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JEE • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Medium

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Showing 151-180 of 227 questions

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151 Medium
151 of 227
Understanding +4 | -1
Which of the following properties is inversely related to electronegativity?
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Correct option: D
Metallic properties
Option D is correct because electronegativity and metallic properties have an inverse relationship; as electronegativity increases, metallic properties decrease.
152 Medium
152 of 227
Understanding +4 | -1
The set representing the correct order of first ionisation potential is:
View answer and explanation
Correct option: B
Be>Mg>Ca\mathrm{Be} > Mg > Ca
Option B (Be>Mg>Ca\mathrm{Be} > Mg > Ca) is correct because ionization potential generally decreases down a group, but Be has a higher ionization energy than expected due to its small size and high effective nuclear charge.
153 Medium
153 of 227
Analyzing +4 | -1
Successive first five ionisation energies of a particular element is 7.1, 14.3, 34.5, 46.8, 162.2 (in eV) respectively. The element is likely to be
View answer and explanation
Correct option: B
Si
The correct answer is Si because there is a significant jump between the 4th and 5th ionization energies, indicating that the 4th electron is being removed from a stable, noble gas-like configuration.
154 Medium
154 of 227
Analyzing +4 | -1
The five successive ionisation energies of the element are 800,2427,3658,25024800,2427,3658,25024 and 32824 kJ mol−132824 \mathrm{~kJ} \mathrm{~mol}^{-1} respectively. The number of valence electrons is :
View answer and explanation
Correct option: A
3
Option A is correct. The large jump in ionization energy between the 3rd and 4th ionization energies indicates that the element has 3 valence electrons.
155 Medium
155 of 227
Understanding +4 | -1
Which of the following groups of elements have highly negative electron gain enthalpy?
View answer and explanation
Correct option: D
Both (1) and (2)
The correct answer is D (Both (1) and (2)) because both Group-16 (chalcogens) and Group-17 (halogens) elements have a high tendency to gain electrons due to their electronic configurations.
156 Medium
156 of 227
Understanding +4 | -1
The statement that is not correct for the periodic classification of elements is
View answer and explanation
Correct option: D
For transition elements the dd-sub shells are filled with electrons monotonically with increase in atomic number
Option D is correct because the filling of d-subshells in transition elements is not always monotonic due to electron-electron repulsion and stability of half-filled and fully-filled configurations.
157 Medium
157 of 227
Understanding +4 | -1
The first ionisation enthalpy of NaNa is 5.1 eV, the value of electron gain enthalpy of Na+N{a^ + } will be
View answer and explanation
Correct option: C
- 5.1 eV
Option C (- 5.1 eV) is correct because the electron gain enthalpy of Na+Na^+ is the negative of the ionization enthalpy of Na.
158 Medium
158 of 227
Analyzing +4 | -1
The incorrect statement among the following is
View answer and explanation
Correct option: A
density increases across the period from left to right while decreases down the group.
Option A is the incorrect statement. Density generally increases across a period and also increases down a group due to increasing atomic mass outweighing the increase in atomic size.
159 Medium
159 of 227
Understanding +4 | -1
The element with Z = 120 (not yet discovered) will be an/a
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Correct option: C
Alkaline earth metal
Option C (Alkaline earth metal) is correct because element with Z = 120 will have electronic configuration [noble gas]ns², similar to alkaline earth metals.
160 Medium
160 of 227
Understanding +4 | -1
The tendency towards formation of coloured ions is the maximum in:
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Correct option: B
d-block elements
The correct answer is B (d-block elements) because d-block elements exhibit a high tendency to form colored ions due to d-d transitions.
161 Medium
161 of 227
Understanding +4 | -1
The factor not affecting the ionization enthalpy is
View answer and explanation
Correct option: C
Type of bonding in the crystalline lattice
Option C (Type of bonding in the crystalline lattice) is correct because ionization enthalpy primarily depends on atomic size, nuclear charge, and the type of electron being removed, not the crystalline lattice structure.
