JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

For

x \in R, f(x)=|\log 2-\sin x|

and

g(x)=f(f(x))

, the

View answer and explanation

Correct option: B

g^{\prime}(0)=\cos (\log 2)

Option B (

g^{\prime}(0)=\cos (\log 2)

) is correct because after analyzing the function

g(x)

near

x=0

and applying the chain rule, the derivative at

x=0

simplifies to

\cos(\log 2)

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x

y

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[x]

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\frac{{dy}}{{dx}}

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