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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If xpyq=(x+y)p+q{x^p}{y^q} = {\left( {x + y} \right)^{p + q}}, then dydx\frac{{dy}}{{dx}} is equal to
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Correct option: A
yx\frac{y}{x}
Option A, yx\frac{y}{x}, is correct because it is the simplified result of differentiating the given equation xpyq=(x+y)p+q{x^p}{y^q} = {\left( {x + y} \right)^{p + q}} implicitly with respect to x.

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