Question

If $\alpha ,\;\beta $ be the roots of the equation ${x^2} - px + q = 0$ and ${\alpha _1},{\beta _1}$ be the roots of the equation ${x^2} - qx + p = 0,$ then the equation whose roots are $\frac{1}{{{\alpha _1}\beta }} + \frac{1}{{\alpha {\beta _1}}}{\rm{and}}\;\frac{1}{{\alpha {\alpha _1}}} + \frac{1}{{\beta {\beta _1}}},$ is

Accepted Answer

${p^2}{q^2}{x^2} - {p^2}{q^2}x + {p^3} + {q^3} - 4pq = 0$

Answer

$pq{x^2} - pqx + {p^2} + {q^2} + 4qp = 0$

Answer

${p^3}{q^3}{x^2} - {p^3}{q^3}x + {p^4} + {q^4} - 4{p^2}{q^2} = 0$

Answer

$\left( {p + q} \right){x^2} - \left( {p + q} \right)x + {p^2} + {q^2} = 0$

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

More Questions from QUADRATIC EQUATIONS