JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

The roots of the given equation

\left( {p - q} \right){x^2} + \left( {q - r} \right)x + \left( {r - p} \right) = 0

are

View answer and explanation

Correct option: C

\frac{{r - p}}{{p - q}},1

The correct answer is C (

\frac{{r - p}}{{p - q}},1

) because by inspection, x=1 is a root, and the other root can be found using the relationship between roots and coefficients.

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