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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Mixed difficulty

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Showing 391-420 of 494 questions

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391 Medium
391 of 494
Analyzing +4 | -1
About the species O2+,O22−,O2,O2−{O}_2^{+}, {O}_2^{2-}, {O}_2, {O}_2^{-}which one of the following statements is correct?
View answer and explanation
Correct option: C
The bond order of O2{O}_2 equals the average bond orders of O2+{O}_2^{+}and O2−{O}_2^{-}.
The bond order of O2{O}_2 equals the average bond orders of O2+{O}_2^{+}and O2−{O}_2^{-}because the bond order calculations confirm this relationship.
392 Medium
392 of 494
Analyzing +4 | -1
Assertion :- CH2=CH−CH=CH2\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2 is a planar compuond.

Reason :- It has 9σ9 \sigma bonds and 2π2 \pi bonds.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
The correct answer is B because both the assertion and reason are true, but the reason doesn't explain why the compound is planar.
393 Easy
393 of 494
Remembering +4 | -1
Hybridisation involves
View answer and explanation
Correct option: B
Mixing up of atomic orbitals
Option B (Mixing up of atomic orbitals) is correct because hybridization is the process of mixing atomic orbitals to form new hybrid orbitals with different energies, shapes, etc.
394 Easy
394 of 494
Understanding +4 | -1
Among the given species identify the isostructural pairs
View answer and explanation
Correct option: B
BF4−  and  NH4+BF_4^ - \,\,{\text{and}}\,\,NH_4^ +
Option B (BF4−  and  NH4+BF_4^ - \,\,{\text{and}}\,\,NH_4^ +) is correct because both ions have tetrahedral geometry and sp3 hybridization.
395 Medium
395 of 494
Analyzing +4 | -1
In which of the following transitions, the bond order has increased and the magnetic behaviour has changed
View answer and explanation
Correct option: A
C2+→C2{C_2}^ + \to {C_2}
Option A (C2+→C2{C_2}^ + \to {C_2}) is correct because the bond order increases from 1.5 to 2, and the magnetic behavior changes from paramagnetic to diamagnetic.
396 Medium
396 of 494
Analyzing +4 | -1
In which of the following groups all the members have linear shape?
View answer and explanation
Correct option: B
N3−,I3−,NO2+{N}_3^{-}, {I}_3^{-}, {NO}_2^{+}
Option B is correct because N3-, I3-, and NO2+ all have a linear shape.
397 Hard
397 of 494
Analyzing +4 | -1
The species having bond order different from that in COCO is
View answer and explanation
Correct option: A
NO−\mathrm{N}{\mathrm{O}^ - }
The correct answer is A (NO-) because NO- has a bond order of 2, while CO, NO+, CN-, and N2 all have a bond order of 3.
398 Easy
398 of 494
Understanding +4 | -1
The compound containing co-ordinate bond is
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because O3O_3, SO3SO_3, and H2SO4H_2SO_4 all contain coordinate bonds.
399 Easy
399 of 494
Understanding +4 | -1
Which of the following is most stable?
View answer and explanation
Correct option: A
H2H_2
Option A (H2H_2) is correct because it has the highest bond order and no antibonding electrons, making it the most stable.
400 Medium
400 of 494
Analyzing +4 | -1
N2{\mathrm{N}_2} and O2{\mathrm{O}_2} are converted into N2+\mathrm{N}_2^ + and O2+\mathrm{O}_2^ + respectively.
Which of the following is not correct?
View answer and explanation
Correct option: D
N2+\mathrm{N}_2^ + becomes diamagnetic
Option A (4) is correct because, based on general trends, four of the comparisons are correct concerning limiting molar conductivity.
401 Easy
401 of 494
Remembering +4 | -1
Debye an unit of dipole moment is of the order of:
View answer and explanation
Correct option: B
10−18{10^{ - 18}} esu cm
Option B (10−18{10^{ - 18}} esu cm) is correct because the Debye unit is defined as approximately 10−18{10^{ - 18}} electrostatic units times centimeters (esu cm).
402 Easy
402 of 494
Remembering +4 | -1
One Debye is equal to how many coulomb meter?
View answer and explanation
Correct option: A
3.33×10−303.33 \times 10^{-30}
Option A (3.33×10−303.33 \times 10^{-30}) is correct because 1 Debye is defined as 3.33×10−303.33 \times 10^{-30} Coulomb meter.
403 Medium
403 of 494
Understanding +4 | -1
In which of the molecules, bond angle is maximum
View answer and explanation
Correct option: D
CO2C{O_2}
Option D (CO2C{O_2}) is correct because carbon dioxide has a linear structure with a bond angle of 180°, which is the maximum among the given molecules.
404 Medium
404 of 494
Analyzing +4 | -1
The correct order of decreasing dipole moment of

(I) toluene

(II) m-dichlorobenzene

(III) o-dichlorobenzene

(IV) P-dichlorobenzene
View answer and explanation
Correct option: B
IV << I << II << III
Option B (IV << I << II << III) is correct because the dipole moment increases from para-dichlorobenzene (0) to toluene to meta-dichlorobenzene to ortho-dichlorobenzene.
405 Medium
405 of 494
Understanding +4 | -1
proton plays an important role in&hellip;bonding.
View answer and explanation
Correct option: D
Coordinate
Option D (Coordinate) is correct because a proton (H+) can accept a lone pair of electrons from a donor atom, which is the basis of coordinate bonding.

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406 Medium
406 of 494
Analyzing +4 | -1
Statement I: According to molecular orbital theory C2\mathrm{C}_2 molecules exist with bond order 2 .

Statement II: C2\mathrm{C}_2 molecule has 8 electrons in bonding molecular orbitals and 2 pair of electrons in anti-bonding molecular orbitals.
View answer and explanation
Correct option: A
Statement I and Statement II both are correct.
Option A is correct. Statement I and Statement II both are correct about the C2 molecule and its bond order.
407 Medium
407 of 494
Analyzing +4 | -1
Assertion : p-nitrophenol is more viscous than o-nitrophenol.

Reason : In p-nitrophenol, intermolecular compound H\mathrm{H}-bonding occurs.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because p-nitrophenol exhibits intermolecular hydrogen bonding, leading to higher viscosity compared to o-nitrophenol.
408 Medium
408 of 494
Understanding +4 | -1
Considering x axis as the intermolecular axis, which of the following will not form sigma bond?
View answer and explanation
Correct option: D
2py  and  2py\mathrm{2}{\mathrm{p}_y}\mathrm{ \,\,and\,\, 2}{\mathrm{p}_y}
Option D is correct. When the x-axis is the intermolecular axis, 2py2p_y and 2py2p_y orbitals will overlap sideways, forming a pi bond, not a sigma bond.
409 Medium
409 of 494
Remembering +4 | -1
The bond formed as a result of the electrostatic attraction between the positive and negative ions is termed as …
View answer and explanation
Correct option: B
Electrovalent bond
Option B (Electrovalent bond) is correct because electrovalent bonds are formed by the electrostatic attraction between positive and negative ions.
410 Medium
410 of 494
Application +4 | -1
A compound contains X,Y and ZX,\mathrm{ }Y\,and\,Z atoms. The oxidation states of X,Y and ZX,\mathrm{ }Y\,and\,Z are +2+ 2, +2+ 2 and −2- 2 respectively. The possible formula of the compound is
View answer and explanation
Correct option: A
XYZ2XY{Z_2}
Option A (XYZ₂) is correct because the charges must balance in a neutral compound, and with X and Y having +2 and Z having -2, the formula XYZ₂ achieves this balance.
411 Easy
411 of 494
Application +4 | -1
Chloride of metal is MCl2{MCl}_2. The formula of its phosphate will be
View answer and explanation
Correct option: B
M3(PO4)2{M}_3\left({PO}_4\right)_2
Option B (M3(PO4)2{M}_3\left({PO}_4\right)_2) is correct because if the metal chloride is MCl2{MCl}_2, the metal has a +2 charge, and phosphate has a -3 charge, leading to the formula M3(PO4)2{M}_3\left({PO}_4\right)_2.
412 Hard
412 of 494
Understanding +4 | -1
NF3\mathrm{N}{\mathrm{F}_3} is:
View answer and explanation
Correct option: C
Having low value of dipole moment than NH3\mathrm{N}{\mathrm{H}_3}
Option C (Having low value of dipole moment than NH3\mathrm{N}{\mathrm{H}_3}) is correct because in NF3\mathrm{N}{\mathrm{F}_3}, the bond dipoles and the lone pair dipole partially cancel each other, resulting in a lower dipole moment compared to NH3\mathrm{N}{\mathrm{H}_3}.
413 Medium
413 of 494
Understanding +4 | -1
Which of the following statement is correct?
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Correct option: A
Polarization of an anion is maximum by high charged cation
Option A (Polarization of an anion is maximum by high charged cation) is correct because according to Fajans' rule, higher charge on the cation increases polarization.
414 Medium
414 of 494
Understanding +4 | -1
Which is not linear?
View answer and explanation
Correct option: D
H2O{\mathrm{H}_2}\mathrm{O}
The correct answer is H2O{\mathrm{H}_2}\mathrm{O} because it has a bent or V-shaped geometry due to the two lone pairs on the oxygen atom, while the others are linear.
415 Medium
415 of 494
Analyzing +4 | -1
Which of the following species has a bond order other than 3?
View answer and explanation
Correct option: D
O2+\mathrm{O}_2^ +
The correct answer is D (O2+) because CO, CN-, and NO+ are isoelectronic, each having 14 electrons and a bond order of 3, while O2+ has 15 electrons and a bond order of 2.5.
416 Medium
416 of 494
Analyzing +4 | -1
Which of the following is false?
View answer and explanation
Correct option: D
Acetylene is non-linear
Option D (Acetylene is non-linear) is correct because acetylene (C2H2{\mathrm{C}_2}{\mathrm{H}_2}) is a linear molecule due to spsp hybridization of the carbon atoms.
417 Hard
417 of 494
Analyzing +4 | -1
The correct order of increasing intermolecular hydrogen bond strength is
View answer and explanation
Correct option: C
CH4<HCN<NH3C{H_4} < HCN < N{H_3}
Option C (CH4<HCN<NH3C{H_4} < HCN < N{H_3}) is correct because the hydrogen bond strength increases with the electronegativity difference between H and the other atom, and CH4 cannot form hydrogen bonds.
418 Hard
418 of 494
Application +4 | -1
The dipole moment of HBr{HBr} is 2.60×10−30 cm2.60 \times 10^{-30} {~cm} and the interatomic spacing is 1.41A∘1.41 \mathop {\text{A}}\limits^ \circ. What is the percent ionic character of HBr{HBr} ?
View answer and explanation
Correct option: B
11.5%11.5 \%
Option B (11.5 %) is correct because the percent ionic character is calculated by dividing the observed dipole moment by the calculated dipole moment and multiplying by 100.
419 Hard
419 of 494
Analyzing +4 | -1
Using MOT, compare O2+{O}_2^{+}and O2−{O}_2^{-}species and choose the incorrect option
View answer and explanation
Correct option: C
O2+{O}_2^{+}is diamagnetic while O2−{O}_2^{-}is paramagnetic
Option C is correct because both O2+ and O2- are paramagnetic due to the presence of unpaired electrons in their molecular orbital configurations.
420 Medium
420 of 494
Analyzing +4 | -1
Assertion (A) : The bond dissociation energy increases from F2{F}_2 to Cl2{Cl}_2 and then decreases to I2{I}_2

Reason (R): The low bond energy of fluorine is due to the repulsion between the lone pairs of electrons in two fluorine atoms.

The correct option among the following is :
View answer and explanation
Correct option: A
(A) is true, (R) is true and (R) is the correct explanation for (A)
The correct answer is A ((A) is true, (R) is true and (R) is the correct explanation for (A)) because the bond dissociation energy trend and the reason for fluorine's low bond energy are both accurate and related.
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