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JEE • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Medium

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121 Medium
121 of 227
Understanding +4 | -1
Electronic configuration of four elements A, B, C and D are given below.
A) 1S22S22P61{S^2}2{S^2}2{P^6} B) 1S22S22P41{S^2}2{S^2}2{P^4} C) 1S22S22P63S11{S^2}2{S^2}2{P^6}3{S^1} D) 1S22S22P51{S^2}2{S^2}2{P^5}
Which of the following is the correct order of increasing tendency to gain electron.
View answer and explanation
Correct option: A
A < C < B < D
Option A (A < C < B < D) is correct because it represents the increasing order of electron gain tendency based on electronic configurations and noble gas stability.
122 Medium
122 of 227
Analyzing +4 | -1
The first second and third ionisation energies (E1,E2  and  E3)\left( {{E_1},{E_2}\,\,and\,\,{E_3}} \right) for an element are 7  eV,12.5  eV7\,\,eV,12.5\,\,eV and 42.5  eV42.5\,\,eV respectively. The most stable oxidation state of the element will be
View answer and explanation
Correct option: D
+2+ 2
Option D (+2) is correct because there is a large jump in ionization energy between E2 and E3, indicating that the element readily loses two electrons to achieve a stable configuration.
123 Medium
123 of 227
Understanding +4 | -1
Which among the following elements has lowest value of ionisation energy?
View answer and explanation
Correct option: B
Sn
Option B (Sn) is correct because, down the group, ionization energy decreases, and due to the inert pair effect, Pb has a higher ionization energy than Sn.
124 Medium
124 of 227
Understanding +4 | -1
For elements B, C, N Li, Be, O and F, the correct order of first ionization enthalpy is
View answer and explanation
Correct option: D
Li<B<Be<C<O<N<F\mathrm{Li} < \mathrm{B} < \mathrm{Be} < \mathrm{C} < \mathrm{O} < \mathrm{N} < \mathrm{F}
Option D (Li<B<Be<C<O<N<F\mathrm{Li} < \mathrm{B} < \mathrm{Be} < \mathrm{C} < \mathrm{O} < \mathrm{N} < \mathrm{F}) is correct because it accounts for the exceptions due to stable electronic configurations in Be and N.
125 Medium
125 of 227
Analyzing +4 | -1
Statement-I: There is regular increase in chemical reactivity from group 1 to group 18 .

