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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If tan⁡−1x−tan⁡−1y=tan⁡−1A,then  A  is  equal  to{\tan ^{ - 1}}x - {\tan ^{ - 1}}y = {\tan ^{ - 1}}A,\mathrm{then\;}A\mathrm{\;is\;equal\;to}
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Correct option: C
x−y1+xy\frac{{x - y}}{{1 + xy}}
Option C (x−y1+xy\frac{{x - y}}{{1 + xy}}) is correct because it directly applies the tangent subtraction formula: tan⁡−1x−tan⁡−1y=tan⁡−1(x−y1+xy){\tan ^{ - 1}}x - {\tan ^{ - 1}}y = {\tan ^{ - 1}}\left( {\frac{{x - y}}{{1 + xy}}} \right).

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