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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1
Let for i=1,2,3,pi(x)\mathrm{i}=1,2,3, \mathrm{p}_{\mathrm{i}}(\mathrm{x}) be a polynomial of degree 2 in x,pi′(x)\mathrm{x}, \mathrm{p}_{\mathrm{i}}^{\prime}(\mathrm{x}) and p′′′(x)\mathrm{p}_{\mathrm{\prime \prime}}{ }_{\mathrm{\prime}}(\mathrm{x}) be the first and second order derivatives of pi(x)\mathrm{p}_{\mathrm{i}}(\mathrm{x}) respectively. Let,
A(x)=[p1(x)p1′(x)p1′′(x)p2(x)p2′(x)p2′′(x)p3(x)p3′(x)p3′′(x)]A(x)=\left[\begin{array}{lll} \mathrm{p}_{1}(\mathrm{x}) & \mathrm{p}_{1}^{\prime}(\mathrm{x}) & \mathrm{p}_{1}^{\prime \prime}(\mathrm{x}) \\ \mathrm{p}_{2}(\mathrm{x}) & \mathrm{p}_{2}{ }^{\prime}(\mathrm{x}) & \mathrm{p}_{2}^{\prime \prime}(\mathrm{x}) \\ \mathrm{p}_{3}(\mathrm{x}) & \mathrm{p}_{3}{ }^{\prime}(\mathrm{x}) & \mathrm{p}_{3}{ }^{\prime \prime}(\mathrm{x}) \end{array}\right]

and B(x)=[A(x)]TA(x)\mathrm{B}(\mathrm{x})=[\mathrm{A}(\mathrm{x})]^{T} \mathrm{A}(\mathrm{x}). Then determinant of B(x)\mathrm{B}(\mathrm{x}) :
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Correct option: A
is a polynomial of degree 6 in xx.
Option A is correct. The determinant of B(x) is a polynomial of degree 6 because the elements of B(x) are at most degree 4, and the determinant involves products of these elements.

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