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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Medium

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61 Medium
61 of 98
Understanding +4 | -1
Borax→ Excess ΔNaBO2+(B)(B)+Nickel oxide→Δ(C)\begin{gathered} {\text{Borax}}\xrightarrow[{{\text{ Excess }}}]{\Delta }{\text{NaB}}{{\text{O}}_2} + {\text{(B)}} \quad \\ {\text{(B)}} + {\text{Nickel oxide}}\xrightarrow{\Delta }{\text{(C)}} \quad \\ \end{gathered}

Compound C\mathrm{C} and its colour is
View answer and explanation
Correct option: C
Ni(BO2)2\mathrm{Ni}\left(\mathrm{BO}_2\right)_2, yellow
Option C (Ni(BO2)2\mathrm{Ni(BO_2)_2}, yellow) is correct because Nickel oxide reacts with Boric anhydride to form Nickel metaborate, which is yellow in color.
62 Medium
62 of 98
Understanding +4 | -1
Consider the following statements:-
a) Borax dissolves in water to give an alkaline solution
b) Boric acid is weak monobasic protonic acid
c) H3BO3{\mathrm{H}_\mathrm{3}}\mathrm{B}{\mathrm{O}_\mathrm{3}} has layered structure in which BO3\mathrm{B}{\mathrm{O}_\mathrm{3}} units are joined by hydrogen bonds
The incorrect statement(s) is/are:
View answer and explanation
Correct option: B
(b) only
Option B (b) only) is correct because Boric acid is a weak monobasic Lewis acid, not a protonic acid.
63 Medium
63 of 98
Understanding +4 | -1
The exhibition of highest coordination number depends on the availability of vacant orbitals in the central atom. Which of the following elements is not likely to act as central atom in MF63−\mathrm{MF}_6^{3-} ?
View answer and explanation
Correct option: A
B\mathrm{B}
Option A (B) is correct because Boron does not have vacant d-orbitals and cannot expand its coordination number to 6.
64 Medium
64 of 98
Analyzing +4 | -1
Na2B4O7⋅10H2O⟶ΔX+NaBO2+H2OX+Cr2O3⟶ΔY( Green coloured )X and Y are \begin{aligned} & {Na}_2 {B}_4 {O}_7 \cdot 10 {H}_2 {O} \stackrel{\Delta}{\longrightarrow} {X}+{NaBO}_2+{H}_2 {O} \\ & {X}+{Cr}_2 {O}_3 \stackrel{\Delta}{\longrightarrow} {Y}(\text { Green coloured }) \\ & {X} \text { and } {Y} \text { are } \end{aligned}
View answer and explanation
Correct option: C
B2O3 and Cr2(BO2)3{B}_2 {O}_3 \text { and } {Cr}_2\left({BO}_2\right)_3
Option D (B2O3B_2O_3 and CrBO3CrBO_3) is incorrect. The correct products are B2O3B_2O_3 and Cr(BO2)3Cr(BO_2)_3.
65 Medium
65 of 98
Analyzing +4 | -1
B2H6{B}_2 {H}_6 can't be prepared by:
View answer and explanation
Correct option: C
B3N3H6+H2O→{B}_3 {N}_3 {H}_6+{H}_2 {O} \rightarrow
Option C is correct because the reaction of B3N3H6{B}_3 {N}_3 {H}_6 with H2O{H}_2 {O} produces H3BO3{H}_3 {BO}_3, NH3{NH}_3, and H2{H}_2, not B2H6{B}_2 {H}_6.
66 Medium
66 of 98
Analyzing +4 | -1
Which of the following has the minimum heat of dissociation:
View answer and explanation
Correct option: C
(CH3)3 N:→B(CH3)3\left(\mathrm{CH}_3\right)_3 \mathrm{~N}: \rightarrow \mathrm{B}\left(\mathrm{CH}_3\right)_3
Option C is correct because the complex with B(CH3)3 has the minimum heat of dissociation due to the +I effect of methyl groups decreasing the Lewis acidity of boron.
67 Medium
67 of 98
Application +4 | -1
B—F bond order in BF3\mathrm{B}{\mathrm{F}_3} is:
View answer and explanation
Correct option: D
4/34/3
Option D (4/34/3) is correct because the B-F bond order in BF3\mathrm{B}{\mathrm{F}_3} is influenced by back bonding, resulting in a value greater than 1.
68 Medium
68 of 98
Understanding +4 | -1
Consider the given statements regarding the properties of boron.