162 Medium
162 of 227
Understanding +4 | -1
The first ionisation enthalpy values of third period element, Na,Mg\mathrm{Na}, \mathrm{Mg} an Si\mathrm{Si} are respectively 496,737496,737 and 786 kJ mol−1786 \mathrm{~kJ} \mathrm{~mol}^{-1}. The first ΔiH\Delta_\mathrm{i} \mathrm{H} value for Al\mathrm{Al} will be close to
View answer and explanation
Correct option: B
575 kJ mol−1575 \mathrm{~kJ} \mathrm{~mol}^{-1}
Option B (575 kJ mol−1575 \text{{ kJ mol}}^{-1}) is correct because aluminum's first ionization enthalpy is lower than magnesium's due to effective shielding of the 3p electron.
163 Medium
163 of 227
Understanding +4 | -1
Which of the following statement is incorrect?
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Correct option: D
Increase in electronegativity down a group is accompanied by a decrease in non-metallic properties
Option D (Increase in electronegativity down a group is accompanied by a decrease in non-metallic properties) is correct because electronegativity generally decreases down a group, which also leads to a decrease in non-metallic properties.
164 Medium
164 of 227
Understanding +4 | -1
The molecular formula of chloride of Eka-Aluminium and Eka-Silicon respectively are
View answer and explanation
Correct option: D
GaCl3{GaCl}_3 and GeCl4{GeCl}_4
Option D (GaCl3{GaCl}_3 and GeCl4{GeCl}_4) is correct because Eka-Aluminium corresponds to Gallium (Ga) and Eka-Silicon corresponds to Germanium (Ge), and their respective chlorides are GaCl3{GaCl}_3 and GeCl4{GeCl}_4.
165 Medium
165 of 227
Remembering +4 | -1
The magnitude of screening effect depends upon the number of
View answer and explanation
Correct option: A
Inner electrons
Option A (Inner electrons) is correct because the screening effect, also known as the shielding effect, is primarily determined by the number of inner electrons between the nucleus and the valence electrons.
166 Medium
166 of 227
Analyzing +4 | -1
Assertion : Atomic size along a period decreases.

Reason : Zeff.Z_{\text {eff.}} in a period decreases.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because atomic size decreases along a period due to increasing effective nuclear charge, but the reason states that effective nuclear charge decreases, which is false.
167 Medium
167 of 227
Analyzing +4 | -1
Given below are two statements:
Statement I: The correct order of first ionization enthalpy values of Li,Na,F\mathrm{Li}, \mathrm{Na}, \mathrm{F} and Cl\mathrm{Cl} is Na<Li<Cl<F\mathrm{Na} < \mathrm{Li} < \mathrm{Cl} < \mathrm{F}.
Statement II: The correct order of negative electron gain enthalpy values of Li,Na,F\mathrm{Li}, \mathrm{Na}, \mathrm{F} and Cl\mathrm{Cl} is Na<Li<F<Cl\mathrm{Na} < \mathrm{Li} < \mathrm{F} < \mathrm{Cl}
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: A
Both Statement I and Statement II are true
Option A (Both Statement I and Statement II are true) is correct because the ionization enthalpy and electron gain enthalpy orders are accurate based on periodic trends and specific electronic configurations.
168 Medium
168 of 227
Understanding +4 | -1
Which pair of ions are isoelectronic?
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Correct option: D
Na+\mathrm{Na}^{+}and Mg2+\mathrm{Mg}^{2+}
Option D (Na+\mathrm{Na}^{+}and Mg2+\mathrm{Mg}^{2+}) is correct because both ions have 10 electrons, making them isoelectronic.
169 Medium
169 of 227
Understanding +4 | -1
Which of the following obeys triad law :
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Correct option: D
Both (1) and (3)
Option D (Both (1) and (3)) is correct because both Li, Na, K and Be, Mg, Ca follow Dobereiner's Triad Law where the atomic mass of the middle element is approximately the average of the other two.
170 Medium
170 of 227
Understanding +4 | -1
Considering the elements F,   Cl,   OF,\,\,\,Cl,\,\,\,O and NN the correct order of their chemical reactivity in terms of oxidizing property is
View answer and explanation
Correct option: B
F>O>Cl>NF > O > Cl > N
Option B (F>O>Cl>NF > O > Cl > N) is correct because oxidizing power generally increases across a period and decreases down a group, with some exceptions due to factors like electron affinity and hydration enthalpy.
