JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

Let

A=\{1,2,3,4\}

and

x, y \in A

, then the value of

\max \left(\sin ^{-1}(\sin x)+\cos ^{-1}(\cos y)\right)

View answer and explanation

Correct option: B

\pi+1

Option D (

(4,2 \sqrt{5})

) is correct because the point lies on the director circle of the given circle, ensuring the tangents drawn from that point are at right angles.

More Questions from INVERSE TRIGONOMETRY

Practice All Chapter MCQs →

\cos ^{-1}(\cos 12)-\sin ^{-1}(\sin 12)

\sin \left(2 \tan ^{-1}(1 / 3)\right)+

\cos \left(\tan ^{-1} 2 \sqrt{2}\right)

\cos ^ {-1}\left\{\frac{1}{\sqrt{2}}\left(\cos \frac{9 \pi}{10}-\sin \frac{9 \pi}{10}\right)\right\}=

\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1

x

{x^2} + {y^2} + {z^2} = {r^2},

{\tan ^{ - 1}}\left( {\frac{{xy}}{{zr}}} \right) + {\tan ^{ - 1}}\left( {\frac{{yz}}{{xr}}} \right) + {\tan ^{ - 1}}\left( {\frac{{xz}}{{yr}}} \right)\;

2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)