I. It is a hard refractory solid.

II. It has low melting point and high density.

III. It shows high electrical conductivity.
Choose the correct statement(s).
View answer and explanation
Correct option: A
Only I
Option A (Only I) is correct because boron is a hard, refractory solid with a high melting point and low electrical conductivity, making statements II and III incorrect.
69 Medium
69 of 98
Understanding +4 | -1
Observe the following statements
1) H3BO3{\mathrm{H}_\mathrm{3}}\mathrm{B}{\mathrm{O}_3} is used as antiseptic
2) In B2H6{\mathrm{B}_\mathrm{2}}{\mathrm{H}_\mathrm{6}} each Boron atom is SP2\mathrm{S}{\mathrm{P}^\mathrm{2}} hybridisation
3) An aqueous solution of borax is alkaline in nature
The correct statements are
View answer and explanation
Correct option: D
1 and 3
Option D (1 and 3) is correct because boric acid (H3BO3) is used as an antiseptic, and an aqueous solution of borax is alkaline, while in B2H6 each Boron atom is sp3 hybridized.
70 Medium
70 of 98
Understanding +4 | -1
The similarities among the trichlorides, tribromides and triiodides of all group-13 elements is/are that they are
View answer and explanation
Correct option: C
Both 1 and 2
Option C is correct. Trichlorides, tribromides, and triiodides of group-13 elements are covalent in nature and undergo hydrolysis in water.
71 Medium
71 of 98
Remembering +4 | -1
The formula of potash alum is
View answer and explanation
Correct option: A
K2SO4.Al2(SO4)3.24H2O{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.A}{\mathrm{l}_2}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}.24{\mathrm{H}_2}\mathrm{O}
Option A (K2SO4.Al2(SO4)3.24H2O{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.A}{\mathrm{l}_2}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}.24{\mathrm{H}_2}\mathrm{O}) is correct because it represents the correct formula for potash alum, a double salt.
72 Medium
72 of 98
Remembering +4 | -1
Which compound can make fire proof clothes?
View answer and explanation
Correct option: A
Aluminium sulphate
Option A (Aluminium sulphate) is correct because aluminium sulphate is used in the treatment of fabrics to make them fire-resistant.
73 Medium
73 of 98
Remembering +4 | -1
For a good quality cement, the ratio of lime to the total of the oxides of Si,Al\mathrm{Si}, \mathrm{Al} and Fe\mathrm{Fe} should be as close as to
View answer and explanation
Correct option: C
2
Option C (2) is correct because the ideal ratio of lime to the total oxides of Si, Al, and Fe in good quality cement is approximately 2.
74 Medium
74 of 98
Analyzing +4 | -1
Assertion (A) : B2Cl4,GaCl2,GaS{B}_2 {Cl}_4, {GaCl}_2, {GaS} are diamagnetic.

Reason (R) : They show +2 oxidation state.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B (Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}) is correct because while both the assertion and reason are true, the +2 oxidation state is not the direct reason for diamagnetism.
75 Medium
75 of 98
Understanding +4 | -1
In which of the following reactions, diborane is not formed?
View answer and explanation
Correct option: D
Na2 B4O7+HCl+H2O⟶\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}+\mathrm{H}_2 \mathrm{O} \longrightarrow
Option D (Na2 B4O7+HCl+H2O⟶\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}+\mathrm{H}_2 \mathrm{O} \longrightarrow) is correct because this reaction forms boric acid, not diborane.
76 Medium
76 of 98
Remembering +4 | -1
The industrial scale production of diborane involves the reaction of BF3\mathrm{BF}_3 with
View answer and explanation
Correct option: B
sodium hydride
Option B (sodium hydride) is correct because the industrial production of diborane involves the reaction of BF3 with sodium hydride.
77 Medium
77 of 98
Remembering +4 | -1
Which of the following element is the most abundant metal and the third most abundant element in the earth's crust?
View answer and explanation
Correct option: A
Al\mathrm{Al}
Option A (Al\mathrm{Al}) is correct because aluminum is the most abundant metal and the third most abundant element in the Earth's crust.
78 Medium
78 of 98
Analyzing +4 | -1
An inorganic compound containing (3c−2e−)\left(3 c-2 e^{-}\right)and (2c−2e−)\left(2 c-2 e^{-}\right) bonds when reacts with NH3\mathrm{NH}_3, at a certain temperature, gives a compound ' XX ' which is isostructural with benzene and when reacts at high temperature forms a substance YY '. The substance ' YY ' is
View answer and explanation
Correct option: A
B2H6\mathrm{B}_2 \mathrm{H}_6
Option B (Na2O2\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}) is correct because the oxygen in sodium peroxide has an oxidation state of -1, which can be both oxidized and reduced.
79 Medium
79 of 98
Understanding +4 | -1
The type of hybridisation in diborane is:
View answer and explanation
Correct option: B
sp3s p^3
Option B (sp3sp^3) is correct because in diborane, each boron atom is sp3sp^3 hybridized.
80 Medium
80 of 98
Remembering +4 | -1
Alum is not used:
View answer and explanation
Correct option: B
As an insecticide
Option B (As an insecticide) is correct because Alum is not used as an insecticide; it is primarily used as a mordant in dyeing, in water purification, and in leather tanning.
81 Medium
81 of 98
Analyzing +4 | -1
Assertion (A): In bivalent state, most of the halides of group 13 elements are hydrolysed in water.

