form
View answer and explanation
Correct option: B
Ethylene glycol
Option B (Ethylene glycol) is correct because the reaction of ethylene with 1% alkaline KMnO4\mathrm{KMn}{\mathrm{O}_4} (Baeyer's reagent) produces ethylene glycol.
227 Easy
227 of 269
Analyzing +4 | -1
Which of the following would not give 2phenylbutane as the major product in a FriedelCrafts alkylation reaction?
View answer and explanation
Correct option: C
Butanoyl chloride +AlCl3+\mathrm{AlCl}_3 then Zn,HCl\mathrm{Zn}, \mathrm{HCl}
Option C is correct because butanoyl chloride with AlCl3 followed by Zn, HCl will result in butylbenzene, not 2-phenylbutane, due to acylation followed by reduction.
228 Easy
228 of 269
Understanding +4 | -1
Which is most acidic of the following?
View answer and explanation
Correct option: B
Acetylene
Option B (Acetylene) is correct because acetylene has the most acidic hydrogen due to the sp hybridization of the carbon atoms, resulting in a higher s-character and greater electronegativity.
229 Medium
229 of 269
Analyzing +4 | -1
Which of the following hydrocarbon on reductive ozonolysis will produce CO2\mathrm{CO}_2 gas?
View answer and explanation
Correct option: C
CH2=C=CH2\mathrm{CH}_2=\mathrm{C}=\mathrm{CH}_2
Option C is correct because reductive ozonolysis of allene (CH₂=C=CH₂) produces two moles of formaldehyde (HCHO) and one mole of carbon dioxide (CO₂).
230 Easy
230 of 269
Remembering +4 | -1
Which of the following is correct formula of Gammaxane
View answer and explanation
Correct option: C
C6H6Cl6{C_6}{H_6}C{l_6}
Option C (C6H6Cl6{C_6}{H_6}C{l_6}) is correct because Gammaxane, also known as Lindane, is the gamma isomer of benzene hexachloride, with the formula C6H6Cl6{C_6}{H_6}C{l_6}.
231 Easy
231 of 269
Remembering +4 | -1
Pure acetylene has sweet ethereal smell while impure smells like garlic due to presence of:
View answer and explanation
Correct option: B
PH3\mathrm{P}{\mathrm{H}_3}
Option B (PH3\mathrm{P}{\mathrm{H}_3}) is correct because the garlic smell in impure acetylene is due to the presence of phosphine (PH3\mathrm{P}{\mathrm{H}_3}) as an impurity.
232 Easy
232 of 269
Analyzing +4 | -1
Which alkene on ozonalysis gives formaldehyde and acetaldehyde
View answer and explanation
Correct option: B
propene
Option B (propene) is correct because the ozonolysis of propene yields formaldehyde and acetaldehyde.
233 Medium
233 of 269
Application +4 | -1
In a nitration experiment, 10.0 g10.0 \mathrm{~g} of benzene gave 13.2 g13.2 \mathrm{~g} of nitrobenzene. The percentage yield for nitration of benzene is:
View answer and explanation
Correct option: A
83.7%83.7 \%
Option A (83.7%83.7 \%) is correct because it is the percentage yield calculated from the actual yield of nitrobenzene compared to the theoretical yield based on the amount of benzene used.
234 Easy
234 of 269
Remembering +4 | -1
To enable easy detection of gas leakage from cylinders, the substance added to L.P.G. is:
View answer and explanation
Correct option: C
Thioalcohols
Option C (Thioalcohols) is correct because thioalcohols (mercaptans) have a strong, unpleasant odor and are added to LPG to detect leaks.
235 Easy
235 of 269
Analyzing +4 | -1
Which of the following compounds contain 10,20,30{1^0},{2^0},{3^0} as well as 40{4^0} carbon atoms
View answer and explanation
Correct option: D
2,2,3-trimethyl pentane
The correct answer is D (2,2,3-trimethyl pentane) because it is the only option that contains primary, secondary, tertiary, and quaternary carbon atoms.
236 Medium
236 of 269
Analyzing +4 | -1
Assertion (A): Acidity of C−H\mathrm{C}-\mathrm{H} bond decreases in the order 3CH≡CH→Red hot iron tube3{\text{CH}} \equiv {\text{CH}}\xrightarrow{{{\text{Red hot iron tube}}}}
Reason (R): Acidity of the C−H\mathrm{C}-\mathrm{H} bond decreases as the electronegativity of the carbon to which it is attached decreases.
View answer and explanation
Correct option: A
Both A &\& R are correct and R is correct explanation of A
Both A & R are correct and R is correct explanation of A because the acidity of C-H bond is directly related to the s-character of the carbon atom, which also affects its electronegativity.
237 Easy
237 of 269
Understanding +4 | -1
Which one is not prepared by Wurtz reaction
View answer and explanation
Correct option: C
CH4C{H_4}
Option C (CH4CH_4) is correct because the Wurtz reaction involves the coupling of two alkyl halides to form a higher alkane, and methane cannot be formed by this method.
238 Medium
238 of 269
Understanding +4 | -1
Butyne on oxidation with hot. alk KMnO4KMn{O_4} gives
View answer and explanation
Correct option: C
CH3CH2COOH+CO2+H2OC{H_3}C{H_2}COOH + C{O_2} + {H_2}O
Option C (CH3CH2COOH+CO2+H2OC{H_3}C{H_2}COOH + C{O_2} + {H_2}O) is correct because butyne oxidation with hot alkaline KMnO4 cleaves the triple bond, yielding propanoic acid and carbon dioxide.
239 Medium
239 of 269
Understanding +4 | -1
Which of the following show Acidic Character of Alkyne?
View answer and explanation
Correct option: C
NaNH2{NaNH}_2
Option C (NaNH2{NaNH}_2) is correct because sodium amide is a strong base that can deprotonate terminal alkynes, demonstrating their acidic character.
240 Medium
240 of 269
Understanding +4 | -1
Which of the following statement(s) is/are correct?

(i) Alkanes can have infinite number of conformations by rotation around a C−C{C}-{C} single bonds.

(ii) Rotation around C−C{C}-{C} single bond is completely free.

(iii) Rotation is hindered by a small energy barrier of 1−20 kJ mol−11-20 {~kJ} {~mol}^{-1} due to torsional strain.
View answer and explanation
Correct option: B
(i) and (iii)
Option B ((i) and (iii)) is correct because alkanes can have infinite conformations due to rotation around C-C single bonds, and this rotation is hindered by a small energy barrier due to torsional strain.
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