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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Medium

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31 Medium
31 of 98
Analyzing +4 | -1
A compound (A)(A) of boron reacts with NMe3\mathrm{NMe}_3 to give an adduct (B)(B) which on hydrolysis gives a compound (C)(C) and hydrogen gas. Compound (C)(C) is an acid. The adduct (B)(B) is
View answer and explanation
Correct option: B
2BH3⋅NMe32 \mathrm{BH}_3 \cdot \mathrm{NMe}_3
Option D (BH3⋅NMe3\mathrm{BH}_3 \cdot \mathrm{NMe}_3) is incorrect. The correct answer should be 2BH3⋅NMe32 \mathrm{BH}_3 \cdot \mathrm{NMe}_3 because diborane (B2H6B_2H_6) reacts with two molecules of NMe3NMe_3.
32 Medium
32 of 98
Remembering +4 | -1
In Hall-Heroult process, the following is used for reducing Al2O3\mathrm{Al}_{2} \mathrm{O}_{3} :-
View answer and explanation
Correct option: C
Graphite
Option C (Graphite) is correct because graphite is used as the anode in the Hall-Héroult process to reduce aluminum oxide to aluminum.
33 Medium
33 of 98
Remembering +4 | -1
The element which exists in liquid state for a wide range of temperature and can be used for measuring high temperature is
View answer and explanation
Correct option: C
GaGa
The correct answer is C (GaGa) because Gallium (Ga) has a relatively low melting point and a high boiling point, allowing it to exist in the liquid state over a wide temperature range.
34 Medium
34 of 98
Understanding +4 | -1
Assertion (A) : Aluminium trimethyl is a dimer having structure like that of AlCl3{AlCl}_3.

Reason (R) : There is three-centre two-electron bonding in Al−C−Al{Al}-{C}-{Al} bridge.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B (Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.) is correct because aluminum trimethyl does form a dimer, and it does involve three-center two-electron bonding, but the bonding is the *reason* it forms a dimer, not a separate fact.
35 Medium
35 of 98
Remembering +4 | -1
The precious stone aquamarine is:
View answer and explanation
Correct option: B
Be-Al silicate
Option B (Be-Al silicate) is correct because aquamarine is a variety of beryl, which is a beryllium aluminum silicate mineral.
36 Medium
36 of 98
Understanding +4 | -1
Consider the following reaction

H3BO3→ΔA→ΔRed  hotB{H_3}B{O_3}\xrightarrow{\Delta }A\xrightarrow[\Delta ]{{{\text{Red}}\,\,{\text{hot}}}}B

AA and BB respectively are
View answer and explanation
Correct option: C
HBO2,B2O3{HBO}_2,{B}_2 {O}_3
Option C (HBO2,B2O3{HBO}_2,{B}_2 {O}_3) is correct because boric acid (H3BO3{H_3}B{O_3}) on heating gives metaboric acid (HBO2{HBO}_2), which on further heating gives boron trioxide (B2O3{B_2} {O_3}).
37 Medium
37 of 98
Analyzing +4 | -1
Consider the following statement about the following reactions :

AA : 2H2O(l)+2 F2( g)→4HF(g)+O2( g)2 {H}_2 {O}({l})+2 {~F}_2({~g}) \rightarrow 4 {HF}({g})+{O}_2({~g})