Reason (R): These are covalent in nature.
View answer and explanation
Correct option: D
A\mathrm{A} is incorrect; R\mathrm{R} is correct.
Option C (Work function of BB is 1.20 eV1.20 \mathrm{~eV}) is incorrect because the work function of B is calculated to be 4.2 eV based on the given conditions.
82 Medium
82 of 98
Analyzing +4 | -1
Which does not exist?
View answer and explanation
Correct option: A
B3+{\mathrm{B}^{3 + }}
The correct answer is A (B3+) because boron's high ionization energy and small size make it extremely unlikely to form a stable B3+ ion.
83 Medium
83 of 98
Remembering +4 | -1
Aluminium reacts with caustic soda to form
View answer and explanation
Correct option: C
Sodium meta-aluminate
Option C (Sodium meta-aluminate) is correct because aluminium reacts with caustic soda (NaOH) to form sodium meta-aluminate (NaAlO2NaAlO_2) and hydrogen gas.
84 Medium
84 of 98
Remembering +4 | -1
Nickeloy is an alloy containing:
View answer and explanation
Correct option: C
Ni+Al+Cu\mathrm{Ni} + \mathrm{Al} + \mathrm{Cu}
Option C (Ni+Al+Cu\mathrm{Ni} + \mathrm{Al} + \mathrm{Cu}) is correct because Nickeloy is an alloy composed of Nickel, Aluminum, and Copper.
85 Medium
85 of 98
Remembering +4 | -1
The salt used for performing bead test in qualitative inorganic analysis is:
View answer and explanation
Correct option: C
Na(NH4)HPO4⋅4H2O{Na}\left({NH}_4\right) {HPO}_4 \cdot 4 {H}_2 {O}
Option C (Na(NH4)HPO4⋅4H2O{Na}\left({NH}_4\right) {HPO}_4 \cdot 4 {H}_2 {O}) is correct because microcosmic salt, which is sodium ammonium hydrogen phosphate, is used in the bead test.
86 Medium
86 of 98
Understanding +4 | -1
Orthoboric acid
View answer and explanation
Correct option: D
Accept OH−\mathrm{OH}^{-}to form [B(OH)4]−\left[\mathrm{B}(\mathrm{OH})_4\right]^-
Option D (Accept OH−\mathrm{OH}^{-}to form [B(OH)4]−\left[\mathrm{B}(\mathrm{OH})_4\right]^-) is correct because orthoboric acid acts as a Lewis acid, accepting a hydroxide ion to form the tetrahydroxyborate(1-) ion.
87 Medium
87 of 98
Understanding +4 | -1
In [Al(H2O)6]3+\left[{Al}\left({H}_2{O}\right)_6\right]^{3+} ion, the hybridisation state of Al{Al} and the shape of the ion respectively are
View answer and explanation
Correct option: C
sp3d2{sp}^3{d}^2, octahedral
Option C (sp3d2{sp}^3{d}^2, octahedral) is correct because the aluminum ion is surrounded by six water ligands, resulting in sp3d2sp^3d^2 hybridization and an octahedral geometry.
88 Medium
88 of 98
Remembering +4 | -1
Thermite is a mixture of
View answer and explanation
Correct option: B
Fe2O3+Al\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Al}
Option B (Fe2O3+Al\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Al}) is correct because thermite is a mixture of iron(III) oxide and aluminum.
89 Medium
89 of 98
Analyzing +4 | -1
BF3+LiAlH4⟶ Ether X+LiF+AlF3\mathrm{BF}_3+\mathrm{LiAlH}_4 \stackrel{\text { Ether }}{\longrightarrow} \mathrm{X}+\mathrm{LiF}+\mathrm{AlF}_3. Which of the following is incorrect about X\mathrm{X}?
View answer and explanation
Correct option: C
Vacant orbital is not involved in bonding
The incorrect statement is C (Vacant orbital is not involved in bonding) because diborane (B2H6) has vacant orbitals involved in banana bond formation.
90 Medium
90 of 98
Understanding +4 | -1
Which among the following statements are correct?
(i)Carbon monoxide is neutral whereas SO3S{O_3} is acidic.
(ii)Potassium oxide is basic whereas nitrous oxide is acidic.
(iii) Aluminium and zinc oxides are amphoteric.
(iv) Sulphur trioxide is acidic whereas phosphorus pentoxide is basic.
(v) Carbon dioxide is neutal whereas sulphur dioxide is amphoteric
View answer and explanation
Correct option: C
(i) and (iii)
Option C ((i) and (iii)) is correct because carbon monoxide is neutral, sulfur trioxide is acidic, and aluminum and zinc oxides are amphoteric.
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