171 Medium
171 of 227
Remembering +4 | -1
Out of the four blocks in which periodic table is divided, helium belongs to which block?
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Correct option: B
pp-block
Option A (pp-block) is correct because, although helium has its differentiating electron in the s-orbital, it's placed in the p-block due to its noble gas properties.
172 Medium
172 of 227
Understanding +4 | -1
The first ionization potentials (eV)(\mathrm{eV}) of N{N} and O{O} respectively are
View answer and explanation
Correct option: D
11.32,8.2111.32,8.21
Option D (11.32, 8.21) is correct because Nitrogen has a half-filled p-orbital configuration, making it more stable and requiring more energy for ionization than Oxygen.
173 Medium
173 of 227
Understanding +4 | -1
Identify the correct order of the size of the following
View answer and explanation
Correct option: C
Ca2+<K+<Ar<Cl−<S2−{Ca}^{2+} < {K}^{+} < {Ar} < {Cl}^{-} < {S}^{2-}
Option C is correct because it correctly orders the given isoelectronic species based on their nuclear charge, with more positive charge leading to smaller size.
174 Medium
174 of 227
Analyzing +4 | -1
The first second and third ionisation energies (E1,E2  and  E3)\left( {{E_1},{E_2}\,\,and\,\,{E_3}} \right) for an element are 7  eV,12.5  eV7\,\,eV,12.5\,\,eV and 42.5  eV42.5\,\,eV respectively. The most stable oxidation state of the element will be
View answer and explanation
Correct option: D
+2+ 2
Option D (+2) is correct because the large jump in ionization energy after the second ionization indicates a stable +2 oxidation state.
175 Medium
175 of 227
Analyzing +4 | -1
In which of the following pairs the radii of second species is greater than that of first?
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Correct option: D
N,NeN, Ne
Option D (N,NeN, Ne) is correct because Neon (Ne) has Van der Waals radius, which is larger than the covalent radius of Nitrogen (N) in the same period.
176 Medium
176 of 227
Analyzing +4 | -1
Which one pair of atoms or ions will have same configuration?
View answer and explanation
Correct option: B
Cl−  and  Ar\mathrm{C}{\mathrm{l}^ - }\,\,and\,\,\mathrm{Ar}
Option D is correct because, according to Bohr's theory, the Coulombic force of attraction on the electron is proportional to Z2n4\frac{Z^2}{n^4}.
177 Medium
177 of 227
Analyzing +4 | -1
Which is not arranged in the correct sequence
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Correct option: A
d5,d3,d1,d4−\mathrm{d^5, d^3, d^1, d^4}- increasing magnetic moment
Option A (d5,d3,d1,d4−\mathrm{d^5, d^3, d^1, d^4}- increasing magnetic moment) is correct because the correct order for increasing magnetic moment is d1,d3,d4,d5\mathrm{d^1, d^3, d^4, d^5}.
178 Medium
178 of 227
Understanding +4 | -1
Assertion (A): Electron gain enthalpy becomes less negative as we go down a group.
Reason (R): Size of the atom increases on going down the group and the added electron would be farther away from the nucleus.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct; Reason is the correct explanation of Assertion
Option A is correct. As we go down a group, the atomic size increases, and the added electron experiences less attraction from the nucleus due to increased shielding, making the electron gain enthalpy less negative.
179 Medium
179 of 227
Analyzing +4 | -1
Assertion : Atomic radius of inert gases are largest in the period

Reason : Effective nuclear charge of inert gases are minimum
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Formic acid (HCOOH) reduces Tollen's reagent due to the presence of an aldehyde group. Therefore, the statement that it does not reduce Tollen's reagent is incorrect, making option D the correct answer.
180 Medium
180 of 227
Analyzing +4 | -1
The five successive ionisation enthalpies of an element are 800,2427,3658,25024  and  32824  kJ mol−1.\mathrm{800, 2427, 3658, 25024 \,\,and\,\, 32824\,\, kJ \,mo}{\mathrm{l}^{ - 1}}. The number of valence electrons in the element is
View answer and explanation
Correct option: A
3
Option A (3) is correct because there is a significant jump in ionization enthalpy after the third ionization, indicating that the element has 3 valence electrons.
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