BB : BF3+HF→HBF4{BF}_3+{HF} \rightarrow {HBF}_4

I. Reaction (AA) is redox reaction whereas reaction (B)(B) is acid-base reaction

II. In reaction (AA) H2O{H}_2 {O} is oxidising agent.

III. In reaction (B),BF3({B}), {BF}_3 is Lewis base.

Choose the correct statement(s) :
View answer and explanation
Correct option: A
Only I
Option A (Only I) is correct because reaction A is a redox reaction, and reaction B is an acid-base reaction.
38 Medium
38 of 98
Understanding +4 | -1
Amorphous boron on burning in air forms:
View answer and explanation
Correct option: B
Mixture of B2O3{\mathrm{B}_2}{\mathrm{O}_3} and BN
Option B (Mixture of B2O3{\mathrm{B}_2}{\mathrm{O}_3} and BN) is correct because amorphous boron reacts with both oxygen and nitrogen in the air upon burning.
39 Medium
39 of 98
Application +4 | -1
In the reaction B2O3+C+Cl2→A+CO.{\mathrm{B}_2}{\mathrm{O}_3} + \mathrm{C} + \mathrm{C}{\mathrm{l}_2} \to A + \mathrm{CO}. The A is
View answer and explanation
Correct option: B
BCl3\mathrm{BC}{\mathrm{l}_3}
Option B (BCl3\mathrm{BC}{\mathrm{l}_3}) is correct because it is the product formed when boron oxide reacts with carbon and chlorine.
40 Medium
40 of 98
Remembering +4 | -1
Which of the following is not correct in case of boron nitride?
View answer and explanation
Correct option: D
It has magnetic properties
The correct answer is D (It has magnetic properties) because boron nitride (BN) does not have unpaired electrons and therefore does not exhibit magnetic properties.
41 Medium
41 of 98
Understanding +4 | -1
Diborane cannot be obtained from
View answer and explanation
Correct option: A
Na2 B4O7+HCl\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}
Option A (Na2 B4O7+HCl\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}) is correct because the reaction of borax with hydrochloric acid produces boric acid, not diborane.
42 Medium
42 of 98
Analyzing +4 | -1
The incorrect statement reading ‘x’ in the reaction is BF3+LiAlH4→Ether(x)+LiF+AlF3B{F_3} + LiAl{H_4}\xrightarrow{{\mathrm{Ether}}}\left( x \right) + LiF + Al{F_3}
View answer and explanation
Correct option: D
Structure of ‘x’ is similar to C2H6{C_2}{H_6}
The correct answer is D (If assertion is false but reason is true) because the unit of Kp is atm(Δn), and for the given reaction, Δn = 2, so the unit of Kp is atm². The assertion incorrectly states the unit is atm.
43 Medium
43 of 98
Remembering +4 | -1
13th{13^{th}} group element with least melting point is:
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Correct option: A
Ga
Option A (Ga) is correct because Gallium (Ga) has the lowest melting point among the 13th group elements.
44 Medium
44 of 98
Analyzing +4 | -1
Standard electrode potential values, ESE^{{S}} for Al3+/Al{Al}^{3+} / {Al} is −1.66 V-1.66 \mathrm{~V} and that of Tl3+/Tl{Tl}^{3+} / {Tl} is +1.26 V+1.26 \mathrm{~V}. Which of the following is incorrect regarding the given information?
View answer and explanation
Correct option: A
Tl3+{Tl}^{3+} is a powerful reducing agent.
Option A (Tl3+{Tl}^{3+} is a powerful reducing agent.) is incorrect because Tl3+{Tl}^{3+} is a powerful oxidizing agent, not a reducing agent, due to its high positive standard electrode potential.
45 Medium
45 of 98
Understanding +4 | -1
Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R:

Assertion A : The stability order of +1 oxidation state of Ga\mathrm{Ga}, In\mathrm{In} and Tl\mathrm{Tl} is Ga<In<Tl\mathrm{Ga} < \mathrm{In} < \mathrm{Tl}.

Reason R : The inert pair effect stabilizes the lower oxidation state down the group.

