JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f:\left( { - 1,1} \right) \to R

be a differentiable function with

f\left( 0 \right) = - 1

and

f'\left( 0 \right) = 1.

Let

g(x) = {\left[ {f\left( {2f\left( x \right) + 2} \right)} \right]^2}

. Then,

\mathrm{g'}\left( 0 \right)

is equal to

View answer and explanation

Correct option: A

-4

Option A (-4) is correct because after applying the chain rule and substituting

x=0

, we find that

g'(0) = -4

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