JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

Find

\cos ^ {-1}\left\{\frac{1}{\sqrt{2}}\left(\cos \frac{9 \pi}{10}-\sin \frac{9 \pi}{10}\right)\right\}=

View answer and explanation

Correct option: D

\frac{17 \pi}{20}

Option D (

\frac{{17 \pi}}{{20}}

) is correct because it simplifies the given expression using trigonometric identities and inverse cosine properties.

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