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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If x=2cosec⁡−1tx=\sqrt{2^{\operatorname{cosec}^{-1} t}} and y=2sec⁡−1t(∣t∣≥1)y=\sqrt{2^{\sec ^{-1} t}}(|\mathrm{t}| \geq 1), then dydx\frac{d y}{d x} is equal to.
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Correct option: B
−yx-\frac{y}{x}
Option B (−yx-\frac{y}{x}) is correct because it is the derivative calculated using the relationship between inverse trigonometric functions.

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