JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

u=f\left(x^3\right), v=g\left(x^2\right), f^{\prime}(x)=\cos x

and

g^{\prime}(x)=\sin x

, then

\frac{d u}{d v}

View answer and explanation

Correct option: A

\frac{3}{2} x \cdot \cos x^3 \cdot \operatorname{cosec} x^2

Option A is correct because it accurately applies the chain rule to find du/dv, using the given derivatives of f'(x) and g'(x).

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