JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

z = \tan \left( {y + ax} \right) + \sqrt {y - ax} \Rightarrow {z_{xx}} - {a^2}{z_{yy}}

is equal to

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Correct option: A

Option A (0) is correct because after finding the second-order partial derivatives and substituting them into the expression, the result is zero.

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