If ${x^y} = {y^x},$ then $x(x - y\log x)\frac{{dy}}{{dx}}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

{x^y} = {y^x},

then

x(x - y\log x)\frac{{dy}}{{dx}}

is equal to

View answer and explanation

Correct option: A

y(y - x\log y)

Option A (

y(y - x\log y)

) is correct because after differentiating the given equation and rearranging, the expression simplifies to the stated result.

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