Skip to main content
Back to ELECTRO MAGNETIC INDUCTION

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Medium
1 of 1
Application +4 | -1
A circular ring of diameter 20 cm\mathrm{20}\,\mathrm{cm} has a resistance of 0.01  Ω0.01\,\,\mathrm{\Omega }. The charge that will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of 2.0 T\mathrm{2}.\mathrm{0}\,\mathrm{T} to a position to the field is about
View answer and explanation
Correct option: C
6.3 C\mathrm{6.3}\,\mathrm{C}
Option C (6.3 C\mathrm{6.3}\,\mathrm{C}) is correct because the charge flow is calculated using q=dϕR=BARq = \frac{{d\phi }}{R} = \frac{{BA}}{R}.

More Questions from ELECTRO MAGNETIC INDUCTION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.