Statement-II: Oxides of group-1 elements are basic and oxide of group 17 are acidic
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C is correct because statement I is false, as reactivity doesn't regularly increase from group 1 to 18, and statement II is true, as group 1 oxides are basic and group 17 oxides are acidic.
126 Medium
126 of 227
Application +4 | -1
In first 110 elements how many elements having e−{e^ - } in 5f5f subshell:-
View answer and explanation
Correct option: C
20
Option C (20) is correct because elements from atomic number 91 to 110 have electrons in the 5f subshell, totaling 20 elements.
127 Medium
127 of 227
Analyzing +4 | -1
In which of the following arrangements the order is not according to the property indicated against it?
View answer and explanation
Correct option: C
B<C<N<O\mathrm{B} < C < N < O increasing first ionisation enthalphy
Option C (B<C<N<O\mathrm{B} < C < N < O increasing first ionisation enthalphy) is correct because the ionization enthalpy of Nitrogen is higher than Oxygen due to the stable half-filled electronic configuration of Nitrogen.
128 Medium
128 of 227
Understanding +4 | -1
The first ionization potentials (eV)(\mathrm{eV}) of Be{Be} and B{B} respectively are
View answer and explanation
Correct option: D
9.32,8.299.32,8.29
Option D is correct because Beryllium has a higher ionization potential than Boron due to its stable, fully-filled 2s² electron configuration.
129 Medium
129 of 227
Analyzing +4 | -1
Which of the following order is wrong
View answer and explanation
Correct option: B
Li<Be<B<C−Li < Be < B < C -First IP
Option B (Li<Be<B<C−Li < Be < B < C -First IP) is wrong because the first ionization potential generally increases across a period, but there are exceptions due to electronic configurations.
130 Medium
130 of 227
Remembering +4 | -1
Electrons are filled into different orbitals and this distribution of electrons into orbitals of an atoms is termed as
View answer and explanation
Correct option: B
Electronic configuration
Option B (Electronic configuration) is correct because electronic configuration describes the arrangement of electrons in the different orbitals of an atom.
131 Medium
131 of 227
Understanding +4 | -1
Of the following, which one is a correct statement?
View answer and explanation
Correct option: D
The ionic radius of a metal is less than its atomic radius
Option D is correct. Metals lose electrons to form positive ions, resulting in a smaller ionic radius due to increased effective nuclear charge.
132 Medium
132 of 227
Analyzing +4 | -1
Which one of the following is smallest in size
View answer and explanation
Correct option: C
Na
Option C (Na) is correct because among the given species, Na is the only cation and neutral atom, while others are isoelectronic anions. Cations are smaller than their corresponding neutral atoms.
133 Medium
133 of 227
Understanding +4 | -1
Which of the following transition involves maximum amount of energy
View answer and explanation
Correct option: D
M(g)2+→M(g)3+ M_{\left( g \right)}^{2 + } \to M_{\left( g \right)}^{3 + }\,
Option D (M(g)2+→M(g)3+ M_{\left( g \right)}^{2 + } \to M_{\left( g \right)}^{3 + }\,) is correct because ionization enthalpy increases with each successive ionization.
134 Medium
134 of 227
Analyzing +4 | -1
The first four ionisation enthalpies of an element are 191, 678, 872, 6982 K cal mol−16982 \,\mathrm{K} \,\mathrm{cal} \,\mathrm{mol}^{-1} respectively. The number of valence electrons in the element is
View answer and explanation
Correct option: C
3
Option C (3) is correct because there is a large jump in ionization enthalpy between the 3rd and 4th ionization, indicating 3 valence electrons.
135 Medium
135 of 227
Understanding +4 | -1
The electronic configuration of elements A, B and C are [He]2s1,[Ne]3s1[He] 2 s^1,[{Ne}] 3 s^1 and [Ar]4s1[{Ar}] 4 {s}^1 respectively. Which one of the following order is correct for the first ionization potentials (in kJmol−1\mathrm{kJ} \mathrm{mol}{ }^{-1}) of A, B, C?
View answer and explanation
Correct option: A
A > B > C
Option A (A > B > C) is correct because ionization potential decreases down the group as the outermost electron is further from the nucleus.
136 Medium
136 of 227
Understanding +4 | -1
Which of the following orders of radii is correctly represented?
View answer and explanation
Correct option: B
Na−>Na>Na+\mathrm{Na}^{-} > \mathrm{Na} > \mathrm{Na}^+
Option B (Na−>Na>Na+\mathrm{Na}^{-} > \mathrm{Na} > \mathrm{Na}^+) is correct because anions are larger than their neutral atoms, and cations are smaller.
137 Medium
137 of 227
Remembering +4 | -1
The enthalpy change accompanying in the given reaction, X(g)+e−⟶X−(g)X(g)+e^{-} \longrightarrow X^{-}(g) is defined as
View answer and explanation
Correct option: A
Electron gain enthalpy
Option A (Electron gain enthalpy) is correct because the given reaction represents the addition of an electron to a gaseous atom, which is the definition of electron gain enthalpy.
138 Medium
138 of 227
Remembering +4 | -1
Which of the following oxide is neutral
View answer and explanation
Correct option: B
CO\mathrm{CO}
Option B (CO\mathrm{CO}) is correct because carbon monoxide is a neutral oxide, meaning it does not react with acids or bases to form salts.
139 Medium
139 of 227
Analyzing +4 | -1
Which is mismatched regarding the position of the element as given below?
View answer and explanation
Correct option: D
Both (1) & (3)
Option D (Both (1) & (3)) is correct because the electronic configurations of Ac and Uup place them in the d-block and p-block, respectively.
140 Medium
140 of 227
Understanding +4 | -1
What effect is observed, on the size of an atom when an electron is removed and in another case when an electron is added to the same atom?
View answer and explanation
Correct option: B
Size decreases and increases respectively
Option B (Size decreases and increases respectively) is correct because removing an electron increases the effective nuclear charge, decreasing size, while adding an electron increases electron-electron repulsion, increasing size.
141 Medium
141 of 227
Remembering +4 | -1
Pauling&rsquo;s equation for determining the electronegativity of an element, is XA,  XB={X_A},\;{X_B} = electronegativity values of elements and Δ=\Delta = represents polarity of A-B bond
View answer and explanation
Correct option: A
XA−XB=0.208Δ{X_A} - {X_B} = 0.208\sqrt \Delta
Option A (XA−XB=0.208Δ{X_A} - {X_B} = 0.208\sqrt \Delta) is correct because it represents Pauling's equation for electronegativity difference based on bond polarity.
142 Medium
142 of 227
Understanding +4 | -1
Which of the following arrangements represents the correct order of electron gain enthalpy (with –ve sign) of the given atomic species?
View answer and explanation
Correct option: D
O<S<F<ClO < S < F < Cl
Option D (O<S<F<ClO < S < F < Cl) is correct because electron gain enthalpy becomes more negative as we move from left to right across a period and less negative as we move down a group, with some exceptions due to electron-electron repulsion.
143 Medium
143 of 227
Analyzing +4 | -1
S-I: The first ionisation energy of BB is less than that of Be{Be}

S-II: The penetration ability of s-electrons is higher than that of p-electrons.

