JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

z = y + f\left( v \right),

where

v = \left( {\frac{x}{y}} \right),

then

v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}

View answer and explanation

Correct option: B

Option B (1) is correct because after partial differentiation and substitution, the terms involving the function f' cancel out, leaving 1.

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