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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If y=1+x+x22!+x33!+⋯∞y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\cdots \infty, then dydx\frac{d y}{d x} is equal to
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Correct option: A
yy
Option A (yy) is correct because the derivative of the given series, which represents exe^x, is equal to the original series.

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