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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
The number of values of a for which the system of equation 2∣x∣+∣x∣=y+x2+a{2^{\left| x \right|}} + \left| x \right| = y + {x^2} + a and x2+y2=1{x^2} + {y^2} = 1 has only one solution where a,x,ya,x,y are real, is
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Correct option: A
1
Option A (1) is correct because by analyzing the symmetry of the equations, we find that there is only one value of 'a' for which the system has a unique solution.

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