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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Let f′(x)=sin⁡(x2)f^{\prime}(x)=\sin \left(x^2\right) and y=f(x2+1)y=f\left(x^2+1\right) then dydx\frac{d y}{d x} at x=1x=1 is :
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Correct option: C
2sin⁡42 \sin 4
Option C (2sin⁡42 \sin 4) is correct because it is the result of applying the chain rule and evaluating the derivative at x=1.

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