JEE PHYSICS MCQ: WORK-ENERGY-POWER

Option A ($\mathrm{P}=\mathrm{dK} / \mathrm{dv}$) is incorrect. Option B ($\mathrm{P}=\mathrm{dK} / \mathrm{dt}$) is also incorrect. The correct answer is not among the options provided. However, if we consider the relation between Kinetic Energy (K) and momentum (P), we have $K = \frac{{P^2}}{{2m}}$. Therefore, $P = \sqrt{{2mK}}$. Differentiating K with respect to v, we get $\frac{{dK}}{{dv}} = mv = P$. So, the closest correct answer would be A, but it should be $\frac{{dK}}{{dv}} = P$.