In the light of the above statements, choose the correct answer from the options given below :
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are true and R\mathrm{R} is the correct explanation of A\mathrm{A}.
Option A is correct because the inert pair effect increases down the group, stabilizing the +1 oxidation state in Tl more than in Ga or In.
46 Medium
46 of 98
Understanding +4 | -1
Boric acid is an acid because its molecule
View answer and explanation
Correct option: D
Accepts OH−O{H^ - } from water releasing proton
Option D (Accepts OH−O{H^ - } from water releasing proton) is correct because Boric acid acts as a Lewis acid by accepting a hydroxide ion from water, releasing a proton.
47 Medium
47 of 98
Remembering +4 | -1
In borax bead test which compound is formed?
View answer and explanation
Correct option: B
Meta-borate
Option B (Meta-borate) is correct because in the borax bead test, metal oxides react with boric anhydride to form metaborates.
48 Medium
48 of 98
Understanding +4 | -1
Anodised aluminium is:
View answer and explanation
Correct option: D
Al electrolytically coated with aluminium oxide
Option D (Al electrolytically coated with aluminium oxide) is correct because anodization is an electrolytic passivation process used to increase the thickness of the natural oxide layer on the surface of aluminium.
49 Medium
49 of 98
Remembering +4 | -1
In which of the following compound '3C-2e' bonds are present:
View answer and explanation
Correct option: A
B2H6\mathrm{B}_2 \mathrm{H}_6
Option A (B2H6\mathrm{B}_2 \mathrm{H}_6) is correct because diborane contains 3-center-2-electron bonds in its structure.
50 Medium
50 of 98
Remembering +4 | -1
Boric acid is not used:
View answer and explanation
Correct option: B
As a flux in soldering
Option A (As a flux in soldering) is correct because boric acid is not typically used as a flux in soldering; fluxes are usually made of other materials.
51 Medium
51 of 98
Understanding +4 | -1
When Al is added to KOH solution
View answer and explanation
Correct option: A
Hydrogen is evolved
Option A (Hydrogen is evolved) is correct because aluminum reacts with KOH to form potassium aluminate and hydrogen gas.
52 Medium
52 of 98
Understanding +4 | -1
Na2B4O7⋅10H2O{Na}_2 {B}_4 {O}_7 \cdot 10 {H}_2 {O} is correctly represented by
View answer and explanation
Correct option: A
Na2[B4O5(OH)4]⋅8H2O{Na}_2\left[{B}_4 {O}_5({OH})_4\right] \cdot 8 {H}_2 {O}
Option A (Na2[B4O5(OH)4]⋅8H2O{Na}_2\left[{B}_4 {O}_5({OH})_4\right] \cdot 8 {H}_2 {O}) is correct because it is the correct chemical formula representation of Borax.
53 Medium
53 of 98
Remembering +4 | -1
Orthoboric acid when heated to red hot, gives :
View answer and explanation
Correct option: D
diboron trioxide
Option D (diboron trioxide) is correct because orthoboric acid, when heated strongly, dehydrates to form metaboric acid, then pyroboric acid, and finally boron trioxide.
54 Medium
54 of 98
Analyzing +4 | -1
Which one of the following has the highest Lewis acid strength?
View answer and explanation
Correct option: A
BI3{BI}_3
The correct answer is A (BI3) because, due to back bonding limitations, BI3 is the strongest Lewis acid among the given options.
55 Medium
55 of 98
Understanding +4 | -1
Which of the following pair have almost the same atomic radii
View answer and explanation
Correct option: D
Al, GaAl,\,Ga
Option D is correct because Aluminum and Gallium have almost the same atomic radii due to the d-orbital contraction in Gallium.
56 Medium
56 of 98
Understanding +4 | -1
Select a correct statement about boric acid
View answer and explanation
Correct option: C
It is a Lewis acid
Option C (It is a Lewis acid) is correct because boric acid accepts a hydroxide ion from water, acting as a Lewis acid rather than a Bronsted acid.
57 Medium
57 of 98
Remembering +4 | -1
Diborane is prepared on large scale by
View answer and explanation
Correct option: A
2BF3(g)+6LiH(s)⟶450 KB2H6(g)+6LiF(s)2 \mathrm{BF}_3(\mathrm{g})+6 \mathrm{LiH}(\mathrm{s}) \stackrel{450 \mathrm{~K}}{\longrightarrow} \mathrm{B}_2 \mathrm{H}_6(\mathrm{g})+6 \mathrm{LiF}(\mathrm{s})
Option A (2BF3(g)+6LiH(s)⟶450 KB2H6(g)+6LiF(s)2 \mathrm{BF}_3(\mathrm{g})+6 \mathrm{LiH}(\mathrm{s}) \stackrel{450 \mathrm{~K}}{\longrightarrow} \mathrm{B}_2 \mathrm{H}_6(\mathrm{g})+6 \mathrm{LiF}(\mathrm{s})) is correct because this reaction is a standard method for large-scale preparation of diborane.
58 Medium
58 of 98
Understanding +4 | -1
Assertion (A) : B(OH)3\mathrm{B}(\mathrm{OH})_3 is a good lubricant and slippery.

Reason (R) : B(OH)3\mathrm{B}(\mathrm{OH})_3 has a layer structure.
View answer and explanation
Correct option: A
Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.
Option A (Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.) is correct because boric acid, B(OH)3B(OH)_3, has a layered structure which allows it to act as a lubricant.
59 Medium
59 of 98
Analyzing +4 | -1
The correct statements among the following is;

(I) Boric acid is a weak monobasic lewis acid.

(II) Boron trioxide is acidic and reacts with basic (metallic) oxides forming metal borates.

(III) Oxides of indium and thallium are amphoteric.
View answer and explanation
Correct option: C
I and II only
The correct answer is I and II only because Boric acid is a weak monobasic Lewis acid, Boron trioxide is acidic, but oxides of Indium and Thallium are basic.
60 Medium
60 of 98
Understanding +4 | -1
The relative stability of +1 oxidation state of group 13 elements follows the order
View answer and explanation
Correct option: B
Al<Ga<In<TlAl < Ga < In < Tl
Option B (Al<Ga<In<TlAl < Ga < In < Tl) is correct because the stability of the +1 oxidation state increases down the group due to the inert pair effect.
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