Back to HYDROCARBONS

JEE CHEMISTRY MCQ: HYDROCARBONS

1 Easy

1 of 1

Understanding +4 | -1

The product obtained at anode upon Kolbe's electrolysis of sodium ethanoate is

View answer and explanation

Correct option: B

\mathrm{C}_2 \mathrm{H}_6

Option B (

\mathrm{C}_2 \mathrm{H}_6

) is correct because the product obtained at the anode during Kolbe's electrolysis of sodium ethanoate is ethane.

More Questions from HYDROCARBONS

Practice All Chapter MCQs →

\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: