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JEE • CHEMISTRY • 14 TH GROUP ELEMENTS (P-BLOCK)

14 th group elements (p-block) practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 197 questions
151 Easy
151 of 197
Analyzing +4 | -1
Which of the following is not isostructural with SiF4Si{F_4} ?
View answer and explanation
Correct option: A
SF4S{F_4}
The correct answer is A (SF4) because SiF4, ClO4-, XeO4, and CCl4 are all tetrahedral, while SF4 has a see-saw shape due to the presence of a lone pair on the sulfur atom.
152 Easy
152 of 197
Understanding +4 | -1
Which among the following does not show catenation?
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Correct option: C
Pb\mathrm{Pb}
Option C (Pb\mathrm{Pb}) is correct because lead does not exhibit catenation due to its large size and weak bonding.
153 Medium
153 of 197
Remembering +4 | -1
In the sale of diamonds the unit of weight is carat. One carat is equal to:
View answer and explanation
Correct option: A
100 mg
Option D (200 mg) is correct because one carat, the unit of weight for diamonds, is equal to 200 milligrams.
154 Easy
154 of 197
Remembering +4 | -1
Bell metal is an alloy of :
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Correct option: B
Cu + Sn
Option B (Cu + Sn) is correct because bell metal is an alloy primarily composed of copper and tin.
155 Medium
155 of 197
Remembering +4 | -1
The major component/ingredient of Portland cement is
View answer and explanation
Correct option: B
tricalcium silicate
Option B is correct because tricalcium silicate (3CaO.SiO2) is the major component of Portland cement, contributing to its strength and hardening properties.
156 Easy
156 of 197
Remembering +4 | -1
Silicon is usually found in :
View answer and explanation
Correct option: A
Sand
Option A (Sand) is correct because sand is primarily composed of silica (SiO2\mathrm{SiO}_2), which is a compound of silicon and oxygen.
157 Medium
157 of 197
Remembering +4 | -1
Which of the following is the amorphous form of silica used in filtration plants?
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Correct option: D
Kieselguhr
Option D (Kieselguhr) is correct because Kieselguhr, an amorphous form of silica, is used in filtration plants due to its porous nature.
158 Easy
158 of 197
Remembering +4 | -1
The main constituents of coal gas are:
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Correct option: A
CH4+CO+H2\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}
Option A (CH4+CO+H2\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}) is correct because coal gas primarily consists of methane, carbon monoxide, and hydrogen.
159 Easy
159 of 197
Remembering +4 | -1
In laboratory silicon can be prepared by the reaction
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Correct option: A
Silica with magnesium
Option A (Silica with magnesium) is correct because silicon can be prepared in the laboratory by reducing silica (SiO2) with magnesium.
160 Medium
160 of 197
Understanding +4 | -1
The small increase in the covalent radii from Si\mathrm{Si} to Pb\mathrm{Pb} is due to the presence of
View answer and explanation
Correct option: B
completely filled dd and ff-orbitals in heavier members
Option B is correct because the presence of completely filled d and f orbitals in heavier members causes poor shielding, leading to a smaller increase in covalent radii than expected.
161 Easy
161 of 197
Remembering +4 | -1
The silicon compound which is used as lubricant and in cosmetic implant is
View answer and explanation
Correct option: C
Silicone
The correct answer is C (Silicone) because silicones are widely used as lubricants and in cosmetic implants due to their properties.
162 Medium
162 of 197
Remembering +4 | -1
Which fuel has the highest calorific value?
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Correct option: A
Coal gas
Option A (Coal gas) is correct because coal gas generally has a higher calorific value compared to water gas, producer gas, and carbon dioxide gas.
163 Easy
163 of 197
Remembering +4 | -1
Which is correct oxidation state of lead?
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Correct option: D
#ERROR!
Option D (+2, +4) is correct because lead exhibits +2 and +4 oxidation states due to the inert pair effect.
164 Medium
164 of 197
Analyzing +4 | -1
Which of the following has the minimum heat of dissociation?
View answer and explanation
Correct option: D
[(CH3)3N→B(CH3)3][{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N} \to \mathrm{B}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}]
Option D ([(CH3)3N→B(CH3)3][{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N} \to \mathrm{B}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}]) is correct because the steric hindrance is greatest in this option, leading to the weakest interaction and thus the minimum heat of dissociation.
165 Easy
165 of 197
Remembering +4 | -1
Glass reacts with HF to produce
View answer and explanation
Correct option: B
SiF4\mathrm{Si}{\mathrm{F}_4}
Option B (SiF4\mathrm{Si}{\mathrm{F}_4}) is correct because silicon dioxide in glass reacts with hydrofluoric acid to form silicon tetrafluoride and water.
166 Medium
166 of 197
Analyzing +4 | -1
Select Incorrect reaction ?
View answer and explanation
Correct option: B
H3BO3→ΔHBO2\mathrm{H}_3 \mathrm{BO}_3 \stackrel{\Delta}{\rightarrow} \mathrm{HBO}_2
Option A (A={A}= Excess, B={B}= Excess) is incorrect. Option B (A={A}= Limited, B={B}= Excess) is correct because with limited Cl₂, NH₃ is in excess, while with excess Cl₂, NH₃ is limiting.
167 Easy
167 of 197
Remembering +4 | -1
Carborundum is
View answer and explanation
Correct option: A
SiC\mathrm{SiC}
Option A (SiC\mathrm{SiC}) is correct because Carborundum is the common name for silicon carbide, which has the formula SiC\mathrm{SiC}.
168 Medium
168 of 197
Remembering +4 | -1
What is the state of hybridization of carbon in fullerene?
View answer and explanation
Correct option: A
sp2s{p^2}
Option A (sp2s{p^2}) is correct because each carbon atom in fullerene is bonded to three other carbon atoms, resulting in sp2s{p^2} hybridization.
169 Medium
169 of 197
Understanding +4 | -1
SiH4+O2\mathrm{Si}{\mathrm{H}_4} + {\mathrm{O}_2} mixture on bubbling through water and bubbles coming in contact with air:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because silane (SiH4\mathrm{Si}{\mathrm{H}_4}) reacts with oxygen to form silica and water, which can burn with a luminous flame and produce vortex rings of silica.
170 Easy
170 of 197
Remembering +4 | -1
Which element has a limited coordination number of four?
View answer and explanation
Correct option: B
C
Option C (Si) is incorrect. Option B (C) is correct because carbon, due to the absence of available d-orbitals in its valence shell, cannot expand its octet and thus has a maximum coordination number of four.
171 Medium
171 of 197
Analyzing +4 | -1
Select correct statement(s).
View answer and explanation
Correct option: D
All of the above.
Option D is correct because all the given statements about cyanamide ion, Mg₂C₃, and CaC₂ are correct.
172 Easy
172 of 197
Understanding +4 | -1
Which is not a characteristic property of carbon?
View answer and explanation
Correct option: C
Availability of d-orbitals for bonding
Option C (Availability of d-orbitals for bonding) is correct because carbon, being a second-period element, does not have d-orbitals available for bonding.
173 Easy
173 of 197
Remembering +4 | -1
The inert form of carbon is:
View answer and explanation
Correct option: A
Diamond
Option A (Diamond) is correct because diamond has a strong, rigid tetrahedral structure, making it chemically inert.
174 Medium
174 of 197
Remembering +4 | -1
The blue coloured mineral ‘Lapis Lazuli’ used as semiprecious stone is:
View answer and explanation
Correct option: A
Sodium alumino silicate
Option A (Sodium alumino silicate) is correct because Lapis Lazuli is a complex mineral primarily composed of sodium alumino silicate.
175 Hard
175 of 197
Remembering +4 | -1
Tin cry refers to :
View answer and explanation
Correct option: D
Emission of sound while bending a tin rod
Option D (Emission of sound while bending a tin rod) is correct because tin cry refers to the characteristic sound produced when a tin rod is bent.
176 Medium
176 of 197
Analyzing +4 | -1
If C(diamond)→C(graphite)+X kJ mol−1\mathrm{C}(\text {diamond})\rightarrow \mathrm{C}(\text {graphite})+\mathrm{X} \mathrm{~kJ} \mathrm{~mol}^{-1}

C(diamond)+O2(g)→CO2(g)+Y kJ mol−1C(graphite)+O2(g)→CO2(g)+Z kJ mol−1\begin{aligned} & \mathrm{C}(\text {diamond})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+\mathrm{Y} \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{C}(\text {graphite})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+\mathrm{Z~kJ} \mathrm{~mol}^{-1} \end{aligned}

At constant temperature. Then
View answer and explanation
Correct option: D
X = Y – Z
Option D (X = Y – Z) is correct because it is derived from Hess's Law by manipulating the given thermochemical equations.
177 Medium
177 of 197
Remembering +4 | -1
The anion present in the cyclic structure of silicates is
View answer and explanation
Correct option: C
SiO32−{SiO}_3^{2-}
Option C (SiO32−{SiO}_3^{2-}) is correct because it represents the basic repeating unit in cyclic silicates where two oxygen atoms are shared.
178 Medium
178 of 197
Understanding +4 | -1
Tungsten carbides is an example of:
View answer and explanation
Correct option: D
Interstitial solid solution
Option D is correct because tungsten carbides are formed when small carbon atoms occupy the interstitial spaces within the tungsten lattice structure, making it an interstitial solid solution.
179 Medium
179 of 197
Remembering +4 | -1
Colour is imparted to glass by mixing:
View answer and explanation
Correct option: B
Metal oxides
Option B (Metal oxides) is correct because the addition of different metal oxides to glass during its production imparts various colors.
180 Medium
180 of 197
Remembering +4 | -1
The compound that is white in colour is
View answer and explanation
Correct option: B
lead sulphate
Option B (lead sulphate) is correct because lead sulphate is a white solid.
Revision notes and key takeaways

Review 14 TH GROUP ELEMENTS (P-BLOCK) in your textbook or class notes, then use this set to check your understanding.

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