The correct answer is
View answer and explanation
Correct option: A
Both I and II are correct
Option A (Both I and II are correct) is correct because Boron has a lower ionization energy than Beryllium, and s-electrons penetrate better than p-electrons.
144 Medium
144 of 227
Application +4 | -1
The ionisation energy and electron affinity of an element are 13.0 eV and 3.8 eV resp.
It’s electronegativity is
View answer and explanation
Correct option: B
3
Option A (2.8) is incorrect. Option B (3) is correct because electronegativity is approximately the average of ionization energy and electron affinity, scaled appropriately.
145 Medium
145 of 227
Application +4 | -1
The formation of O2−(g){O}^{2-}(\mathrm{g}) starting from O(g){O}(\mathrm{g}) is endothermic by 603 kJ mol−1603 \mathrm{~kJ} \mathrm{~mol}^{-1}. If electron affinity of O(g){O}(\mathrm{g}) is −141 kJ mol−1-141 \mathrm{~kJ} \mathrm{~mol}^{-1}, the second electron affinity of oxygen would be:
View answer and explanation
Correct option: A
+744 kJ mol−1+744 \mathrm{~kJ} \mathrm{~mol}^{-1}
Option A (+744 kJ mol⁻¹) is correct because it represents the energy required to add a second electron to O⁻(g), calculated from the overall endothermic formation of O²⁻(g).
146 Medium
146 of 227
Understanding +4 | -1
Choose the correct coding for following statements. Here T\mathrm{T} stands for True and F\mathrm{F} stands for False statement.

(i) Mendeleev left several gaps in his periodic table for the undiscovered elements.

(ii) The gap under aluminium and a gap under silicon was left and these elements were called Eka aluminium and Eka silicon.

(iii) Germanium was placed in place of Eka-aluminium and gallium was placed in place of Eka silicon.
View answer and explanation
Correct option: C
TTF
Option C (TTF) is correct because Mendeleev did leave gaps, he predicted Eka-aluminum and Eka-silicon, but Germanium replaced Eka-silicon while Gallium replaced Eka-aluminum.
147 Medium
147 of 227
Analyzing +4 | -1
Incorrect statement is/are :

a. Maximum element containing group is third

b. Te is 1st 1^{\text {st }} man made radioactive element

c. Law of octave is valid only upto atomic no. 20.

d. Li-Mg pair shows diagonal relationship.
View answer and explanation
Correct option: D
Only b
Option D (Only b) is correct because Technetium (Tc) is the first man-made radioactive element, not Tellurium (Te).
148 Medium
148 of 227
Analyzing +4 | -1
In which of the following arrangements, the order is NOT according to the property indicated against it
View answer and explanation
Correct option: C
B<C<N<O\mathrm{B < C < N < O} (Increasing first IP)
Option B is correct because the electron affinity of Cl is more than F due to small size and high electron density of F.
149 Medium
149 of 227
Understanding +4 | -1
The atomic radii of transition elements from CrCr to CuCu are almost equal because
View answer and explanation
Correct option: B
Increased effective nuclear charge is balanced by increased screening effect of (n−1) d(n - 1)\,d-orbitals
Option B (Increased effective nuclear charge is balanced by increased screening effect of (n−1) d(n - 1)\,d-orbitals) is correct because the balance between these two effects results in relatively constant atomic radii across the transition series.
150 Medium
150 of 227
Understanding +4 | -1
Arrange the following elements in increasing
order of first ionization enthalpy:

Li, Be, B, C, N, O

Choose the correct answer from the options given
below:
View answer and explanation
Correct option: B
Li << B << Be << C << O << N
Option B (Li << B << Be << C << O << N) is correct because it accounts for the exceptions in the general trend of increasing ionization enthalpy across a period, specifically the lower ionization enthalpy of Boron compared to Beryllium and Oxygen compared to Nitrogen.
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