JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

f(x)=\frac{a+\sqrt{a^2-x^2}+x}{\sqrt{a^2-x^2}+a-x}

, where

a>0

and

x < a

, then

f'(0)

has the value equal to

View answer and explanation

Correct option: D

\frac{1}{a}

Option D (

\frac{1}{a}

) is correct because after simplifying the function and finding its derivative, the value of

f'(0)

\frac{1}{a}

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