JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

x

and

y

be two real numbers such that

x>0

and

x y=1

. The minimum value of

x+y

View answer and explanation

Correct option: C

Option C (2) is correct because the minimum value of x+y, given xy=1 and x>0, is 2, which can be found using calculus or AM-GM inequality.

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