If $ y=\sqrt{\frac{1+e^{x}}{1-e^{x}}} $, then $ \frac{d y}{d x} $ is equal to

$ \frac{e^{x}}{\left(1-e^{x}\right) \sqrt{1-e^{x}}} $

$ \frac{e^{x}}{\left(1-e^{x}\right) \sqrt{1+e^{x}}} $

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\sqrt{\frac{1+e^{x}}{1-e^{x}}}

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: A

\frac{e^{x}}{\left(1-e^{x}\right) \sqrt{1-e^{2 x}}}

Option A is correct because the derivative is found using the chain rule and quotient rule, simplifying to the given expression.

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