JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Hard

1 of 1

Application +4 | -1

\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1

, then

x

is equal to

View answer and explanation

Correct option: D

\frac{1}{5}

Option D (

\frac{1}{5}

) is correct because solving the equation

\sin(\sin^{-1} \frac{1}{5} + \cos^{-1} x) = 1

leads to

x = \frac{1}{5}

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