If $f\left( x \right) = a{x^2} + bx + c\;$ and $\;f\left( { - 1} \right) - 1,f\left( 3 \right) < - 4\;$ and $\;a \ne 0,$ then

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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f\left( x \right) = a{x^2} + bx + c\;

and

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

and

\;a \ne 0,

then

View answer and explanation

Correct option: B

a < 0

Option B (

a < 0

) is correct because the given conditions on f(-1), f(1), and f(3) lead to a negative value for 'a' after solving the inequalities.

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