JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

A function

y=f(x)

satisfies

x \frac{d y}{d x}=\sqrt{y^2+1}, x>0 \& f(2)=0

, then

f(4)=

View answer and explanation

Correct option: B

0.75

Option B (0.75) is correct because solving the differential equation and applying the initial condition f(2)=0 yields f(4)=0.75.

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