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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1
A 50  mH\mathrm{50}\,\,\mathrm{mH} coil carries a current of 2A\mathrm{2 A}, the energy stored in joule is
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Correct option: D
0.1
Option D (0.1) is correct because the energy stored in an inductor is calculated using the formula U = (1/2)LI2.

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