If $ y=\frac{e^{x} \log x}{x^{2}} $, then $ \frac{d y}{d x} $ is equal to

$ \frac{e^{x}[1-(x-2) \log x]}{x^{4}} $

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\frac{e^{x} \log x}{x^{2}}

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: D

\frac{e^{x}[1+(x-2) \log x]}{x^{3}}

Option D is correct because the derivative is found using the product and quotient rules, simplifying to the given expression.

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