If $y = c{e^{x/\left( {x - a} \right)}}$, then $\frac{{dy}}{{dx}}$ equals

${a^2}{\left( {x - a} \right)^2}$

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y = c{e^{x/\left( {x - a} \right)}}

, then

\frac{{dy}}{{dx}}

equals

View answer and explanation

Correct option: B

- \frac{{ay}}{{{{\left( {x - a} \right)}^2}}}

Option B (

- \frac{{ay}}{{{{\left( {x - a} \right)}^2}}})

is correct because it is the result of applying the chain rule and quotient rule correctly during differentiation.

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