A loop of area $0.1\,\,{m^2}$ rotates with a speed of ${\rm{60}}$ rps perpendicular to a magnetic field of ${\rm{0}}{\rm{.4}}\,\,{\rm{T}}$. If there are ${\rm{100}}$ turns in the loop, maximum voltage induced in the loop is

${\rm{15}}{\rm{.07}}\,\,{\rm{V}}$

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A loop of area

0.1\,\,{m^2}

rotates with a speed of

\mathrm{60}

rps perpendicular to a magnetic field of

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

. If there are

\mathrm{100}

turns in the loop, maximum voltage induced in the loop is

View answer and explanation

Correct option: B

\mathrm{1507}\,\,\mathrm{V}

Option B (1507 V) is correct because it is calculated using the formula for the maximum induced voltage in a rotating loop.

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